Suppose n<=32, we can enumerate C(k, n), with bits representing absence or presence, in the following way: #include <iostream> #include <vector> #include <bitset> using namespace std; bitset<32> getComb(const vector<int> &…
Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers. Ensure that numbers within the set are sorted in ascending order. Example 1…
/** 题目:D - No Need 链接:http://arc070.contest.atcoder.jp/tasks/arc070_b 题意:给出N个数,从中选出一个子集,若子集和大于等于K,则这是一个Good子集,现在要求这N个数里无用数的个数. 无用数的定义是:在这个数所属的所有Good子集中,如果把这个数删去后原子集仍然是一个Good子集,它就是一个无用数 思路:关键点是存在单调性,如果某个数是必须的,那么比他大的数都是必须的: 证明如下:假设x是必须的,y是比x大的某个数:x是必须的…
其中的一篇是这样的:一般情况下,如果要对一个列表或者数组既要遍历索引又要遍历元素时,可以用enumerate 比如: for index,value in enumerate(list): print index,value 当然也可以 for i in range(0,len(list)): print i,list[i] >>> a =[1,2,3,4] >>> for k,v in enumerate(a): ... print k ...…
题意 给一个n个结点的带点权的图,找到第k小的团的权值 分析 用bitset表示团的状态,一个结点必须和团里的每个结点都连边才能加进去,所以可以直接用\(\&\)运算来判断一个结点是否能加进去后还形成团,用优先队列来维护前k小的团的权值. Code #include<bits/stdc++.h> #define fi first #define se second #define pb push_back #define ll long long using namespace std…
Sasha and Kolya decided to get drunk with Coke, again. This time they have k types of Coke. i-th type is characterised by its carbon dioxide concentration . Today, on the party in honour of Sergiy of Vancouver they decided to prepare a glass of Coke…