Max Sum Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 161294    Accepted Submission(s): 37775 Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max s…

链接: http://acm.hdu.edu.cn/showproblem.php?pid=1003 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 180817    Accepted Submission(s): 42261 Problem Description Given a sequence a[1],a[2],a[3]....…

Max Sum Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 207989 Accepted Submission(s): 48681 Problem Description Given a sequence a[1],a[2],a[3]--a[n], your job is to calculate the max sum of a su…

这题的意思就是取m个连续的区间,使它们的和最大,下面就是建立状态转移方程 dp[i][j]表示已经有 i 个区间,最后一个区间的末尾是a[j] 那么dp[i][j]=max(dp[i][j-1]+a[j],max(dp[i-1][1..j-1])+a[j]) 看数据范围,1e6 肯定开不下数组,观察发现,dp[i][j]仅和dp[i][j-1]和dp[i-1][1..j-1]中最大值有关,即只和dp[i-1]有关 所以开滚动数组求解   复杂度可以通过开数组mmax[j]表示dp[i-1][1.…

Max Sum Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 154155    Accepted Submission(s): 35958 Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max su…

Problem Description Now I think you have got an AC in Ignatius.L's "Max Sum" problem. To be a brave ACMer, we always challenge ourselves to more difficult problems. Now you are faced with a more difficult problem. Given a consecutive number sequ…

http://acm.hdu.edu.cn/showproblem.php?pid=1024 Max Sum Plus Plus Problem Description Now I think you have got an AC in Ignatius.L's "Max Sum" problem. To be a brave ACMer, we always challenge ourselves to more difficult problems. Now you are fac…

Now I think you have got an AC in Ignatius.L's "Max Sum" problem. To be a brave ACMer, we always challenge ourselves to more difficult problems. Now you are faced with a more difficult problem.  Given a consecutive number sequence S 1, S 2, S 3,…

Max Sum Plus Plus Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 36673    Accepted Submission(s): 13069 Problem Description Now I think you have got an AC in Ignatius.L's "Max Sum" proble…

 #include <iostream> #include<stdio.h> #include<stdlib.h> using namespace std; int main() {     int t;     scanf("%d",&t);     for(int i=0;i<t;i++)     {         int n;         scanf("%d",&n);         int…