负载是否平衡只与前两列有关,剩下的只要与前两列不重复就随便放. 第一列我们按1-n这样循环放,第二列每次找个数最少的那个服务器放. #include <cstdio> #include <cstring> #include <cstdlib> using namespace std; ; int N, M; int mat[MAXN][MAXN]; int cnt[MAXN]; int ori[MAXN]; bool vis[MAXN]; void show() { ;…

Backup Plan Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 93    Accepted Submission(s): 36Special Judge Problem Description Makomuno has N servers and M databases. All databases are synchroniz…

错成那样,还以为是卡时间卡精度的变态题,结果就那么ac了= = 悔死我了 题意就不概述了,只要处理前两列即可.其中第一列顺序直接扫一遍,第二列要先处理较少的那几种.我是接着第一列用 head[] 继续处理,朋友给出了直接逆向处理的算法,更快.代码也会好写一点. #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ; int st[MAXN],ed[MAXN],head[M…

link:http://acm.hdu.edu.cn/showproblem.php?pid=4671 其实是不难的那种构造题,先排第一列,第二列从后往前选. #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <cctype> #include <algorithm> #…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4671 假设是3 m,首先按照第一列按照1 2 3 1 2 3 1...排下去,然后个数就是一个 (m/3)+1,(m/3)+1....m/3的形式,题目要求不相差1,那么对于第二列serve直接从后往前就可以了,总可以保证不想差1,最多两列就可以解决.. //STATUS:C++_AC_31MS_272KB #include <functional> #include <algorithm&…

You will need to identify how you want your maintenance plan to be setup. In this example the maintenance plan will be setup with full backups, differentials, and transactions logs. Check SQL Server Agent Service Verify the SQL Server Agent service i…

Binary Tree 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5573 Description The Old Frog King lives on the root of an infinite tree. According to the law, each node should connect to exactly two nodes on the next level, forming a full binary tree. S…

http://acm.hdu.edu.cn/showproblem.php?pid=5015 由于是个二维的递推式,当时没有想到能够这样构造矩阵.从列上看,当前这一列都是由前一列递推得到.依据这一点来构造矩阵.令b[i]代表第i列,是一个(n+2)*1的矩阵,即b[1] = [1,233......],之所以在加了两行,是要从前一个矩阵b[i-1]得到b[i]中的第二个数2333...,再构造一个转换矩阵a,它是一个(n+2)*(n+2)的矩阵,那么a^(m-1) * b就是第m列. /* a矩…

Elegant Construction 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5813 Description Being an ACMer requires knowledge in many fields, because problems in this contest may use physics, biology, and even musicology as background. And now in this prob…

The plan of city rebuild Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 616    Accepted Submission(s): 215 Problem Description News comes!~City W will be rebuilt with the expectation to become…