Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

题目描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the min…

155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } void push(int x) { if(s1.empty() && s2.empty()){ s1.push(x); s2.push(x); } else{ if(x < s2.top()){ s1.push(x); s2.push(x); } else{ s1.push(x); s2…

翻译 设计支持push.pop.top和在常量时间内检索最小元素的栈. push(x) -- 推送元素X进栈 pop() -- 移除栈顶元素 top() -- 得到栈顶元素 getMin() -- 检索栈的最小元素 原文 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop…

题目 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimu…

[题目] Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the mini…

题目描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.push(x) -- Push element x onto stack.pop() -- Removes the element on top of the stack.top() -- Get the top element.getMin() -- Retrieve the minimum…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack.    pop() -- Removes the element on top of the stack.    top() -- Get the top element.    getMin() -- Retrieve the…

LeetCode相关的网上资源比较多,看到题目一定要自己做一遍,然后去学习参考其他的解法. 链接: https://oj.leetcode.com/problems/min-stack/ 题目描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Remov…

1.原文问题描述: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the…

题目: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minim…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minimum e…

https://leetcode.com/problems/min-stack/ #include <vector> #include <queue> #include <map> #include <iostream> using namespace std; class MinStack { public: vector<int> vec; priority_queue<int,vector<int>,greater<…

题意:设计一个能输出栈内最小值的栈 该题设计两个栈,一个栈是正常的栈s,而另一个是存最小值的栈sm 在push时要判断sm是否为空,如果为空或者非空但是栈顶元素大于等于插入值的 需要在sm中插入x 同样地在pop时,s的元素被删除了,那么sm中的也应该被删除. 通过这些操作维护sm能很巧妙在O(1)复杂度得到最小值. class MinStack { public: stack<int> sm; stack<int> s; void push(int x) { s.push(x);…

今天做了一道MinStack的题,深深的感到自己C++还完全没有学好!!! #include <iostream> #include <stack> using std::stack; class MinStack { public: stack<int> st; stack<int> stm; void push(int x) { st.push(x); if(stm.empty() || stm.top()>=x) { stm.push(x); }…

1- 问题描述 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the m…

原标题:https://oj.leetcode.com/problems/min-stack/ Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the…

这是悦乐书的第177次更新,第179篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第36题(顺位题号是155).设计一个支持push,pop,top和在恒定时间内检索最小元素的堆栈. push(x) - 将元素x推入堆栈. pop() - 删除堆栈顶部的元素. top() - 获取顶部元素. getMin() - 检索堆栈中的最小元素. 例如: MinStack minStack = new MinStack(); minStack.push(-2); minSta…

LeetCode 155:最小栈 Min Stack 设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈. push(x) -- 将元素 x 推入栈中. pop() -- 删除栈顶的元素. top() -- 获取栈顶元素. getMin() -- 检索栈中的最小元素. Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. pu…

Min Stack My Submissions Question Solution Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top…

Implement a stack with min() function, which will return the smallest number in the stack. It should support push, pop and min operation all in O(1) cost. Notice min operation will never be called if there is no number in the stack. Have you met this…

3.2 How would you design a stack which, in addition to push and pop, also has a function min which returns the minimum element? Push, pop and min should all operate in O(1) time. LeetCode上的原题,请参见我之前的博客Min Stack 最小栈.…

题目: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the minim…

Min Stack 本题收获: 1.可以利用两个栈操作. 2.栈的基本操作. 题目: Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top…

Min Stack Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin() -- Retrieve the…

［抄题］: 实现一个带有取最小值min方法的栈,min方法将返回当前栈中的最小值. 你实现的栈将支持push,pop 和 min 操作,所有操作要求都在O(1)时间内完成. ［思维问题］: ［一句话思路］: 用一个minstack来辅助实现 ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: 主函数中,数据结构为类+名 类是Stack<Integer> minStack.empty() == true 或者isempty都可…

遇到个好玩的问题,就是用一个stack实现min stack,什么意思呢,就是我实现stack,但是能以O(1)的时间复杂度和空间复杂度去找到我stack里面的最小值. 常规的方法是:用一个变量存放当前最小值,但是会出现这种情况,就是当我的stack pop掉的值刚好是最小值时候,后面就没法知道当前的最小值了. 怎么办呢?可以考虑在push阶段做个改变,就是在我每次往stack里面push数据的时候,跟当前的最小值比较,如果比当前最小值还小的话,那么将当前最小值入栈,再把最小值修改为这个值.在p…

[20]Valid Parentheses (2018年11月28日,复习, ko) 给了一个字符串判断是不是合法的括号配对. 题解:直接stack class Solution { public: bool isValid(string s) { set<char> st{'(', '[', '{'}; map<char, char> mp{{'(', ')'}, {'{', '}'}, {'[', ']'}}; stack<char> stk; for (auto…