ZOJ 2969 Easy Task】的更多相关文章

E - Easy Task Description Calculating the derivation of a polynomial is an easy task. Given a function f(x) , we use (f(x))' to denote its derivation. We use x^n to denote xn. To calculate the derivation of a polynomial, you should know 3 rules:(1) (…
A. Appleman and Easy Task time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you…
An Easy Task Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 1   Accepted Submission(s) : 1 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Ignatius was born in a lea…
An Easy Task Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4088 Accepted Submission(s): 2327   Problem Description Ignatius was born in a leap year, so he want to know when he could hold his bir…
B. An Easy Task Time Limit: 1000ms Case Time Limit: 1000ms Memory Limit: 65536KB 64-bit integer IO format: %lld      Java class name: Main Submit Status PID: 35999 Font Size:  +   - You are given an easy task by your supervisor -- to find the best va…
An Easy Task Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 17062    Accepted Submission(s): 10902 Problem Description Ignatius was born in a leap year, so he want to know when he could hold h…
A. Appleman and Easy Task time limit per test  1 second memory limit per test  256 megabytes input  standard input output  standard output Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can…
A. Appleman and Easy Task time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you…
题意 每次把序列中最大的数a的一个和最小的数b的一个变成a-b.求最后是否能使序列里的数全部相同,能则输出这个相同的数. 分析 一定是有解的,不断减少最大数的个数,最大数减少为0个时,就是减少了不同数字的个数,最后就只剩一种数字了. 可以直接暴力模拟. 代码 #include<cstdio> int ok(int a[],int n) { int i; for(i=1; i<n; i++) if(a[i]!=a[i+1])break; return i==n; } int main()…
Problem Description Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him? Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap y…