problem 538. Convert BST to Greater Tree 参考 1. Leetcode_easy_538. Convert BST to Greater Tree; 完…

题目如下: Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree li…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode.com/problems/convert-bst-to-greater-tree/description/ 题目描述 Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the…

lc 538 Convert BST to Greater Tree 538 Convert BST to Greater Tree Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original ke…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

题目要求 Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. 题目分析及思路 题目给出一棵二叉搜索树,要求将它转成Greater Tree.定义Greater Tre…

给定一个二叉搜索树(Binary Search Tree),把它转换成为累加树(Greater Tree),使得每个节点的值是原来的节点值加上所有大于它的节点值之和.例如:输入: 二叉搜索树:              5            /   \           2     13输出: 转换为累加树:             18            /   \          20     13详见:https://leetcode.com/problems/convert-…

这是悦乐书的第255次更新,第268篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第122题(顺位题号是538).给定二进制搜索树(BST),将其转换为更大树,使原始BST的每个键都更改为原始键加上所有键的总和大于BST中的原始键.例如: 输入:二进制搜索树的根,如下所示: 5 / \ 2 13 输出:大树的根,如下所示: 18 / \ 20 13 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,使用Java语言编写和测…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example Given a binary search Tree ｀{5,2,3}｀: 5 / \ 2 13…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary Search Tree like thi…

Level:   Easy 题目描述: Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST. Example: Input: The root of a Binary…

problem 744. Find Smallest Letter Greater Than Target 题意:一堆有序的字母,然后又给了一个target字母,让求字母数组中第一个大于target的字母,数组是循环的,如果没有,那就返回第一个字母. solution1:注意数组已经是有序数组啦...注意mid的计算,注意最后返回的元素位置. class Solution { public: char nextGreatestLetter(vector<char>& letters,…

［抄题］: 给定二叉搜索树(BST),将其转换为更大的树,使原始BST上每个节点的值都更改为在原始树中大于等于该节点值的节点值之和(包括该节点). Given a binary search Tree `{5,2,13}｀: 5 / \ 2 13 Return the root of new tree 18 / \ 20 13 [暴力解法]: 时间分析: 空间分析: ［思维问题］: ［一句话思路］: 反向求和并把和赋给root.val ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情…

https://www.cnblogs.com/grandyang/p/6591526.html 这个题本质上是中序遍历的反向.中序遍历是从小到大,而这个题目是从大到小,然后每个数加上比自己大的所有数的和. 因为实际上并没有改变树的结构,只是改变了原来树中节点的值,所以用void做返回值就可以了. 每次加sum实际上就是加的所有比当前节点大的数的和,并且这个和一定等于前一个节点的更新值. class Solution { public: TreeNode* convertBST(TreeNode…

1.题目描述 2.问题分析 使用一个vector将所有节点的值以升序排列.然后比较,求和,加上. 3.代码 TreeNode* convertBST(TreeNode* root) { if (root == NULL) return NULL; vector<int> v; inorder(root,v); increaseVal(root, v); return root; } void increaseVal(TreeNode *root, vector<int> &…

problem 669. Trim a Binary Search Tree 参考 1. Leetcode_easy_669. Trim a Binary Search Tree; 完…

problem 606. Construct String from Binary Tree 参考 1. Leetcode_easy_606. Construct String from Binary Tree; 完…

[LeetCode]109. Convert Sorted List to Binary Search Tree 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/convert-sorted-list-to-binary-search-tree/description/ 题目描述: Given a s…

[BZOJ3769]spoj 8549 BST again Description 求有多少棵大小为n的深度为h的二叉树.(树根深度为0:左右子树有别:答案对1000000007取模) Input 第一行一个整数T,表示数据组数. 以下T行,每行2个整数n和h. Output 共T行,每行一个整数表示答案(对1000000007取模) Sample Input 2 2 1 3 2 Sample Output 2 4 HINT 对于100%的数据,1<=n<=600,0<=h<=60…

[LeetCode]297. Serialize and Deserialize Binary Tree 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/serialize-and-deserialize-binary-tree/description/ 题目描述: Serialization is the process of converting a data structure or object into a se…

[BZOJ2002]弹飞绵羊(Link-Cut Tree) 题面 题目描述 某天,Lostmonkey发明了一种超级弹力装置,为了在他的绵羊朋友面前显摆,他邀请小绵羊一起玩个游戏.游戏一开始,Lostmonkey在地上沿着一条直线摆上n个装置,每个装置设定初始弹力系数ki,当绵羊达到第i个装置时,它会往后弹ki步,达到第i+ki个装置,若不存在第i+ki个装置,则绵羊被弹飞.绵羊想知道当它从第i个装置起步时,被弹几次后会被弹飞.为了使得游戏更有趣,Lostmonkey可以修改某个弹力装置的弹力系…

[BZOJ2588]Spoj 10628. Count on a tree Description 给定一棵N个节点的树,每个点有一个权值,对于M个询问(u,v,k),你需要回答u xor lastans和v这两个节点间第K小的点权.其中lastans是上一个询问的答案,初始为0,即第一个询问的u是明文. Input 第一行两个整数N,M. 第二行有N个整数,其中第i个整数表示点i的权值. 后面N-1行每行两个整数(x,y),表示点x到点y有一条边. 最后M行每行两个整数(u,v,k),表示一组…

[CF600E]Lomsat gelral(dsu on tree) 题面 洛谷 CF题面自己去找找吧. 题解 \(dsu\ on\ tree\)板子题 其实就是做子树询问的一个较快的方法. 对于子树的询问,我们不难想到子树就是\(dfs\)序上的连续一段, 可以把树转化成序列再用莫队来解. 其实可以对树进行树链剖分,然后暴力+优化来解 具体的做法就是: 递归处理轻儿子,计算轻儿子答案, 然后消去轻儿子对于答案的影响. 然后递归处理重儿子,不消去影响,最后加入所有轻儿子贡献,计算答案. 复杂度?…

[BZOJ1977][BeiJing2010组队]次小生成树 Tree Description 小 C 最近学了很多最小生成树的算法,Prim 算法.Kurskal 算法.消圈算法等等. 正当小 C 洋洋得意之时,小 P 又来泼小 C 冷水了.小 P 说,让小 C 求出一个无向图的次小生成树,而且这个次小生成树还得是严格次小的,也就是说: 如果最小生成树选择的边集是 EM,严格次小生成树选择的边集是 ES,那么需要满足:(value(e) 表示边 e的权值)  这下小 C 蒙了,他找到了你,希望…

[题解]CF611H New Year and Forgotten Tree 神题了... 题目描述 给定你一棵树,可是每个节点上的编号看不清了,只能辨别它的长度.现在用问号的个数代表每个节点编号那个数字的长度,请你还原这一颗树,任意输出一个方案,有PSJ\(SPJ\)来检验你的正确性.无解输出一行\(-1\) . 输入格式: 第一行一个整数\(n\). 接下来 \(n-1\)行每行两个有问号构成的字符串,代表编号长度. 输出格式 : 若有解,直接输出\(n-1\)行,每行两个正整数,代表你还原…