LightOJ - 1148-Mad Counting (数学)】的更多相关文章

lightoj 1148 Mad Counting 链接:http://lightoj.com/volume_showproblem.php?problem=1148 题意:民意调查,每一名公民都有盟友,问最少人数. 思路:考察的知识点有两个:第一是整数相乘取上整:第二是容器大小(ps:不能算一个知识点,只能算一个坑点). 做题思路:排序,如果被调查的人有相同盟友人数(n)的个数(cnt)大于这个数+1,即:(cnt > n+1), 容器已满,只能新开辟一个容器来装盟友. 代码: #includ…
先上题目: 1148 - Mad Counting   PDF (English) Statistics Forum Time Limit: 0.5 second(s) Memory Limit: 32 MB Mob was hijacked by the mayor of the Town "TruthTown". Mayor wants Mob to count the total population of the town. Now the naive approach to…
1148 - Mad Counting   PDF (English) Statistics Forum Time Limit: 0.5 second(s) Memory Limit: 32 MB Mob was hijacked by the mayor of the Town "TruthTown". Mayor wants Mob to count the total population of the town. Now the naive approach to this p…
1148 - Mad Counting   PDF (English) Statistics Forum Time Limit: 0.5 second(s) Memory Limit: 32 MB Mob was hijacked by the mayor of the Town "TruthTown". Mayor wants Mob to count the total population of the town. Now the naive approach to this p…
1148 - Mad Counting PDF (English) Statistics Forum Time Limit: 0.5 second(s) Memory Limit: 32 MB Mob was hijacked by the mayor of the Town "TruthTown". Mayor wants Mob to count the total population of the town. Now the naive approach to this pro…
链接: https://vjudge.net/problem/LightOJ-1058 题意: There are n distinct points in the plane, given by their integer coordinates. Find the number of parallelograms whose vertices lie on these points. In other words, find the number of 4-element subsets o…
题目链接:Inversion Counting 题意: 定义数列{ai|i=1,2,...,n}的逆序对如下:对于所有的1≤j<i≤n,若ai<aj,则<i,j>为一个逆序对.于是,对于一个数列a[1..n],给定m次操作.对于每一次操作,给定l,r(1≤l<r≤n),将序列a[l..r]倒置.求倒置后的逆序对的数量的奇偶性. 题解: 假设现在我们有一个序列并翻转这个序列[l,r]区间里面的数.假设某个数的k值是指在这个值后面小于这个数的数的个数,其实我们可以发现对于[1,l…
http://www.lightoj.com/volume_showproblem.php?problem=1058 题意:给你顶点,问能够成多少个平行四边形. 思路:开始想使用长度来扫描有多少根,但是好像坐标太大似乎不可行.其实我们可以通过找所有线段的中点的重合个数来计算有几个平行四边形,这种通过别的性质来判断几何关系的思维是解几何题的基础,当作入门? /** @Date : 2016-12-02-21.49 * @Author : Lweleth (SoungEarlf@gmail.com)…
17997 Simple Counting 时间限制:2000MS  内存限制:65535K提交次数:0 通过次数:0 题型: 编程题   语言: 不限定 Description Ly is crazy about counting . Recently , he got a simple problem , but he had to learn Gaoshu these days .So , he turns to you for help . You are given a sequenc…
You are given n rods of length 1,2, . . . , n. You have to pick any 3 of them and build a triangle. Howmany distinct triangles can you make? Note that, two triangles will be considered different if they haveat least 1 pair of arms with different length…