Given n segments in the two dimensional space, write a program, which determines if there exists a line such that after projecting these segments on it, all projected segments have at least one point in common. Input Input begins with a number T show…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13549    Accepted Submission(s): 6645 Problem Description Many geometry(几何)problems were designed in the ACM/…

Line.h #pragma once //Microsoft Visual Studio 2015 Enterprise //根据两点式方法求直线,并求两条直线的交点 #include"BoundaryPoint.h" #include"Coordinates.h" class Line { public: Line GetLine(BoundaryPoint sourcePoint, BoundaryPoint endPoint); Line GetLine(C…

题意:给出n条线段,问你是否存在一条直线让他与所有线段相交. 思路:枚举两条直线的起点和终点做一条直线,看他是否与所有线段相交. #include<cstdio> #include<cmath> #include<iostream> #include<algorithm> #include<vector> #include<stack> #include<cstring> #include<queue> #in…

原文:http://blog.csdn.net/bxyill/article/details/8962832 问题描述: 现有一直线,从原点到无穷大. 这条直线上有N个线段.线段可能相交. 问,N个线段总共覆盖了多长?(重复覆盖的地区只计算一次) ================================================ 解题思路: 可以将每个线段拆分成“单位1” 遍历所有线段,使用一个数组记录每个线段所走过的“单位1” 最后统计数组中被走过的中“单位1”的个数,即是所有线…

http://poj.org/problem?id=1269 我今天才知道原来标准的浮点输出用%.2f   并不是%.2lf  所以wa了好几次 题目大意:   就给你两个线段 然后求这两个线段所在的直线的关系  有共线  平行  和相交 #include<stdio.h> #include<string.h> #include<stdlib.h> #include<ctype.h> #include<math.h> #define N 200…

,); ,); ,); ,); var p:Point = new Point(); trace(checkPoint()) function checkPoint() { if (p1Start.x == p1End.x) { if (p2Start.x == p2End.x) { trace("平行线"); p = null; } else { p.x = p1Start.x; p.y = p2Start.y+(p1Start.x-p2Start.x)/(p2End.x-p2Sta…

//粘贴到帧上运行即可 var p1Start:Point = new Point(0,0); var p1End:Point = new Point(50,50); var p2Start:Point = new Point(50,50); var p2End:Point = new Point(100,100); var p:Point = new Point(); trace(checkPoint()) function checkPoint() { if (p1Start.x == p1…

题意: 给出n条线段两个端点的坐标,问所有线段投影到一条直线上,如果这些所有投影至少相交于一点就输出Yes!,否则输出No!. 思路: 计算几何.这道题要思考到两点: 1:把问题转化为是否存在一条直线与每条线段都有交点.证明:若存在一条直线l和所有线段相交,作一条直线m和l垂直,则m就是题中要求的直线,所有线段投影的一个公共点即为垂足. 2:枚举两两线段的各一个端点,连一条直线,再判断剩下的线段是否都和这条直线有交点.证明:若有l和所有线段相交,则可保持l和所有线段相交,左右平移l到和某一线段交…

Segments Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8579   Accepted: 2608 Description Given n segments in the two dimensional space, write a program, which determines if there exists a line such that after projecting these segments…