557. Reverse Words in a String III 最简单的把空白之间的词反转 class Solution { public: string reverseWords(string s) { vector<int> blank; ;i < s.size();i++){ if(s[i] == ' ') blank.push_back(i); } ; int end; ;i < blank.size();i++){ end = blank[i] - ; revers…
Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. Clarification: What constitutes a…
Reverse Words in a String Given an input string, reverse the string word by word. Example 1: Input: "the sky is blue" Output: "blue is sky the" Example 2: Input: " hello world! " Output: "world! hello" Explanation:…
题目:reverse words in a string Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". 解析:将字符串中的单词逆序输出 借助一个堆栈,从前向后遍历字符串,遇到空,跳过,直到非空字符,拼接word,等再次遇到空时,得到一个word,加入堆栈, 以此类推,直到…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/reverse-words-in-a-string/description/ 题目描述 Given an input string, reverse the string word by word. Example 1: Input: "the sky is blue"…
Difficulty: Medium  More:[目录]LeetCode Java实现 Description Given an input string, reverse the string word by word. Example: Input: "the sky is blue", Output: "blue is sky the". Note: A word is defined as a sequence of non-space character…
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 解题思路: 本题方法多多,最简单的方式直接按“ ” spilt即可,JAVA实现如下: public String reverseWords(String s) { if (s == null || s.length()…
Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. 倒序字符串. 注意使用BufferString,因为如果使用Stri…
Given an input string, reverse the string word by word. Example: Input: "the sky is blue",Output: "blue is sky the".Note: A word is defined as a sequence of non-space characters.Input string may contain leading or trailing spaces. Howe…
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". Update (2015-02-12): For C programmers: Try to solve it in-place in O(1) space. 这题遇到的困难主要是细节地方处理的不好:(1)空格的处理,(2…
原题地址 将单词按空格分词,然后倒序拼接即可 代码: void reverseWords(string &s) { vector<string> words; ; ; ; i < s.length(); i++) { if (s[i] == ' ') { ) words.push_back(s.substr(start, len)); len = ; } else { ) { start = i; len = ; } else len++; } } ) words.push_ba…
给定一个字符串,翻转字符串中的每个单词.例如,给定 s = "the sky is blue",返回 "blue is sky the".对于C程序员:请尝试用O(1) 时间复杂度的原地解法.说明:    什么构成一个词?    一系列非空格字符组成一个词.    输入字符串是否可以包含前导或尾随空格?    是.但是,您的反转字符串不应包含前导或尾随空格.    两个单词之间多空格怎么样?    将它们缩小到反转字符串中的单个空格.详见:https://leetc…
Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". public class Solution { public String reverseWords(String s) { String afterTrim= s.trim(); String[] split=afterTr…
Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. click to show clarification. Clari…
[抄题]: Given an input string, reverse the string word by word. Example: Input: "the sky is blue", Output: "blue is sky the". [暴力解法]: 时间分析: 空间分析: [优化后]: 时间分析: 空间分析: [奇葩输出条件]: [奇葩corner case]: [思维问题]: 打碎成数组后再添加,居然有看不懂的bug. public class So…
思路: 本题考查的目的并不是使用字符串的函数.方法是两次reverse,先对每个单词先做一次翻转,然后对整个字符串做一次翻转. 需要注意的是去除extra space,并且对全space字符串.以及最后一个单词要做特殊处理. class Solution { public: void reverseWords(string &s) { ; ; ; ; // point to the string with extra space deleted //ignore space at the beg…
题目 Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". click to show clarification. Clarification: What constitutes a word? A sequence of non-space characters cons…
Given an input string, reverse the string word by word. Example 1: Input: "the sky is blue" Output: "blue is sky the" Example 2: Input: "  hello world!  " Output: "world! hello" Explanation: Your reversed string sho…
1.题目描述 2.题目分析 找到字符串中的空格即可 3.代码 int countSegments(string s) { ){ ; } vector<string> v; ; i < s.size(); i++){ if( isspace(s[i]) ){ continue; } ; while( !isspace(s[j]) ){ if( j < s.size() ) j++; else break; } string sb = s.substr(i,j-i); v.push_b…
1.题目描述 2.分析 使用一个map将字母和数字对应起来,方便后续使用. 3.代码 vector<int> numberOfLines(vector<int>& widths, string S) { map<char,int> m; vector<int> ans; ; i< ;i++) m[i+'a'] = widths[i]; ; ; ; ; t < S.size(); t++) { curLen += m[ S[t] ]; la…
151. 翻转字符串里的单词 151. Reverse Words in a String…
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters.The input string does not contain leading or trailing spaces and the words are always separated by a single space.For example,Given s = "t…
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc"…
[抄题]: Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc&…
题目来源 https://leetcode.com/problems/reverse-linked-list-ii/ Reverse a linked list from position m to n. Do it in-place and in one-pass. For example:Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note:G…
导航页-LeetCode专题-Python实现 相关代码已经上传到github:https://github.com/exploitht/leetcode-python 文中代码为了不动官网提供的初始几行代码内容,有一些不规范的地方,比如函数名大小写问题等等:更合理的代码实现参考我的github repo 1.读题 Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321…
前言   [LeetCode 题解]系列传送门:  http://www.cnblogs.com/double-win/category/573499.html   1.题目描述 Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out no…
[LeetCode]150. Evaluate Reverse Polish Notation 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/evaluate-reverse-polish-notation/description/ 题目描述: Evaluate the value of an arithmetic expression in Reverse Polish Notation. Valid operator…
题目来源 https://leetcode.com/problems/substring-with-concatenation-of-all-words/ You are given a string, s, and a list of words, words, that are all of the same length. Find all starting indices of substring(s) in s that is a concatenation of each word…
目录 描述 解法一:迭代 思路 Java 实现 Python 实现 复杂度分析 解法二:递归(不满足空间复杂度) 思路 Java 实现 Python 实现 复杂度分析 更多 LeetCode 题解笔记可以访问我的 github. 描述 给出一个链表,每 k 个节点一组进行翻转,并返回翻转后的链表. k 是一个正整数,它的值小于或等于链表的长度.如果节点总数不是 k 的整数倍,那么将最后剩余节点保持原有顺序. 示例 : 给定这个链表:1->2->3->4->5 当 k = 2 时,应…