题意:给定两个加血的方式,一个是直接加多少,另一种是加百分之几,然后你能够你选 k 种,问你选哪 k 种. 析:首先肯定要选加的多的,所以我们先排序,从大到小,然后用前缀和存储一下,再去枚举从第一种和从第二种选 i 个,从另一个中选 k-i的, 注意这个 k 可能大于 m+n,讨论一下. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <s…

A 水题 /*Huyyt*/ #include<bits/stdc++.h> #define mem(a,b) memset(a,b,sizeof(a)) using namespace std; typedef long long ll; typedef unsigned long long ull; ][] = {{, }, {, }, {, -}, { -, }, {, }, {, -}, { -, -}, { -, }}; , gakki = + + + + 1e9; , MAXM =…

传送门 •题意 二维平面上有 n 条线段,每条线段坐标为 $(l_i,i),(r_i,i)$: 平面上的每个整点坐标上都可以放置一枚硬币,但是要求任意两枚硬币的横坐标不相同: 问最多有多少条线段可以放置硬币. •题解1 考虑到当 $X=x$ 时,最多有一条线段可以放置一枚硬币: 那么,我们可以从左到右查找最多有多少条线段可以放置硬币: 定义变量 $X$ 表示 $[0,X]$ 位置已放置好硬币: 既然是按照 $x$ 来的,那么我们就需要将所有可能可以放置硬币的线段按照 $l$ 升序排列,如果 $l…

A. Nano alarm-clocks Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100637/problem/A Description An old watchmaker has n stopped nano alarm-clocks numbered with integers from 1 to n. Nano alarm-clocks count time in hours, and…

Shopping 题目连接: http://codeforces.com/gym/100803/attachments Description Your friend will enjoy shopping. She will walk through a mall along a straight street, where N individual shops (numbered from 1 to N) are aligned at regular intervals. Each shop…

Hidden Code 题目连接: http://codeforces.com/gym/100015/attachments Description It's time to put your hacking skills to the test! You've been called upon to help crack enemy codes in the current war on... something or another. Anyway, the point is that yo…

A. ArielTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100685/problem/A Description King Triton really likes watching sport competitions on TV. But much more Triton likes watching live competitions. So Triton decides to set up…

G. #TheDress Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100637/problem/G Description After landing on planet i1c5l people noticed that blue and black clothes are quite popular among the locals. Each aboriginal has at least…

A. Nano alarm-clocks Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100637/problem/A Description An old watchmaker has n stopped nano alarm-clocks numbered with integers from 1 to n. Nano alarm-clocks count time in hours, and…

题目链接:http://codeforces.com/gym/101775/problem/B Aori is very careless so she is always making troubles. One day she does it again, with N big troubles! But this time she seems to be at ease because she has found M Inklings to take all the blames. Eac…

Description 对于一个长度为n的非负整数序列b_1,b_2,...,b_n,定义这个序列的能量为:f(b)=max{i=0,1,...,n}((b_1 xor b_2 xor...xor b_i)+(b_{i+1} xor b_{i+2} xor...xor b_n))其中xor表示按位异或(XOR),给定一个长度为n的非负整数序列a_1,a_2,...,a_n,请计算a的每个前缀的能量值. Input 第一行包含一个正整数n(n<=300000),表示序列a的长度. 第二行包含n个非…

http://www.lydsy.com/JudgeOnline/problem.php?id=1028 表示不会贪心QAQ 按顺序枚举,如果能形成刻子那么就形成刻子,否则形成顺子.orz 证明?:因为按顺序枚举,所以当枚举到i,i一定要用完,所以因为>3个顺子和>3个刻子等价,所以考虑<3个顺子.如果i是刻子,假设我们用顺子,那么显然会剩下<=2个,因此不是最优的,所以有刻子就用刻子. 那么暴力枚举添加的,然后暴力枚举哪个是对子,最后暴力判断..n^3.. #include &l…

Description 对于一个长度为n的非负整数序列b_1,b_2,...,b_n,定义这个序列的能量为:f(b)=max{i=0,1,...,n}((b_1 xor b _2 xor...xor b_i)+(b_{i+1} xor b_{i+2} xor...xor b_n))其中xor表示按位异或(XOR),给定一个长度为n的非 负整数序列a_1,a_2,...,a_n,请计算a的每个前缀的能量值. Input 第一行包含一个正整数n(n<=300000),表示序列a的长度. 第二行包含n…

http://codeforces.com/gym/101055/problem/A 题目:给定一些三维空间的点,要你找一个平面,能覆盖尽量多的点,只要求输出点数即可.n<=50 因为数据量小,我们考虑暴力. 首先,三个不在同一条直线的点,确定一个平面,然后枚举其他的点.判断一下,这样的复杂度是n^4.可以接受 特判.所有点都在同一条直线.直接输出n. 后面的,枚举三个点后,能算出这个平面的法向量,然后枚举其他点,与法向量的数量积是0的,就可以ans++ #include <cstdio>…

题意:给一些带颜色的点,求一个最小的矩形,恰好包括一半的红色点,且不包括蓝色点. 题解:暴力,求个二维前缀和,用容斥原理更新一下.N很小所以我采用了离散优化,跑了个0ms. 之前没写过二维前缀和,加上离散写得也不是很熟练,所以搞了2个小时,好在是一发就过了.貌似有个坑,线不要特判,不然wa. #include<cstdio> #include<cmath> #include<vector> #include<map> #include<set>…

原题链接:http://codeforces.com/gym/100203/attachments/download/1702/statements.pdf 题解 考虑暴力的复杂度是O(n^3),所以我们需要记录所有的ai+aj,如果当前考虑到了ak,那么就去前面寻找ai,使得ak-ai是我们记录过的和.整个算法的复杂度O(n^2). 代码 #include<iostream> #include<cstring> #include<cstdio> #include<…

题意:有个长方体由A*B*C组成,每个废料都有一个价值,要选一个子长方体,使得价值最大. 析:我们暴力枚举上下左右边界,然后用前缀和来快速得到另一个,然后就能得到长方体,每次维护一个最小值,然后差就是最大值. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #incl…

Gym - 100338E 题意:给你n,k问在1-n中能整出k的字典序最小的数.范围1018 思路:比较简单的贪心了,枚举10的幂m,然后加上k-m%k, 更新答案就可以了,数据一定要用unsigned long long,我就在这里挂了几次,查了半天. #include <iostream> #include <cstdio> #include <fstream> #include <algorithm> #include <cmath> #…

链接:https://ac.nowcoder.com/acm/contest/886/J来源:牛客网 时间限制:C/C++ 2秒,其他语言4秒 空间限制:C/C++ 262144K,其他语言524288K 64bit IO Format: %lld 题目描述 Rowlet is playing a very popular game in the pokemon world. Recently, he has encountered a problem and wants to ask for…

Identity Checker 题目连接: http://codeforces.com/gym/100015/attachments Description You likely have seen that x(sin x +cos2 x) ! x = 0, and you may have seen that sin(2x) ! 2 sin x cos x =0. But did you know that tan (2x)(x ! x tan2 x) ! 2x tan x = 0? Wo…

题意: 一共有n项服务,每项服务有安装的时间s和截止时间d.对于每项任务,如果有一项超出截止时间,惩罚值为所超出时间的长度.问如何安装才能使惩罚值最大的两个任务的惩罚值之和最小. 分析: 如果是求总惩罚值的最小值,则按所有任务的截止时间排序,这样贪心的理由是,先完成截止时间早的任务至少不会是情况变得更坏. 虽然题目所求不是这个,但我们可以稍作修改. 设p为按上述贪心顺序安装任务,惩罚值最大的两个任务中靠后的那个位置. 枚举p之前的任务i,将第i个任务移到p后面执行,有可能减小两个最大惩罚值之和,…

D. Data Center Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/560/problem/B Description The startup "Booble" has shown explosive growth and now it needs a new data center with the capacity of m petabytes. Booble can b…

题目链接:http://codeforces.com/gym/101848/problem/B 给出一串数字要你最多改动三个数字使这一串数字成为等差数列.因为最多改动三个数字所以可以先求出相邻两项的差值再进行修改,判断是否符合,最多循环四遍即可. #include<iostream> using namespace std; int main() { ],b[]; cin>>n; ;i<n;i++) cin>>a[i]; ) { ;i<n;i++) b[i]…

B. Nanami's Digital Board 题目连接: http://www.codeforces.com/contest/434/problem/B Description Nanami is an expert at playing games. This day, Nanami's good friend Hajime invited her to watch a game of baseball. Unwilling as she was, she followed him to…

题意:有个邮递员,要送信,每次最多带 m 封信,有 n 个地方要去送,每个地方有x 封要送,每次都到信全送完了,再回去,对于每个地方,可以送多次直到送够 x 封为止. 析:一个很简单的贪心,就是先送最远的,如果送完最远的还剩下,那么就送次远的,如果不够了,那么就加上回来的距离,重新带够 m 封信,对于左半轴和右半轴都是独立的,两次计算就好. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include &l…

After the data structures exam, students lined up in the cafeteria to have a drink and chat about how much they have enjoyed the exam and how good their professors are. Since it was late in the evening, the cashier has already closed the cash registe…

Gym Class Time Limit: 6000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 768    Accepted Submission(s): 309 Problem Description 众所周知,度度熊喜欢各类体育活动. 今天,它终于当上了梦寐以求的体育课老师.第一次课上,它发现一个有趣的事情.在上课之前,所有同学要排成一列, 假设最开始每个人有…

Description     A new Semester is coming and students are troubling for selecting courses. Students select their course on the web course system. There are n courses, the ith course is available during the time interval (Ai,Bi). That means, if you wa…

[Lydsy1711月赛]分割序列 Time Limit: 5 Sec  Memory Limit: 256 MBSubmit: 213  Solved: 97[Submit][Status][Discuss] Description 对于一个长度为n的非负整数序列b_1,b_2,...,b_n,定义这个序列的能量为:f(b)=max{i=0,1,...,n}((b_1 xor b _2 xor...xor b_i)+(b_{i+1} xor b_{i+2} xor...xor b_n))其中x…

1044: [HAOI2008]木棍分割 Time Limit: 10 Sec  Memory Limit: 162 MB Submit: 4112  Solved: 1577 [Submit][Status][Discuss] Description 有n根木棍, 第i根木棍的长度为Li,n根木棍依次连结了一起, 总共有n-1个连接处. 现在允许你最多砍断m个连 接处, 砍完后n根木棍被分成了很多段,要求满足总长度最大的一段长度最小, 并且输出有多少种砍的方法使得总长 度最大的一段长度最小.…