HDU 5308 I Wanna Become A 24-Point Master】的更多相关文章

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5308 题面: I Wanna Become A 24-Point Master Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 602    Accepted Submission(s): 249 Special Judge Proble…
I Wanna Become A 24-Point Master Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 485    Accepted Submission(s): 191 Special Judge Problem Description Recently Rikka falls in love with an old bu…
I Wanna Become A 24-Point Master Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 60    Accepted Submission(s): 16 Special Judge Problem Description Recently Rikka falls in love with an old but…
I Wanna Become A 24-Point Master Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 897    Accepted Submission(s): 379Special Judge Problem Description Recently Rikka falls in love with an old but…
题目链接:http://acm.hdu.edu.cn/listproblem.php?vol=44 题意:给你n个n,如果能在n-1次运算之后(加减乘除)结果为24的输出n-1次运算的过程,如果不能输出-1. 思路:乍看起来,没什么规律,但是可以想象的是(n+n+n+n)/n=4,(n+n+n+n+n+n)/n=6,(n-n)*n*n*·····*n=0所以在n大于15的时候结果基本是固定的,只要对小于15的数一一输出就行(但是这题真是无语,算这种题目真是累,脑洞啊~~) 代码: #includ…
给出N个数字N,要把全部数字用完.使用+-*/最后变为24.中间运算能够有有浮点数 对于1-14直接打表 15以上的能够通过13个同样数字得到24.然后使后面的数所有运算为0相加就可以 贴一发官方题解 #include "stdio.h" #include "string.h" int now; void pri(int l,int r) { int i; printf("%d - %d\n",l,l+1); now++; for (i=l+2;…
A Sweet Journey Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5477 Description Master Di plans to take his girlfriend for a travel by bike. Their journey, which can be seen as a line segment of length L, is a r…
文章转载自:https://i4t.com/5451.html 背景 Kubernetes 1.24新特性 从kubelet中移除dockershim,自1.20版本被弃用之后,dockershim组件终于在1.24的kubelet中被删除.从1.24开始,大家需要使用其他受到支持的运行时选项(例如containerd或CRI-O):如果您选择Docker Engine作为运行时,则需要使用cri-dockerd. 对于kubelet和containerd重要提示 在升级至1.24之前,请确认c…
斯特灵公式 Wiki http://zh.wikipedia.org/wiki/斯特林公式 /** \brief hdu 1018 * * \param date 2014/7/24 * \param state AC * \return * */ #include <iostream> #include <fstream> #include <cmath> using namespace std; const double PI=3.1415926; int main…
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