674. 最长连续递增序列 674. Longest Continuous Increasing Subsequence 题目描述 给定一个未经排序的整型数组,找到最长且连续的递增序列. Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray). 每日一算法2019/5/21Day 18LeetCode674. Longest Conti…
Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray). Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though…
674. 最长连续递增序列 给定一个未经排序的整数数组,找到最长且连续的的递增序列. 示例 1: 输入: [1,3,5,4,7] 输出: 3 解释: 最长连续递增序列是 [1,3,5], 长度为3. 尽管 [1,3,5,7] 也是升序的子序列, 但它不是连续的,因为5和7在原数组里被4隔开. 示例 2: 输入: [2,2,2,2,2] 输出: 1 解释: 最长连续递增序列是 [2], 长度为1. 注意:数组长度不会超过10000. class Solution { public int find…
1. 题目 给定一个未经排序的整数数组,找到最长且连续的的递增序列. 示例 1: 输入: [1,3,5,4,7] 输出: 3 解释: 最长连续递增序列是 [1,3,5], 长度为3. 尽管 [1,3,5,7] 也是升序的子序列, 但它不是连续的,因为5和7在原数组里被4隔开. 示例 2: 输入: [2,2,2,2,2] 输出: 1 解释: 最长连续递增序列是 [2], 长度为1. 注意:数组长度不会超过10000. 来源:力扣(LeetCode) 链接:https://leetcode-cn.c…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3734 访问. 给定一个未经排序的整数数组,找到最长且连续的的递增序列. 输入: [1,3,5,4,7] 输出: 3 解释: 最长连续递增序列是 [1,3,5], 长度为3.尽管 [1,3,5,7] 也是升序的子序列, 但它不是连续的,因为5和7在原数组里被4隔开. 输入: [2,2,2,2,2] 输出: 1 解释: 最长连续递增序列是 [2], 长度为1. 注意…
Given an unsorted array of integers, find the length of longest continuous increasing subsequence. Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] i…
Given an unsorted array of integers, find the length of longest continuous increasing subsequence. Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] i…
题目: Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray). Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even tho…
Given an unsorted array of integers, find the length of longest continuous increasing subsequence. Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] i…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 动态规划 空间压缩DP 日期 题目地址:https://leetcode.com/problems/longest-continuous-increasing-subsequence/description/ 题目描述 Given an unsorted array of integers, find the length of longest co…
Longest Increasing Subsequence 最长递增子序列 子序列不是数组中连续的数. dp表达的意思是以i结尾的最长子序列,而不是前i个数字的最长子序列. 初始化是dp所有的都为1,最终的结果是求dp所有的数值的最大值. class Solution { public: int lengthOfLIS(vector<int>& nums) { int length = nums.size(); ) ; vector<); int max_num; ;i <…
[抄题]: Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray). Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even t…
给定一个未经排序的整数数组,找到最长且连续的的递增序列. 示例 1: 输入: [1,3,5,4,7] 输出: 3 解释: 最长连续递增序列是 [1,3,5], 长度为3. 尽管 [1,3,5,7] 也是升序的子序列, 但它不是连续的,因为5和7在原数组里被4隔开. 最长连续递增子序列,解法就直接模拟,从1-n,要是a[i]<a[i+1],长度加一,碰到a[i]>=a[i+1]就更新最长的递增序列长度 class Solution { public: int findLengthOfLCIS(v…
原题链接在这里:https://leetcode.com/problems/longest-continuous-increasing-subsequence/description/ 题目: Given an unsorted array of integers, find the length of longest continuous increasing subsequence. Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: T…
problem 674. Longest Continuous Increasing Subsequence solution class Solution { public: int findLengthOfLCIS(vector<int>& nums) { , cnt = , cur = INT_MAX; for(auto num:nums) { if(num>cur) cnt++; ; res = max(res, cnt); cur = num; } return res…
给定一个未经排序的整数数组,找到最长且连续的的递增序列. 示例 1: 输入: [1,3,5,4,7] 输出: 3 解释: 最长连续递增序列是 [1,3,5], 长度为3. 尽管 [1,3,5,7] 也是升序的子序列, 但它不是连续的,因为5和7在原数组里被4隔开. 示例 2: 输入: [2,2,2,2,2] 输出: 1 解释: 最长连续递增序列是 [2], 长度为1. 注意:数组长度不会超过10000. class Solution { public: int findLengthOfLCIS(…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 滑动窗口 日期 题目地址:https://leetcode-cn.com/problems/check-if-all-1s-are-at-least-length-k-places-away/ 题目描述 给你一个整数数组 nums ,和一个表示限制的整数 limit,请你返回最长连续子数组的长度,该子数组中的任意两个元素之间的绝对差必须小于或者等于 l…
这是悦乐书的第286次更新,第303篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第154题(顺位题号是674).给定未排序的整数数组,找到最长连续增加子序列的长度.例如: 输入:[1,3,5,4,7] 输出:3 说明:最长的连续增加子序列为[1,3,5],其长度为3,即使[1,3,5,7]也是一个增加的子序列,它不是一个连续的,其中5和7被4分开. 输入:[2,2,2,2,2] 输出:1 说明:最长连续增加子序列为[2],其长度为1. 注意:数组长度不超过10,0…
给定一个只包含 '(' 和 ')' 的字符串,找出最长的包含有效括号的子串的长度. 示例 1:输入: "(()"输出: 2解释: 最长有效括号子串为 "()"示例 2:输入: ")()())"输出: 4解释: 最长有效括号子串为 "()()" #include <iostream> #include <stack> using namespace std; int longestValidParenth…
编写一个函数来查找字符串数组中的最长公共前缀. 如果不存在公共前缀,返回空字符串 "". 示例 1: 输入: ["flower","flow","flight"]输出: "fl" 示例 2: 输入: ["dog","racecar","car"]输出: "" 解释: 输入不存在公共前缀.说明: 所有输入只包含小写字母 a-z .…
给定一个字符串 s,找到 s 中最长的回文子串.你可以假设 s 的最大长度为 1000. 示例 1:输入: "babad"输出: "bab"注意: "aba" 也是一个有效答案. 示例 2:输入: "cbbd"输出: "bb" 思路一:暴力法,不说了 思路二:动态规划 参考官方给的思路: How can we reuse a previously computed palindrome to compute…
问题 给定一个整数数组,你需要寻找一个连续的子数组,如果对这个子数组进行升序排序,那么整个数组都会变为升序排序. 你找到的子数组应是最短的,请输出它的长度. 输入: [2, 6, 4, 8, 10, 9, 15] 输出: 5 解释: 你只需要对 [6, 4, 8, 10, 9] 进行升序排序,那么整个表都会变为升序排序. 说明 : 输入的数组长度范围在 [1, 10,000]. 输入的数组可能包含重复元素 ,所以升序的意思是<=. Given an integer array, you need…
Given an unsorted array of integers, find the length of longest continuous increasing subsequence. Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] i…
Given an unsorted array of integers, find the length of longest continuousincreasing subsequence (subarray). Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though […
原题链接 1 class Solution: 2 def findLengthOfLCIS(self, nums: List[int]) -> int: 3 ans = begin = 0 4 for i in range(len(nums)): 5 if i > 0 and nums[i] <= nums[i-1]: 6 begin = i 7 ans = max(ans,i-begin+1) 8 return ans…
static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: int findLengthOfLCIS(vector<int>& nums) { int sz=nums.size(); ) return sz; ; int res=INT_MIN; ;i<sz;i++) { ]) count++; else { res=max(res,…
1.题目描述 2.问题分析 从每一个num[i]往前扫描即可. 3.代码 int findLengthOfLCIS(vector<int>& nums) { ){ return nums.size() ; } vector<); ; ; i < nums.size() ; i++){ ; ; j >= ; j--){ ] ) maxI++; else break; } maxans = max( maxI, maxans); } return maxans; }…
Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray). Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though…
Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray). Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though…
数组篇 # 题名 刷题 通过率 难度 1 两数之和 C#LeetCode刷题之#1-两数之和(Two Sum) 43.1% 简单 4 两个排序数组的中位数 C#LeetCode刷题之#4-两个排序数组的中位数(Median of Two Sorted Arrays)-该题未达最优解 30.1% 困难 11 盛最多水的容器 C#LeetCode刷题之#11-盛最多水的容器(Container With Most Water) 37.9% 中等 15 三数之和 C#LeetCode刷题之#15-三数…