Thanks a lot for helping Harry Potter in finding the Sorcerer's Stone of Immortality in October. Did we not tell you that it was just an online game ? uhhh! now here is the real onsite task for Harry. You are given a magrid S ( a magic grid ) having…

Magic Grid Time Limit:336MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Description Thanks a lot for helping Harry Potter in finding the Sorcerer's Stone of Immortality in October. Did we not tell you that it was just an online game ? uhhh!…

C. Magic Grid time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Let us define a magic grid to be a square matrix of integers of size n×nn×n, satisfying the following conditions. All integers…

在MagicCombo组件中嵌入Grid,以支持分页查找和跨页选取 ​ 1. ​2. [代码][JavaScript]单选示例代码     <script type="text/javascript" src="/js/mac/pager.js"></script><script type="text/javascript" src="/js/mac/grid.js"></script…

题目 大意:构造一个n行n列的矩阵,使得每一行,每一列的异或和都相等,n是4的倍数. 先看4*4的矩阵,我们很容易构造出符合要求的矩阵,比如 0    1    2    3 4    5    6    7 8    9   10  11 12 13  14  15 这个矩阵每行每列的异或和都为0 对于一个n*n的矩阵,我们可以写成多个4*4的矩阵,为了保证数字不重复,可以对于其他的小矩阵都加上16,32等等 #include<iostream> #include<cstdio>…

题目大意 给你一个n 让你用0~n^2-1的数填满一个n*n的正方形 满足每个数值出现一次且每行每列的异或值相等 输出任意一种方案 分析 我们发现对于4*4的正方形 0  1  2  3 4  5  6  7 8  9 10 11 12 13 14 15 是满足条件的 那么如果对正方形中的每一个数都加上一个相同的数 那么这个正方形一定还是满足的 由于这种构造方式的异或值均是0 所以任意多个满足的正方形拼起来一定也是满足的 于是我们将正方形分为若干4*4的正方形 使得每一个正方形是一组连续的数 那…

B. Chris and Magic Square 题目连接: http://www.codeforces.com/contest/711/problem/B Description ZS the Coder and Chris the Baboon arrived at the entrance of Udayland. There is a n × n magic grid on the entrance which is filled with integers. Chris notice…

ZS the Coder and Chris the Baboon arrived at the entrance of Udayland. There is a n × n magic grid on the entrance which is filled with integers. Chris noticed that exactly one of the cells in the grid is empty, and to enter Udayland, they need to fi…

Thanks a lot for helping Harry Potter in finding the Sorcerer's Stone of Immortality in October. Did we not tell you that it was just an online game ? uhhh! now here is the real onsite task for Harry. You are given a magrid S ( a magic grid ) having…

time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output   ZS the Coder and Chris the Baboon arrived at the entrance of Udayland. There is a n × n magic grid on the entrance which is filled with in…

Chris and Magic Square 题目链接: http://codeforces.com/contest/711/problem/B Description ZS the Coder and Chris the Baboon arrived at the entrance of Udayland. There is a n × n magic grid on the entrance which is filled with integers. Chris noticed that…

A. Bus to Udayland time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output ZS the Coder and Chris the Baboon are travelling to Udayland! To get there, they have to get on the special IOI bus. The…

A ZS the Coder and Chris the Baboon are travelling to Udayland! To get there, they have to get on the special IOI bus. The IOI bus has nrows of seats. There are 4 seats in each row, and the seats are separated into pairs by a walkway. When ZS and Chr…

A Thanks a lot for helping Harry Potter in finding the Sorcerer's Stone of Immortality in October. Did we not tell you that it was just an online game ? uhhh! now here is the real onsite task for Harry. You are given a magrid S ( a magic grid ) havin…

目录 \(\bf {Round \ \#500 \ (Div. \ 1)}\) \(\bf {Round \ \#589 \ (Div. \ 2)}\) \(\bf {Avito \ Cool \ Challenge \ 2018}\) \(\bf {Round \ \#545 \ (Div. \ 1)}\) \(\bf {Round \ \#454 \ (Div. \ 1)}\) \(\bf {Round \ \#575 \ (Div. \ 3)}\) \(\bf Codefest \ 19\…

这套题还是有点质量的吧 -- 题目链接 A. XORinacci 傻叉签到题,因为异或的性质所以这个序列的循环节长度只有 \(3\) -- 查看代码 B. Uniqueness 因为序列长度乃至数的种类都不超过 \(2000\),考虑先把序列离散化. 题意让我们求一个最短的区间满足如下性质,对于每一种数,其在此区间出现次数不小于在原序列中的出现次数减 \(1\). 可以先前缀和求一下对于每种数,当前位置及之前的出现次数,和至少一共需要删掉多少个这种数,即在原序列中的出现次数减 \(1\),方便以…

目录 Contest Info Solutions A. XORinacci B. Uniqueness C. Magic Grid D. Restore Permutation E. Let Them Slide F. Bits And Pieces Contest Info Practice Link Solved A B C D E F G H 6/8 O O Ø O O Ø - - O 在比赛中通过 Ø 赛后通过 ! 尝试了但是失败了 - 没有尝试 Solutions A. XORina…

蒟蒻的心路历程 上来看B,结果不会... 回来做A,写完之后nantf已经切B了. 回来做B,花了13min磕了出来. 继续做C,自闭. 继续做D,花了10min磕了出来. 继续做E,一开始有点自闭,后来口胡了出来,但是实现略微死人,花了1h磕了出来. 继续自闭....... A XORinacci \(a,b,a\oplus b,a,b,a\oplus b,\ldots\) B Uniqueless 使用two-pointer, 前缀和优化后判断\(O(n)\),时间复杂度\(O(n^2)\)…

传送门 A. XORinacci 手玩三四项发现序列就是 $a,b,a\ xor\ b,a,b,...$,直接输出即可 #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #include<cmath> using namespace std; typedef long long ll; inline int read() { ,f=; char ch…

Codefest 19 (open for everyone, rated, Div. 1 + Div. 2) C. Magic Grid 这种题直接构造 数n是2的n次方的倍数的时候可以这样划分数 比如n是4的倍数  n=k*4 000        001         010         011 100        101         110         111 (k-1)00   (k-1)01   (k-1)10   (k-1)11 然后填格子 Codeforces R…

传送门 A. XORinacci 签到. Code /* * Author: heyuhhh * Created Time: 2020/2/26 9:26:33 */ #include <iostream> #include <algorithm> #include <cstring> #include <vector> #include <cmath> #include <set> #include <map> #inc…

A 3 x 3 magic square is a 3 x 3 grid filled with distinct numbers from 1 to 9 such that each row, column, and both diagonals all have the same sum. Given an grid of integers, how many 3 x 3 "magic square" subgrids are there?  (Each subgrid is co…

A 3 x 3 magic square is a 3 x 3 grid filled with distinct numbers from 1 to 9 such that each row, column, and both diagonals all have the same sum. Given an grid of integers, how many 3 x 3 "magic square" subgrids are there?  (Each subgrid is co…

开头 这是每周比赛中的第一道题,博主试了好几次坑后才勉强做对了,第二道题写的差不多结果去试时结果比赛已经已经结束了(尴尬),所以今天只记录第一道题吧 题目原文 Magic Squares In Grid A 3 x 3 magic square is a 3 x 3 grid filled with distinct numbers from 1 to 9 such that each row, column, and both diagonals all have the same sum.…

problem 840. Magic Squares In Grid solution: class Solution { public: int numMagicSquaresInside(vector<vector<int>>& grid) { ].size(); ; ; i<m-; ++i) { ; j<n-; ++j) { if(isvalid(grid, i, j)) cnt++; } } return cnt; } bool isvalid(vect…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3752 访问. 3 x 3 的幻方是一个填充有从 1 到 9 的不同数字的 3 x 3 矩阵,其中每行,每列以及两条对角线上的各数之和都相等. 给定一个由整数组成的 m * n 矩阵,其中有多少个 3 × 3 的 "幻方" 子矩阵?(每个子矩阵都是连续的). 输入: [[4,3,8,4],       [9,5,1,9],       [2,7,6,2]…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 利用河图规律 暴力解法 日期 题目地址:https://leetcode.com/problems/magic-squares-in-grid/description/ 题目描述 A 3 x 3 magic square is a 3 x 3 grid filled with distinct numbers from 1 to 9 such tha…

class Solution { public: int numMagicSquaresInside(vector<vector<int>>& grid) { ; int szx=grid.size(); ].size(); ;i<szx-;i++) { ;j<szy-;j++) { ][j+]==&&judge(grid,i,j)) count++; } } return count; } bool judge(vector<vector…

这是悦乐书的第326次更新,第349篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第196题(顺位题号是840).3 x 3魔方是一个3 x 3网格,填充了从1到9的不同数字,这样每行,每列和两个对角线都具有相同的总和. 给定一个整数网格,求有多少个3 x 3"魔方"子网格? (每个子网格都是连续的).例如: 输入:[[4,3,8,4],[9,5,1,9],[2,7,6,2]] 输出:1 说明: 以下子网格是一个3 x 3魔方: 4 3 8 9 5 1 2…

3 x 3 的幻方是一个填充有从 1 到 9 的不同数字的 3 x 3 矩阵,其中每行,每列以及两条对角线上的各数之和都相等. 给定一个由整数组成的 N × N 矩阵,其中有多少个 3 × 3 的 "幻方" 子矩阵?(每个子矩阵都是连续的). 示例 1: 输入: [[4,3,8,4], [9,5,1,9], [2,7,6,2]] 输出: 1 解释: 下面的子矩阵是一个 3 x 3 的幻方: 438 951 276 而这一个不是: 384 519 762 总的来说,在本示例所给定的矩阵中…