传送门 分析 我们设S[i]表示到第i个数为止一共有多少个数在集合Z之中,最终答案就是S[max]-S[min]的最小值.所以我们不难发现对于每一个[ai,bi]都表示S[bi]-S[ai-1]>=ci,而我们又知道0<=S[i]-S[i-1]<=1,所以建图策略便是每一个ai向bi连一条权值为ci的边,i-1向i连一条权值为0的边,i向i-1连一条权值为-1的边,然后跑最长路就可以了.注意在代码中为了方便起见所有的值i向后移了一位. 代码 #include<iostream>…

Given a collection of intervals, find the minimum number of intervals you need to remove to make the rest of the intervals non-overlapping. Note: You may assume the interval's end point is always bigger than its start point. Intervals like [1,2] and…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 这道和之前那道Insert Interval 插入区间 很类似,这次题目要求我们合并区间,之前那题明确了输入区间集是有序的,而这题没有,所有我们首先要做的就是给区间集排序,由于我们要排序的是个结构体,所以我们要定义自…

Intervals Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 26028   Accepted: 9952 Description You are given n closed, integer intervals [ai, bi] and n integers c1, ..., cn. Write a program that: reads the number of intervals, their end po…

Source: Sigma Zone, by Philip Mayfield The Binomial Distribution is commonly used in statistics in a variety of applications. Binomial data and statistics are presented to us daily. For example, in the election of political officials we may be asked…

Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 题目的意思是将相交得区间合并,典型的贪心算法 首先将区间先按照start进行排序, 然后保存先前区间的start和end 如果当前的start > 先前的end,说明当前的区间与之前的区间不想交,则将先前的区间放入结果中…

感觉有一点进步了,但是思路还是不够犀利. /** * Definition for an interval. * struct Interval { * int start; * int end; * Interval() : start(0), end(0) {} * Interval(int s, int e) : start(s), end(e) {} * }; */ class Solution { public: vector<Interval> merge(vector<In…

class Solution { public: static bool cmp(Interval &a,Interval &b) { return a.start<b.start; } vector<Interval> merge(vector<Interval>& intervals) { vector<Interval> res; )return res; sort(intervals.begin(),intervals.end(),…

Given a collection of intervals, find the minimum number of intervals you need to remove to make the rest of the intervals non-overlapping. Note: You may assume the interval's end point is always bigger than its start point. Intervals like [1,2] and…

Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18].     先排序,然后循环合并   /** * Definition for an interval. * struct Interval { * int start; * int end;…

Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 思路:开始想用线段树,后来想想这个不是动态变化的没必要. 按区间的第一个值从小到大排序,然后跳过后面被覆盖的区间来找. sort折腾了好久,开始搞不定只好自己写了一个归并排序.现在代码里的sort是可用的. class…

Description You are given n closed, integer intervals [ai, bi] and n integers c1, ..., cn. Write a program that: reads the number of intervals, their end points and integers c1, ..., cn from the standard input, computes the minimal size of a set Z of…

1346. Intervals of Monotonicity Time limit: 1.0 secondMemory limit: 64 MB It’s well known that a domain of any continuous function may be divided into intervals where the function would increase monotonically or decrease monotonically. A number of in…

题目要求: Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 解题思路: 1)将集合进行排序: 集合的排序建议使用Collections的sort方法实现,需要自己实现Comparator接口: 2)依次进行归并,当后者的start大于当前Interval的end时,将…

Given a collection of intervals, find the minimum number of intervals you need to remove to make the rest of the intervals non-overlapping. Note: You may assume the interval's end point is always bigger than its start point. Intervals like [1,2] and…

Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 区间合并,分为三种情况 /** * Definition for an interval. * struct Interval { * int start; * int end; * Interval() : start…

Insert Interval Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], i…

Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 解题思路: 1.将区间按照起始位置从小到大排序: 2.一次遍历,如果发现当前区间起始小于上一个区间结束,则进行合并: 解题步骤: 1.因为需要比较结构体,所以编写比较函数< 2.新建一个结果数组,保存合并后的结果: 3.…

Description There is given the series of n closed intervals [ai; bi], where i=1,2,...,n. The sum of those intervals may be represented as a sum of closed pairwise non−intersecting intervals. The task is to find such representation with the minimal nu…

Description You are given n closed, integer intervals [ai, bi] and n integers c1, ..., cn. Write a program that: reads the number of intervals, their end points and integers c1, ..., cn from the standard input, computes the minimal size of a set Z of…

Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 解题思路一: 用两个指针startIndex和endIndex来维护每次添加intervals的start和end的位置,然后分类讨论即可,JAVA实现如下: public List<Interval> merge…

题目来源 https://leetcode.com/problems/merge-intervals/ Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 题意分析 Input:a list of intervals Output:a list of intervals…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

网络流/费用流 引用下题解: lyd: 首先把区间端点离散化,设原来的数值i离散化后的标号是c[i].这样离散化之后,整个数轴被分成了一段段小区间. 1.建立S和T,从S到离散化后的第一个点连容量K,费用0的边.离散化后的最后一个点到T连容量K.费用0的边. 2.离散化后的相邻点之间(从i到i+1)连容量为K,费用为0的边. 3.输入的区间从离散化后的左端点到右端点连容量1.费用W的边. 感觉好神啊…… 其实应该只要把源点到第一个点的流量限制为k应该就可以了……这个构思蛮巧妙的……限制了每个地方…

原题地址 排序+合并,没啥好说的 第一次尝试C++的lambda表达式,有种写js的感觉,很神奇 c11就支持了lambda表达式,仔细想想,我学C++大概就是在09~10年,c11还没有发布,不得不说C++跟当时已经大不一样了. 代码: vector<Interval> merge(vector<Interval> &intervals) { vector<Interval> result; sort(intervals.begin(), intervals.…

题意 在区间[0,50000]上有一些整点,并且满足n个约束条件:在区间[ui, vi]上至少有ci个整点,问区间[0, 50000]上至少要有几个整点. 思路 差分约束求最小值.把不等式都转换为>=形式,那么显然有xvi >= xui-1 + ci,那么就在约束图中连一条(ui-1, vi, ci)的边:当然不要忘记隐含的不等式:xi >= xi-1 + 0;   xi-1 >= xi -1. 建完图后SPFA求最长路径即可 代码 [cpp] #include <iostr…

Intervals 题目连接: http://codeforces.com/gym/100231/attachments Description Start with an integer, N0, which is greater than 0. Let N1 be the number of ones in the binary representation of N0. So, if N0 = 27, N1 = 4. For all i > 0, let Ni be the number…