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题意:对于一个数\(x\),有函数\(f(x)\),如果它是偶数,则\(x/=2\),否则\(x-=1\),不断重复这个过程,直到\(x-1\),我们记\(x\)到\(1\)的这个过程为\(path(x)\),它表示这个过程中所有\(x\)的值,现在给你一个数\(n\)和\(k\),要你找出最大的数\(x\),并且\(x\)在\(path[1,n]\)中出现的次数不小于\(k\). 题解:我们对于\(x\)可以选择分奇偶来讨论. 1.假如\(x\)为奇数,那么根据题意,我们知道\(x,2x,2x…

链接: https://codeforces.com/contest/1271/problem/E 题意: At first, let's define function f(x) as follows: f(x)={x2x−1if x is evenotherwise We can see that if we choose some value v and will apply function f to it, then apply f to f(v), and so on, we'll…

目录 Codeforces Round #608 (Div. 2) 题解 前言 A. Suits 题意 做法 程序 B. Blocks 题意 做法 程序 C. Shawarma Tent 题意 做法 程序 D. Portals 题意 做法 程序 E. Common Number 题意 做法 程序 结束语 Codeforces Round #608 (Div. 2) 题解 前言 题目链接:仅仅只是为了方便以题目作为关键字能查找到我的题解而已(逃 Codeforces 1271A Codeforce…

Codeforces Round #521 (Div. 3)  E. Thematic Contests 题目传送门 题意: 现在有n个题目,每种题目有自己的类型要举办一次考试,考试的原则是每天只有一种题目类型一种题目类型只能出现在一天每天的题目类型不能相同,而且后一天的题目数量必须正好为前一天的两倍,第一天的题目数量是任意的求怎么安排能使题目尽量多.注意:不是天数尽量多 思路: 首先我们知道一件事,题目属于哪种类型并不重要,重要的是每种类型的个数所以我们先统计出所有类型的个数,存进一个数组,而…

传送门 A. Suits 签到. Code /* * Author: heyuhhh * Created Time: 2019/12/15 17:16:33 */ #include <iostream> #include <algorithm> #include <cstring> #include <vector> #include <cmath> #include <set> #include <map> #inclu…

引子: A题过于简单导致不敢提交,拖拖拉拉10多分钟还是决定交,太冲动交错了CE一发,我就知道又要错过一次涨分的机会.... B题还是过了,根据题意目测数组大小开1e5,居然蒙对,感觉用vector更好一点... C题WA第9组,GG思密达....明天起床再补C吧 - - 题目链接: http://codeforces.com/contest/835/problem/B B. The number on the board Some natural number was written on t…

链接: https://codeforces.com/contest/1215/problem/B 题意: You are given a sequence a1,a2,-,an consisting of n non-zero integers (i.e. ai≠0). You have to calculate two following values: the number of pairs of indices (l,r) (l≤r) such that al⋅al+1-ar−1⋅ar…

链接: https://codeforces.com/contest/1271/problem/D 题意: You play a strategic video game (yeah, we ran out of good problem legends). In this game you control a large army, and your goal is to conquer n castles of your opponent. Let's describe the game p…

D. Minimum number of steps time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of s…

http://codeforces.com/problemset/problem/182/D 题意:如果把字符串a重复m次可以得到字符串b,那么我们称字符串a为字符串b的一个因子,现在给定两个字符串S1和S2,求它们的公共因子个数. 思路: 先求最小循环节,如果最小循环节不同,那么肯定是没有公共因子的.如果相同的话,那就看循环节长度为1,2,3...是否可行. #include<iostream> #include<cstdio> #include<cstring> u…

E - Bus Number 最近感觉打CF各种车祸.....感觉要反思一下, 上次读错题,这次想当然地以为18!肯定暴了longlong 而没有去实践, 这个题我看到就感觉是枚举每个数字的个数,但是我觉得算得时候会爆longlong 就想用大数,但是我去看别人交的全部都是C++,就感觉是不是有别的方法, 想了半天感觉时间来不及了就强行上了个java,结果时间来不及... 以后写题首先要读清楚题目,其次不要想当然,要去实践!!!!!!!!!!! 真的很烦. import java.math.Bi…

B. Perfect Number time limit per test2 seconds memory limit per test256 megabytes Problem Description We consider a positive integer perfect, if and only if the sum of its digits is exactly 10. Given a positive integer k, your task is to find the k-t…

传送门 题意 给出n个数及x,求 \[\frac{\sum _{i=1}^n x^{a_1+a_2+...+a_{i-1}+a_{i+1}+...a_n}}{\prod_{i=1}^n x^{a_i}}\] 分析 结果必然为\(x^{sum}\),sum的值首先取所有数的和减去最大值 然后暴力合并,具体原因我不太懂,只能附上CF的标准题解 Obviously, the answer is \(x^v\). Let \(sum = a1 + a2 + ... + an\). Also let $s…

比赛传送门 再次改下写博客的格式,以锻炼自己码字能力 A. Suits 题意:有四种材料,第一套西装需要 \(a\).\(d\) 各一件,卖 \(e\) 块:第二套西装需要 \(b\).\(c\).\(d\) 各一件,卖 \(f\) 块.问,怎么做套装卖的前最多. 题解:[贪心]---- 先选比较贵的那一套,因为 \(d\) 套都要用上则以它为基准,再用剩余材料加第二套的总价钱 // https://codeforces.com/contest/1271/problem/A #include<i…

题目传送门 B. Perfect Number time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output We consider a positive integer perfect, if and only if the sum of its digits is exactly 1010. Given a positive integ…

B. Long Number time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a long decimal number aa consisting of nn digits from 11 to 99. You also have a function ff that maps every dig…

题目链接:https://codeforces.com/contest/1384/problem/A 题意 构造 $n+1$ 个字符串,使得 $n$ 对相邻字符串的相同前缀长度对应于数组 $a$ . 题解 构造一个足够长的字符串,每次反转前缀不同处的字符即可. 代码 #include <bits/stdc++.h> using namespace std; void solve() { int n; cin >> n; string s(200, 'a'); cout <&l…

#include <iostream> #include <vector> using namespace std; int main(){ ; cin >> n >>k; ; i < n ; ++ i ){ int a; vector<,); cin >> a; while(a){ <=k) goodNum[a%]++; a/=; } ; ; j < k+; ++ j) if(!goodNum[j]) break; )…

题目大意:给你n个点的一棵树, 每个点的权值为2^i ,让你删掉k个点使得剩下的权值和最大. 思路:这题还是比较好想的, 我们反过来考虑, 剩下一个的情况肯定是选第n个点,剩下两个 我们肯定优先考虑第n - 1 个点, 因为其他点全部加起来都没有这个点的权值大, 所以我们可以 以第n个点为根, 倍增出每个点祖先的情况, 然后从后往前贪心, 能取到就取, 不能取到就跳过. #include<bits/stdc++.h> #define LL long long #define fi first…

最后肯定是bbbb...aaaa...这样. 你每进行一系列替换操作,相当于把一个a移动到右侧. 会增加一些b的数量……然后你统计一下就行.式子很简单. 喵喵喵,我分段统计的,用了等比数列……感觉智障.一个a一个a地统计答案即可. #include<cstdio> #include<cstring> #include<iostream> using namespace std; #define MOD 1000000007ll typedef long long ll;…

#define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ],b[],c[]; int u,v; ],least[]; pair<]; vector<]; bool cmp(int a,int b){ return a>b; } int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int n,m,…

题意:你起初有一支军队,有$k$个士兵,现在有$n$座城堡,你若想占领第$i$座城堡,至少得有$a[i]$个士兵才能占领$($占领后士兵不会减少$)$,占领了第$i$座城堡后,你将得到$b[i]$个士兵,然后你有两种方式防御你占领的城堡: 在你占领第$i$个城堡后留下一个士兵防御第$i$个城堡 有$m$个传送门,能从$u_{i}$传送到$v_{i}(u_{i}>v_{i})$,你可以在占领完第$u_{i}$座城堡后再派一个士兵去防御第$v_{i}$个城堡 如果你防御了第$i$座城堡,你能得到$c…

传送门 D. Arthur and Walls time limit per test 2 seconds memory limit per test 512 megabytes input standard input output standard output Finally it is a day when Arthur has enough money for buying an apartment. He found a great option close to the cente…

B. More Cowbell Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/604/problem/B Description Kevin Sun wants to move his precious collection of n cowbells from Naperthrill to Exeter, where there is actually grass instead of co…

C. Read Time Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/343/problem/C Description Mad scientist Mike does not use slow hard disks. His modification of a hard drive has not one, but n different heads that can read data i…

B. Robin Hood 题目连接: http://www.codeforces.com/contest/671/problem/B Description We all know the impressive story of Robin Hood. Robin Hood uses his archery skills and his wits to steal the money from rich, and return it to the poor. There are n citiz…

B. Skills 题目连接: http://www.codeforces.com/contest/613/problem/B Description Lesha plays the recently published new version of the legendary game hacknet. In this version character skill mechanism was introduced. Now, each player character has exactly…

链接: https://codeforces.com/contest/1230/problem/C 题意: Anadi has a set of dominoes. Every domino has two parts, and each part contains some dots. For every a and b such that 1≤a≤b≤6, there is exactly one domino with a dots on one half and b dots on th…

The link to problem:Problem - D - Codeforces   D. Range and Partition  time limit per test: 2 seconds memory limit per test: 256 megabytes input: standard input output: standard output Given an array a of n integers, find a range of values [x,y] (x≤y…