poj1269---直线位置关系】的更多相关文章

Toy Storage Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5439   Accepted: 3234 Description Mom and dad have a problem: their child, Reza, never puts his toys away when he is finished playing with them. They gave Reza a rectangular box…
题目链接:POJ 1269 Problem Description We all know that a pair of distinct points on a plane defines a line and that a pair of lines on a plane will intersect in one of three ways: 1) no intersection because they are parallel, 2) intersect in a line becau…
题目传送门:POJ 1269 Intersecting Lines Description We all know that a pair of distinct points on a plane defines a line and that a pair of lines on a plane will intersect in one of three ways: 1) no intersection because they are parallel, 2) intersect in…
题目链接:http://poj.org/problem?id=1269 题意:给你两条直线上的任意不同的两点,然后求两条直线的位置关系,如果相交于一点输出该点坐标; #include<iostream> #include<algorithm> #include<math.h> #include<string.h> #include<stdio.h> #include<map> #include<vector> #inclu…
两条直线可能有三种关系:1.共线     2.平行(不包括共线)    3.相交. 那给定两条直线怎么判断他们的位置关系呢.还是用到向量的叉积 例题:POJ 1269 题意:这道题是给定四个点p1, p2, p3, p4,直线L1,L2分别穿过前两个和后两个点.来判断直线L1和L2的关系 这三种关系一个一个来看: 1. 共线. 如果两条直线共线的话,那么另外一条直线上的点一定在这一条直线上.所以p3在p1p2上,所以用get_direction(p1, p2, p3)来判断p3相对于p1p2的关…
题目链接:http://poj.org/problem?id=1269 题面: Description We all know that a pair of distinct points on a plane defines a line and that a pair of lines on a plane will intersect in one of three ways: 1) no intersection because they are parallel, 2) interse…
题目链接:http://poj.org/problem?id=2318 题面: TOYS Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 17413   Accepted: 8300 Description Calculate the number of toys that land in each bin of a partitioned toy box. Mom and dad have a problem - the…
题目链接 题意 判断两条直线的位置关系,重合/平行/相交(求交点). 直线以其上两点的形式给出(点坐标为整点). 思路 写出直线的一般式方程(用\(gcd\)化为最简), 计算\(\begin{vmatrix}a1&b1\\a2&b2\end{vmatrix}\), 若不为\(0\),则两直线有交点,\[x=\frac{\begin{vmatrix}-c1&b1\\-c2&b2\end{vmatrix}}{\begin{vmatrix}a1&b1\\a2&b…
题目传送门 题意:判断两条直线的位置关系,共线或平行或相交 分析:先判断平行还是共线,最后就是相交.平行用叉积判断向量,共线的话也用叉积判断点,相交求交点 /************************************************ * Author :Running_Time * Created Time :2015/10/24 星期六 09:08:55 * File Name :POJ_1269.cpp *********************************…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1756 题意:中文题,套模板即可: /* 射线法:判断一个点是在多边形内部,边上还是在外部,时间复杂度为O(n): 射线法可以正确用于凹多边形: 射线法是使用最广泛的算法,这是由于相比较其他算法而言,它不但可以正 确使用在凹多边形上,而且不需要考虑精度误差问题.该算法思想是从点出 发向右水平做一条射线,计算该射线与多边形的边的相交点个数,当点不在 多边形边上时,如果是奇数,那么点就一定在多边形内部,否…