The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are responsible for…

时间限制:0.5s 空间限制:6M 题意: 显然就是求一个无源汇有上下界的网络流的可行流的问题 Solution: 没什么好说的,直接判定可行流,输出就好了 code /* 无汇源有上下界的网络流 */ #include <iostream> #include <cstring> #define ms(a,b) memset(a,b,sizeof a) using namespace std; ; struct node { int u, v, c, ne; } edge[MAXN…

Reactor Cooling time limit per test: 0.5 sec. memory limit per test: 65536 KB input: standard output: standard The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nu…

题意: 给定n个点和m条边, 每条边有流量上下限[b,c], 求是否存在一种流动方法使得每条边流量在范围内, 而且每个点的流入 = 流出 分析: 无源汇有上下界最大流模板, 记录每个点流的 in 和 out , 然后如果一个点 i 的in > out,  从源点i连一条边到in, out > in 就从i 连一条边到 v. #include <cstdio> #include <iostream> #include <cstring> #include &l…

[题目分析] 无源汇上下界可行流. 上下界网络流的问题可以参考这里.↓ http://www.cnblogs.com/kane0526/archive/2013/04/05/3001108.html [代码] #include <cstdio> #include <cstring> #include <cmath> #include <cstdlib> //#include <map> #include <set> #include…

题目描述 The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are responsibl…

题目链接: http://acm.sgu.ru/problem.php?contest=0&problem=194 题目大意: n个点(n<20000!!!不是200!!!RE了无数次),m条边(管子)(m范围好像没说,我开了10^6),每个点流入的和流出的液体要相等,每条边(管子)有上下界流量,问是否有解,有解YES无解NO,有解还要输出每条边的流量. 题目输入样例略坑,我以为要多组数据输入输出TEST #1 什么的.后来仔细看了Input发现只有一组吧应该,保险起见还是写了多组,但是不用…

Description The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are res…

[题目链接] http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=20757 [题意] 求有容量上下界的无源无汇可行流. [思路] 无源无汇可行流要求所有的顶点都满足流量平衡. 基本思路是转化成最大流来做. 对于边(u,v,b,c),连边(u,v,c-b).为了保持流量平衡,我们还需要连边         1.(S,u,inB[u]-outB[u])  inB>outB 2.(u,T,outB[u]-inB[u])  outB>…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1314 题意: 给n个点,及m根pipe,每根pipe用来流躺液体的,单向的,每时每刻每根pipe流进来的物质要等于流出去的物质,要使得m条pipe组成一个循环体,里面流躺物质. 并且满足每根pipe一定的流量限制,范围为[Li,Ri].即要满足每时刻流进来的不能超过Ri(最大流问题),同时最小不能低于Li. 求的是最大流. 很久之前就看了带上下界的网络流,一直没看懂…