C. ReplacementTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/570/problem/C Description Daniel has a string s, consisting of lowercase English letters and period signs (characters '.'). Let's define the operation of replace…

E. Editor The development of a text editor is a hard problem. You need to implement an extra module for brackets coloring in text. Your editor consists of a line with infinite length and cursor, which points to the current character. Please note that…

B. Legacy 题目连接: http://codeforces.com/contest/786/problem/B Description Rick and his co-workers have made a new radioactive formula and a lot of bad guys are after them. So Rick wants to give his legacy to Morty before bad guys catch them. There are…

题目链接:http://codeforces.com/contest/765/problem/F 题意概述: 给出一个序列,若干组询问,问给出下标区间中两数作差的最小绝对值. 分析: 这个题揭示着数据结构题目世界的真谛...... 在线显然凉凉......考虑离线做法. 本题的主要思想: 首先考虑把所有的询问按照右端点排序,用一个指针扫整个序列,同时考虑i作为一组差的右端可以对右端点大于等于i的询问做出的贡献.我们可以发现,我们扫到当前点i,对于所有询问的右端点大于等于i的询问,如果其左端点小于…

B. Legacy 题目连接: http://codeforces.com/contest/786/problem/B Description Rick and his co-workers have made a new radioactive formula and a lot of bad guys are after them. So Rick wants to give his legacy to Morty before bad guys catch them. There are…

C. Replacement Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/570/problem/C Description Daniel has a string s, consisting of lowercase English letters and period signs (characters '.'). Let's define the operation of replac…

题意:给定一个字符串,里面有各种小写字母和' . ' ,无论是什么字母,都是一样的,假设遇到' . . ' ,就要合并成一个' .',有m个询问,每次都在字符串某个位置上将原来的字符改成题目给的字符,问每次须要多少次合并次数.才使字符串没有' .. ' 思路:最原始的想法,就是对于每一次询问,都遍历整个字符串.这样时间复杂度o(n*m),就高达10^10方,非常明显会tle. 换下思路,事实上每次询问所改变的字符都会保留到下一次.也就是下一次的次数就会受到上一次的影响,那么我仅仅要就算出第一次的…

C. Replacement time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Daniel has a string s, consisting of lowercase English letters and period signs (characters '.'). Let's define the operation…

题目:Click here 题意:看一下题目下面的Note就会明白的. 分析:一开始想的麻烦了,用了树状数组(第一次用)优化,可惜没用. 直接判断: #include <bits/stdc++.h> using namespace std; typedef long long ll; const int INF = 0x3f3f3f3f; ; int n, m; char str[M]; int main() { while( ~scanf("%d %d", &n,…

先扫描一遍得到每个位置向后连续的'.'的长度,包含自身,然后在扫一遍求出初始的合并次数. 对于询问,只要对应位置判断一下是不是'.',以及周围的情况. #include<bits/stdc++.h> using namespace std; ; char s[maxn]; int post[maxn]; int main() { //freopen("in.txt","r",stdin); int n,m; scanf("%d%d",…

A. Replacement 题目连接: http://codeforces.com/contest/135/problem/A Description Little Petya very much likes arrays consisting of n integers, where each of them is in the range from 1 to 109, inclusive. Recently he has received one such array as a gift…

题目链接: http://codeforces.com/contest/14/problem/D D. Two Paths time limit per test2 secondsmemory limit per test64 megabytes 问题描述 As you know, Bob's brother lives in Flatland. In Flatland there are n cities, connected by n - 1 two-way roads. The citie…

http://codeforces.com/contest/101/problem/B 给定一个数n,起点是0  终点是n,有m两车,每辆车是从s开去t的,我们只能从[s,s+1,s+2....t-1]处上车,从t处下车., 问能否去到点n,求方案数 设L[x]表示有多少辆车能够到达x处. 只能从t处下车:说明只能单点更新,对于没辆车x,在区间[s,s+1,s+2....t-1]内上车是可以得,那么有多少辆车呢?明显就是∑区间里能到达的点.然后单点更新t即可 数据大,明显不能到达的点是没用的,离…

http://codeforces.com/problemset/problem/12/D 这里的BIT查询,指的是查询[1, R]或者[R, maxn]之间的最值,这样就够用了. 设三个权值分别是b[1], b[2], b[2]; 首先,先把b[1]值离散化,离散成一个个id,那么只能是在id比较大的地方找了.然后把b[2]排序,倒序查询,也就是先查询最大的,当然它是没可能自杀的,因为它已经最大了,然后查询完后,把它压进bit后,以后在bit查询,就不需要管b[2]了,因为在bit里面的b[2…

E. Pillars time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Marmot found a row with n pillars. The i-th pillar has the height of hi meters. Starting from one pillar i1, Marmot wants to jump…

D. Legacy time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Rick and his co-workers have made a new radioactive formula and a lot of bad guys are after them. So Rick wants to give his legacy…

D. Strip time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Alexandra has a paper strip with n numbers on it. Let's call them ai from left to right. Now Alexandra wants to split it into some p…

Strip time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Alexandra has a paper strip with n numbers on it. Let's call them ai from left to right. Now Alexandra wants to split it into some piec…

Toposort   问题描述 给出nn个点mm条边的有向无环图. 要求删掉恰好kk条边使得字典序最小的拓扑序列尽可能小. 输入描述 输入包含多组数据. 第一行有一个整数TT, 表示测试数据组数. 对于每组数据: 第一行包含3个整数nn, mm和kk (1 \le n \le 100000, 0 \le k \le m \le 200000)(1≤n≤100000,0≤k≤m≤200000), 表示图中结点数目, 图中边的数目以及要删的边数. 接下来mm行, 每行包含两个整数u_iu​i​​ a…

Codeforces Beta Round #80 (Div. 2 Only) A Blackjack1 题意 一共52张扑克,A代表1或者11,2-10表示自己的数字,其他都表示10 现在你已经有一个queen了,问你有多少种方案,能够得到n点 题解 其实只用考虑三种情况,都考虑一下就好了,实在不行就暴力枚举-- 代码 #include<bits/stdc++.h> using namespace std; int n; int main() { scanf("%d",&…

Codeforces Beta Round #83 (Div. 1 Only) A. Dorm Water Supply 题意 给你一个n点m边的图,保证每个点的入度和出度最多为1 如果这个点入度为0,那么这个点就是水龙头点. 如果这个点的出度为0,那么这个点就是储存点. 现在让你把所有水龙头到储存点的路径都输出出来,且输出这条路径的边权最小值 题解 显然是个仙人掌图,所以直接XJB暴力就好了 代码 #include<bits/stdc++.h> using namespace std; co…

Codeforces Beta Round #79 (Div. 2 Only) http://codeforces.com/contest/102 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define pb push_back #define eb empla…

Codeforces Beta Round #77 (Div. 2 Only) http://codeforces.com/contest/96 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define pb push_back #define eb emplac…

Codeforces Beta Round #76 (Div. 2 Only) http://codeforces.com/contest/94 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define pb push_back #define eb emplac…

Codeforces Beta Round #75 (Div. 2 Only) http://codeforces.com/contest/92 A #include<iostream> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define maxn 100005 typedef long long ll; t…

Codeforces Beta Round #74 (Div. 2 Only) http://codeforces.com/contest/90 A #include<iostream> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define maxn 100005 typedef long long ll; t…

Codeforces Beta Round #73 (Div. 2 Only) http://codeforces.com/contest/88 A 模拟 #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define pb push_back #define eb emp…

Codeforces Beta Round #72 (Div. 2 Only) http://codeforces.com/contest/84 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define pb push_back #define eb emplac…

Codeforces Beta Round #70 (Div. 2) http://codeforces.com/contest/78 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define pb push_back #define eb emplace_bac…

Codeforces Beta Round #69 (Div. 2 Only) http://codeforces.com/contest/80 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define sqr(x) ((x)*(x)) #define pb push_back #define eb emplac…