123 $_ = "beforematcha? fter";    124 if(/\b\w+a\b/){    125     print "matched: <$`><$&><$'>|\n";    126 } if(/a\b/) 这样的模式匹配也行,\b是单词边界锚点,即以a结尾的单词都可以匹配到…
本文转载自: http://www.jb51.net/article/19330.htm 1概述 “\b”匹配单词边界,不匹配任何字符. “\b”匹配的只是一个位置,这个位置的一侧是构成单词的字符,另一侧为非单词字符.字符串的开始或结束位置.“\b”是零宽度的. 基本上所有的资料里都会说“\b”是单词边界,但是关于“单词”的范围却是少有提及.通常情况下,正则表达式中所谓的“单词”,就是由“\w”所定义的字符所组成的子串. “\b”表示所在位置的一侧为单词字符,另一侧为非单词字符.字符串的开始或结…
re.findall  匹配到正则表达式的字符,匹配到的每个字符存入一个列表,返回一个匹配到的所有字符列表 一. 匹配单个字符 import re # \w 匹配所有字母.数字.下划线 re.findall('\w','abcd_123 *-') # 结果为:['a', 'b', 'c', 'd', '_', '1', '2', '3'] # \s 匹配所有不可见字符 # 不可见字符有:\n \t 空格 re.findall('\s','abcd \n\tdf21 ') # 结果为:[' ',…
Leetcode之回溯法专题-212. 单词搜索 II(Word Search II) 给定一个二维网格 board 和一个字典中的单词列表 words,找出所有同时在二维网格和字典中出现的单词. 单词必须按照字母顺序,通过相邻的单元格内的字母构成,其中“相邻”单元格是那些水平相邻或垂直相邻的单元格.同一个单元格内的字母在一个单词中不允许被重复使用. 示例: 输入: words = ["oath","pea","eat","rain&q…
Leetcode之广度优先搜索(BFS)专题-127. 单词接龙(Word Ladder) BFS入门详解:Leetcode之广度优先搜索(BFS)专题-429. N叉树的层序遍历(N-ary Tree Level Order Traversal) 相同思路的题目:Leetcode之广度优先搜索(BFS)专题-752. 打开转盘锁(Open the Lock) 给定两个单词(beginWord 和 endWord)和一个字典,找到从 beginWord 到 endWord 的最短转换序列的长度.…
package com.swift.lianxi; import java.util.HashMap; import java.util.Iterator; import java.util.Map; import java.util.Set; /*1.请简述Map 的特点 2.请简述HashMap的特点 3.请简述LinkedHashMap的特点 4.使用代码依次完成: a).将如下键值对信息存入Map集合中: "黄晓明", "Baby" "邓超&quo…
Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist in the word list. Note…
This is a follow up of Shortest Word Distance. The only difference is now you are given the list of words and your method will be called repeatedly many times with different parameters. How would you optimize it? Design a class which receives a list…
This is a follow up of Shortest Word Distance. The only difference is now word1 could be the same as word2. Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list. word1 and word2 may be…
找出最短路径 [抄题]: Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist i…