1069 The Black Hole of Numbers (20 分)   For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the seco…

1069 The Black Hole of Numbers(20 分) For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second…

题目信息 1069. The Black Hole of Numbers (20) 时间限制100 ms 内存限制65536 kB 代码长度限制16000 B For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new n…

1069 The Black Hole of Numbers(20 分) For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second…

1069 The Black Hole of Numbers (20 分)   For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the seco…

1069 The Black Hole of Numbers (20分) 1. 题目 2. 思路 把输入的数字作为字符串,调用排序算法,求最大最小 3. 注意点 输入的数字的范围是(0, 104), 如果作为字符串处理时要注意前面补0 4. 代码 #include<cstdio> #include<cstring> #include<algorithm> using namespace std; bool cmp(char a, char b){ return a>…

For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat in…

For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat in…

For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat in…

For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat in…

题目 For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in nonincreasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat i…

简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<algorithm> using namespace std; int n; ]; int num1,num2;…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6789244.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 按照题目的意思纯模拟一遍就行了 #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> using namespace…

题意: 输入一个四位的正整数N,输出每位数字降序排序后的四位数字减去升序排序后的四位数字等于的四位数字,如果数字全部相同或者结果为6174(黑洞循环数字)则停止. trick: 这道题一反常态的输入的数字是一个int类型而不是包含前导零往常采用字符串的形式输入,所以在测试点2,3,4如果用字符串输入会超时..... AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace st…

1069. The Black Hole of Numbers (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-…

Source: PAT A1069 The Black Hole of Numbers (20 分) Description: For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obt…

For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat in…

For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat in…

For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat in…

//这是到水题,之前因为四位数的原因一直不能A,看了别人的程序,才明白,不够四位的时候没考虑到,坑啊.....脸打肿 #include<cstdio>#include<algorithm>using namespace std;int main(){ //freopen("input.txt","r",stdin); int i,n,s[5]; while(scanf("%d",&n)!=EOF) { while(…

pat 1069 The Black Hole of Numbers 水题,代码如下: #include<cstdio> #include<cstdlib> #include<cstring> #include<algorithm> using namespace std; bool isSame(char buf[]) { ; while(buf[i] != '\0') { ])return false; else i++; } return true;…

2019/4/3 1063 Set Similarity n个序列分别先放进集合里去重.在询问的时候,遍历A集合中每个数,判断下该数在B集合中是否存在,统计存在个数(分子),分母就是两个集合大小减去分子. // 1063 Set Similarity #include <set> #include <map> #include <cstdio> #include <iostream> #include <algorithm> using name…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了…

树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…

本文为PAT甲级分类汇编系列文章. 计算类,指以数学运算为主或为背景的题. 题号 标题 分数 大意 1058 A+B in Hogwarts 20 特殊进制加法 1059 Prime Factors 25 分解素因数 1060 Are They Equal 25 一定精度下两数是否相等 1065 A+B and C (64bit) 20 大数加法与比较 1069 The Black Hole of Numbers 20 黑洞数 1073 Scientific Notation 20 科学计数法还…

今天开个坑,分类整理PAT甲级题目(https://pintia.cn/problem-sets/994805342720868352/problems/type/7)中1051~1100部分.语言是modern C++. 为什么要整理呢,因为我2019年9月要考PAT甲级,虽然是第一次考,虽然只学了数据结构(https://mooc.study.163.com/course/1000033001?tid=2402970002#/info),但我要冲着高分(2019年9月8日更新:满分)去. 下…

1.简单数学 1008 Elevator (20分) 模拟题 #include <cstdio> #include <cstring> #include <string> #include <algorithm> #include <iostream> #include <map> #include <cmath> #define ll long long #define inf 0x3f3f3f using namesp…

1069. Prufer Code Time limit: 0.25 secondMemory limit: 8 MB A tree (i.e. a connected graph without cycles) with vertices is given (N ≥ 2). Vertices of the tree are numbered by the integers 1,…,N. A Prufer code for the tree is built as follows: a leaf…

https://www.ted.com/talks/katie_bouman_what_does_a_black_hole_look_like/transcript 00:13In the movie "Interstellar[ˌɪntərˈstelə(r)]星际的," we get an up-close look at a supermassive black hole. Set against a backdrop of bright gas, the black hole's…

Description Yehan is a angry grumpy rabbit, who likes jumping into the hole. This day,Yehan jumps again in the pit at home. Each time, he should jump from the hole at the coordinate (1,1) to (n,m), and he has to jump as the way : he can only jump (x,…