HDU 5640 King's Cake GCD】的更多相关文章

King's Cake 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5640 Description It is the king's birthday before the military parade . The ministers prepared a rectangle cake of size n×m(1≤n,m≤10000) . The king plans to cut the cake himself. But he has…
King's Cake Problem Description It is the king's birthday before the military parade . The ministers prepared a rectangle cake of size n×m(1≤n,m≤10000) . The king plans to cut the cake himself. But he has a strange habit of cutting cakes. Each time,…
King's Cake Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 736    Accepted Submission(s): 539 Problem Description It is the king's birthday before the military parade . The ministers prepared a…
Problem Description   It is the king's birthday before the military parade . The ministers prepared a rectangle cake of size n×m(1≤n,m≤10000) . The king plans to cut the cake himself. But he has a strange habit of cutting cakes. Each time, he will cu…
题意: 给定长方形,每次从中切去一个最大的正方形,问最终可以得到多少正方形. 分析: 过程类似求gcd,每次减去最小的边即可. 代码: #include <cstdio> #include<algorithm> #include<iostream> using namespace std; int main (void) { int T;cin>>T; int n, m; while(T--){ cin>>n>>m; int cnt…
pid=4454" target="_blank" style="">题目链接:hdu 4454 Stealing a Cake 题目大意:给定一个起始点s,一个圆形.一个矩形.如今从起点開始,移动到圆形再移动到矩形.求最短距离. 解题思路:在圆周上三分就可以.即对角度[0,2*pi]三分.计算点和矩形的距离能够选点和矩形四条边的距离最短值. #include <cstdio> #include <cstring> #incl…
King's Cake Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 188    Accepted Submission(s): 159 Problem Description It is the king's birthday before the military parade . The ministers prepared a…
题目链接 King's Cake Time Limit: 2000/1000 MS (Java/Others)     Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 79    Accepted Submission(s): 69 Problem Description It is the king's birthday before the military parade . The ministers prepar…
题目链接:hdu 5381 The sum of gcd 将查询离线处理,依照r排序,然后从左向右处理每一个A[i],碰到查询时处理.用线段树维护.每一个节点表示从[l,i]中以l为起始的区间gcd总和.所以每次改动时须要处理[1,i-1]与i的gcd值.可是由于gcd值是递减的,成log级,对于每一个gcd值记录其区间就可以.然后用线段树段改动,可是是改动一个等差数列. #include <cstdio> #include <cstring> #include <vecto…
King's Order 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5642 Description After the king's speech , everyone is encouraged. But the war is not over. The king needs to give orders from time to time. But sometimes he can not speak things well. So i…