leetcode总结：permutations, permutations II, next permutation, permutation sequence

【leetcode总结：permutations, permutations II, next permutation, permutation sequence】的更多相关文章

【一天一道LeetCode】#47. Permutations II

一天一道LeetCode系列 (一)题目 Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example, [1,1,2] have the following unique permutations: [1,1,2], [1,2,1], and [2,1,1]. (二)解题求全排列数.具体思路可以参考[一天一道LeetCode]#…

【LeetCode】47. Permutations II 解题报告（Python & C++）

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录题目描述题目大意解题方法方法一:递归方法二:回溯法日期题目地址:https://leetcode.com/problems/permutations-ii/description/ 题目描述 Given a collection of numbers that might contain duplicates, return all possible unique p…

[Leetcode][Python]46: Permutations

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 46: Permutationshttps://leetcode.com/problems/permutations/ Given a collection of numbers, return all possible permutations.For example,[1,2,3] have the following permutations:[1,2,3], [1,3…

LeetCode：46. Permutations（Medium）

1. 原题链接 https://leetcode.com/problems/permutations/description/ 2. 题目要求给定一个整型数组nums,数组中的数字互不相同,返回该数组所有的排列组合 3. 解题思路采用递归的方法,使用一个tempList用来暂存可能的排列. 4. 代码实现 import java.util.ArrayList; import java.util.List; public class Permutations46 { public static…

【LeetCode】46. Permutations 解题报告（Python & C++）

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录题目描述解题方法方法一:库函数方法二:递归方法三:回溯法日期题目地址:https://leetcode.com/problems/permutations/description/ 题目描述 Given a collection of distinct numbers, return all possible permutations. For example, [1,…

LeetCode Single Number I / II / III

[1]LeetCode 136 Single Number 题意:奇数个数,其中除了一个数只出现一次外,其他数都是成对出现,比如1,2,2,3,3...,求出该单个数. 解法:容易想到异或的性质,两个相同的数异或为0,那么把这串数从头到尾异或起来,最后的数就是要求的那个数. 代码如下: class Solution { public: int singleNumber(vector<int>& nums) { ; ;i<nums.size();i++) sum ^= nums[i…

[array] leetcode - 40. Combination Sum II - Medium

leetcode - 40. Combination Sum II - Medium descrition Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combinat…