首先注意一下题面要求,使得选出的线段两两要么包含要么不相交,也就是说一条线段可能会出现不相交的几条线段,而这些线段上面也可能继续这样包含线段.然后我们可以发现我们要做的实际上是在这条线段上选取几条线段然后递归求出子问题,这是一个 \(dp\) 的形式,令 \(f_i\) 表示在线段 \(i\) 上最多能选出多少个满足条件的区间.但是在这里拓扑序我们还未知,我们看看能否求出这个 \(dp\) 的拓扑序.我们发现对于任意一条线段我们能选择被它包含的线段必然左端点大于该线段左端点,右端点大于该线段左端…

The only difference between easy and hard versions is a number of elements in the array. You are given an array aa consisting of nn integers. The value of the ii-th element of the array is aiai. You are also given a set of mm segments. The jj-th segm…

You are given an array a1,a2,…,an of integer numbers. Your task is to divide the array into the maximum number of segments in such a way that: each element is contained in exactly one segment; each segment contains at least one element; there doesn't…

传送门:http://codeforces.com/contest/1108/problem/E2 E2. Array and Segments (Hard version) time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The only difference between easy and hard versions i…

题目传送门 题意:给出一个序列,试将其划分为尽可能多的非空子段,满足每一个元素出现且仅出现在其中一个子段中,且在这些子段中任取若干子段,它们包含的所有数的异或和不能为0． 思路:先处理出前缀异或,这样选择更多的区间其实就相当于选择更多的前缀异或,并且这些前缀异或不能异或出0,这就变成了线性基的基础题了.贪心的放,能放就放.不能放就意味着线性基的add函数里面的val最后变成了0,也就是当前已经插入的线性基已经可以异或出正在插入的数了,所以不能放. (今天真巧,一连遇到两道线性基的题目) #inc…

Codeforces 1108E2 E2. Array and Segments (Hard version) Description: The only difference between easy and hard versions is a number of elements in the array. You are given an array \(a\) consisting of \(n\) integers. The value of the \(i\)-th element…

Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Example: Input: "Hello, my name is John" Output:…

Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Both the array size and each of the array element will not exceed 100. Exam…

Given a set of distinct positive integers, find the largest subset such that every pair (Si, Sj) of elements in this subset satisfies: Si % Sj = 0 or Sj % Si = 0. If there are multiple solutions, return any subset is fine. Example 1: nums: [1,2,3] Re…

结构:Client--master host--interconnect--segment host 每个节点都是单独的PG数据库,要获得最佳的性能需要对每个节点进行独立优化. master上不包含任何的用户数据,仅保留system catalog,用户数据全部存储在segments上. master负责处理传入的sql命令,分发到对应的segments上,组合返回的结果并返回给客户端. Because the master does not contain any user data, it…

看了源码就是packagename里面必须包含一个. 源码在: ./sdk/eclipse/plugins/com.android.ide.eclipse.adt/src/com/android/ide/eclipse/adt/internal/build/builders/PreCompilerBuilder.java: "Application package '%1$s' must have a minimum of 2 segments.", 就是说:这个提示来自ADT,如果非…

题目描述 对于从1到N (1 <= N <= 39) 的连续整数集合,能划分成两个子集合,且保证每个集合的数字和是相等的.举个例子,如果N=3,对于{1,2,3}能划分成两个子集合,每个子集合的所有数字和是相等的: {3} 和 {1,2} 这是唯一一种分法(交换集合位置被认为是同一种划分方案,因此不会增加划分方案总数) 如果N=7,有四种方法能划分集合{1,2,3,4,5,6,7},每一种分法的子集合各数字和是相等的: {1,6,7} 和 {2,3,4,5} {注 1+6+7=2+3+4+5}…

Segments 执行效果 命令  在 sense 里边执行  GET /abcd/_segments  前边的是索引名称,后边是请求 段信息 说明  索引是面向分片的,是由于索引是由一个或多个分片(以及它的副本)构成,每个分片就是一个物理上的Lucene索引 返回 名词解释 已提交索引段:指那些已经执行了提交命令的段,意味着已经提交到磁盘持久化并且是只读的: 可查询索引段:可供查询使用的索引段: 索引的代:告诉我们索引有多“老”,起初创建的索引段的代为0,接着是1,依次继续: 被标记为已删除的…

Very nice DP problem. The key fact of a mutual-divisible subset: if a new number n, is divisible with the largest number m within a mutual-divisible set s, s U {n} is also a mutal-divisible subset. class Solution { public: vector<int> largestDivisib…

Problem Introduction The goal in this problem is given a set of segments on a line and a set of points on a line, to count, for each point, the number of segments which contain it. Problem Description Task.In this problem you are given a set of point…

Problem Introduction You are given a set of segments on a line and your goal is to mark as few points on a line as possible so that each segment contains at least one marked point. Problem Description Task.Given a set of n segments \(\{ [a_0, b_0], […

The segmentation and paging mechanisms provide in the support a wide variety of approaches to memorymanagement. When segmentation and paging are combined, segments can be mapped to pages in several ways.To implement a flat (unsegmented) addressing en…

N (1 <= N <= 39),问有多少种把1到N划分为两个集合的方法使得两个集合的和相等. 如果总和为奇数,那么就是0种划分方案.否则用dp做. dp[i][j]表示前 i 个数划分到一个集合里,和为j的方法数. dp[i][j]=dp[i-1][j]+dp[i][j-i] n 为 39 时,1 到 39 的和为 780,枚举 j 的时候枚举到 s/2,最后输出dp[n][s/2]/2. http://train.usaco.org/usacoprob2?a=z5hb7MFUmsX&…

Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Each of the array element will not exceed 100. The array size will not exce…

Given a set of distinct positive integers, find the largest subset such that every pair (Si, Sj) of elements in this subset satisfies: Si % Sj = 0 or Sj % Si = 0. If there are multiple solutions, return any subset is fine. Example 1: nums: [1,2,3] Re…

D. Vika and Segments     Vika has an infinite sheet of squared paper. Initially all squares are white. She introduced a two-dimensional coordinate system on this sheet and drew n black horizontal and vertical segments parallel to the coordinate axes.…

Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Example: Input: "Hello, my name is John" Output:…

制图工作中,大量密集点显示是最常遇到的问题.其特点是分布可能不均匀.数据点比较密集,容易造成空间上的重叠,影响制图美观.那么,如果美观而详细的显示制图呢? Subset Features(子集要素)工具是 ArcGIS 地统计分析模块的一个工具,该工具可将数据按照百分比进行抽稀,生成两个结果数据集,一个是抽稀后保留的数据,另一个是互补的那一部分数据. 实现原理 其原理是将数据分成两个子集.子集 1 将有 L 个要素,子集 2 将有 N - L 个要素(N 表示原始数据集中的要素数量).要素的分割…

Given a set of distinct positive integers, find the largest subset such that every pair (Si, Sj) of elements in this subset satisfies: Si % Sj = 0 or Sj % Si = 0. If there are multiple solutions, return any subset is fine. Example 1: nums: [1,2,3] Re…

https://en.wikipedia.org/wiki/Subset_sum_problem In computer science, the subset sum problem is an important problem in complexity theory and cryptography. The problem is this: given a set (or multiset) of integers, is there a non-empty subset whose…

D. Vika and Segments time limit per test:  2 seconds     memory limit per test:  256 megabytes input : standard input output:  standard output Vika has an infinite sheet of squared paper. Initially all squares are white. She introduced a two-dimensio…

1.脚本 This directory includes some useful codes: 1. subset selection tools. (子集抽取工具) subset.py 2. parameter selection tools. (参数选优工具) grid.py 3. LIBSVM format checking tools(格式检查工具)checkdata.py Part I: Subset selection tools子集抽取 Introduction =========…

Given a set of distinct positive integers, find the largest subset such that every pair (Si, Sj) of elements in this subset satisfies: Si % Sj = 0 or Sj % Si = 0. If there are multiple solutions, return any subset is fine. Example 1: nums: [1,2,3] Re…

APPLIES TO: Oracle Database - Enterprise Edition - Version 8.1.7.4 to 11.2.0.1 [Release 8.1.7 to 11.2]Information in this document applies to any platform.***Checked for relevance on 03-Nov-2014*** PURPOSE This article describes what happens when a s…

P1466 集合 Subset Sums 162通过 308提交 题目提供者该用户不存在 标签USACO 难度普及/提高- 提交  讨论  题解 最新讨论 暂时没有讨论 题目描述 对于从1到N (1 <= N <= 39) 的连续整数集合,能划分成两个子集合,且保证每个集合的数字和是相等的.举个例子,如果N=3,对于{1,2,3}能划分成两个子集合,每个子集合的所有数字和是相等的: {3} 和 {1,2} 这是唯一一种分法(交换集合位置被认为是同一种划分方案,因此不会增加划分方案总数) 如果N…