class Solution { public: int strStr(char *haystack, char *needle) { , skip[]; char *str = haystack, *substr = needle; int len_src = strlen(str), len_sub = strlen(substr); // preprocess ; i < ; i++) skip[i] = len_sub; ; ; i < last;i++) skip[substr[i]…
数据结构与算法--Boyer-Moore和Rabin-Karp子字符串查找 Boyer-Moore字符串查找算法 注意,<算法4>上将这个版本的实现称为Broyer-Moore算法,我看了下没有关于"好后缀"的介绍,推测应该说的是Boyer-Moore-Horsepool算法,即Boyer-Moore算法的简化版本. 暴力法和KMP算法,都是从左到右比较字符串的各个字符.换种思路,如果从右往左比较字符呢?这就是将要学习的Boyer-Moore算法.和KMP算法一样,需要一个…
Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 额,当然我用的就是暴力搜索来,没用到KMP之类的算法,有时间再来补上辣,代码如下: class Solution { public: int strStr(string haystack, string needle) { ; ; ; i <= h…
Implement strStr(). Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Example 1: Input: haystack = "hello", needle = "ll" Output: 2 Example 2: Input: haystack = "aaaaa",…
Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 问题:实现 strStr() 函数.即在  haystack 中匹配 needle 字符串. 可以理解为,实际上这道题是在问如何实现 KMP(Knuth–Morris–Pratt) 算法.这是个效率比较高的算法,只需要扫一遍 haystack 就可…
这个题目是典型的KMP算法,当然也可以试试BM,当然有关KMP和BM的介绍阮一峰曾经写过比较好的科普,然后july也有讲解,不过那个太长了. 先放题目吧: Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Update (2014-11-02): The signature of the func…
Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 解法: 这道题让我们在一个字符串中找另一个字符串第一次出现的位置,那我们首先要做一些判断,如果子字符串为空,则返回0,如果子字符串长度大于母字符串长度,则返回-1.然后我们开始遍历母字符串,我们并不需要遍历整个母字符串,而是遍历到剩下的长度和子字符…
Implement strStr() Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 最简单的思路,逐一比较: class Solution { public: int strStr(char *haystack, char *needle) { int n1=strlen(haystack);…
Given a string, your task is to count how many palindromic substrings in this string. The substrings with different start indexes or end indexes are counted as different substrings even they consist of same characters. Example 1: Input: "abc" Ou…
题目: Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 思路: 题意:判断一个字符串是否包含另外一个 写一个函数判断一个字符串从坐标k,是否相等于另一个,遍历一下,i < a.length() -b.length()+1,b.length() < a.length() - 代码: public…