A. As Easy As Possible 每个点往右贪心找最近的点,可以得到一棵树,然后倍增查询即可. 时间复杂度$O((n+m)\log n)$. #include <bits/stdc++.h> using namespace std ; typedef long long LL ; typedef long long Int ; typedef pair < int , int > pi ; #define clr(a,x) memset ( a , x , sizeof…
A. Hacker Cups and Balls 二分答案,将$\geq mid$的数看成$1$,$<mid$的数看成$0$,用线段树进行区间排序检查即可.时间复杂度$O(n\log^2n)$. #include<cstdio> #include<algorithm> using namespace std; const int N=100010,M=262150; int n,m,i,a[N],e[N][2],l,r,MID,ans; int len[M],c1[M],ta…
D 考虑每个点被删除时其他点对它的贡献,然后发现要求出距离为1~k的点对有多少个. 树分治+FFT.分治时把所有点放一起做一遍FFT,然后减去把每棵子树单独做FFT求出来的值. 复杂度$nlog^2n$ #include<bits/stdc++.h> #define N 270000 #define pi acos(-1) #define ll long long #define inf 0x3f3f3f3f using namespace std; const int p = 10000…
题目: You are given one string S consisting of only '0' and '1'. You are bored, so you start to play with the string. In each operation, you can move any character of this string to some other position in the string. For example, suppose . Then you can…
题目:Statements Dreamoon likes algorithm competitions very much. But when he feels crazy because he cannot figure out any solution for any problem in a competition, he often draws many meaningless straight line segments on his calculation paper. Dreamo…
题目: Dreamoon likes algorithm competitions very much. But when he feels crazy because he cannot figure out any solution for any problem in a competition, he often draws many meaningless straight line segments on his calculation paper. Dreamoon's calcu…
作者:我爱机器学习原文链接:SIGKDD历年Best Papers SIGKDD(Data Mining)(1997-2016) 年份 标题 一作 一作单位 2016 FRAUDAR: Bounding Graph Fraud in the Face of Camouflage Bryan Hooi Carnegie Mellon University 2015 Efficient Algorithms for Public-Private Social Networks Flavio Chie…
数据挖掘方面重要会议的最佳paper集合,兴许将陆续分析一下内容: 主要有KDD.SIGMOD.VLDB.ICML.SIGIR KDD (Data Mining) 2013 Simple and Deterministic Matrix Sketching Edo Liberty, Yahoo! Research 2012 Searching and Mining Trillions of Time Series Subsequences under Dynamic Time Warping T…
