Question 796. Rotate String Solution 题目大意:两个字符串匹配 思路:Brute Force Java实现: public boolean rotateString(String A, String B) { if (A.length() != B.length()) return false; if (A.length() == 0) return true; // Brute Force for (int i=0; i<A.length(); i++) {…

344. Reverse String 最基础的旋转字符串 class Solution { public: void reverseString(vector<char>& s) { if(s.empty()) return; ; ; while(start < end){ char tmp = s[end]; s[end] = s[start]; s[start] = tmp; start++; end--; } return; } }; 541. Reverse Strin…

problem 796. Rotate String solution1: class Solution { public: bool rotateString(string A, string B) { if(A.size()!=B.size()) return false; && B.size()==) return true;//errr... ; i<A.size(); ++i) { , i) == B) return true; } return false; } }; s…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/rotate-string/description/ 题目描述 We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost charac…

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom…

［抄题］: We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can…

class Solution { public: bool rotateString(string A, string B) { if(A.length()==B.length()&&(A+A).find(B)!=string::npos) return true; return false; } }; 把俩A拼起来,能找到B,则可以通过循环右移将A转化为B…

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom…

这是悦乐书的第317次更新,第338篇原创 在开始今天的算法题前,说几句,今天是世界读书日,推荐两本书给大家,<终身成长>和<禅与摩托车维修艺术>,值得好好阅读和反复阅读. 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第186题(顺位题号是796).给定两个字符串A和B,在A上进行移位操作,规则是将A最左边的字符移动到最右边去.例如,如果A ='abcde',那么在A上移位一次后,它将是'bcdea'.当且仅当A在A上移位一定次数后可以变为B时返回True.…

Given a string and an offset, rotate string by offset. (rotate from left to right) Example Given "abcdefg". offset=0 => "abcdefg" offset=1 => "gabcdef" offset=2 => "fgabcde" offset=3 => "efgabcd&quo…

Given a string and an offset, rotate string by offset. (rotate from left to right) Example Given "abcdefg" for offset=0, return "abcdefg" for offset=1, return "gabcdef" for offset=2, return "fgabcde" for offset=3, r…

8. Rotate String Description Given a string and an offset, rotate string by offset. (rotate from left to right) Example Given "abcdefg". offset=0 => "abcdefg" offset=1 => "gabcdef" offset=2 => "fgabcde" off…

Description Given a string and an offset, rotate string by offset. (rotate from left to right) Example Given "abcdefg". offset=0 => "abcdefg" offset=1 => "gabcdef" offset=2 => "fgabcde" offset=3 => "…

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom…

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom…

1.题目描述 2.问题分析 直接旋转字符串A,然后做比较即可. 3.代码 bool rotateString(string A, string B) { if( A.size() != B.size() ) return false; if( A.empty() && B.empty() ) return true; ; while( i < A.size() ){ ] ; A += c; A.erase( A.begin() ); if( A == B ) return true;…

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom…

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom…

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom…

题目: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we ma…

原题链接: http://oj.leetcode.com/problems/scramble-string/  这道题看起来是比較复杂的,假设用brute force,每次做分割,然后递归求解,是一个非多项式的复杂度,一般来说这不是面试官想要的答案. 这事实上是一道三维动态规划的题目,我们提出维护量res[i][j][n],当中i是s1的起始字符,j是s2的起始字符,而n是当前的字符串长度,res[i][j][len]表示的是以i和j分别为s1和s2起点的长度为len的字符串是不是互为scram…

Question 438. Find All Anagrams in a String Solution 题目大意:给两个字符串,s和p,求p在s中出现的位置,p串中的字符无序,ab=ba 思路:起初想的是求p的全排列,保存到set中,遍历s,如果在set中出现,s中的第一个字符位置保存到结果中,最后返回结果.这种思路执行超时.可能是求全排列超时的. 思路2:先把p中的字符及字符出现的次数统计出来保存到map中,再遍历s,这个思路和169. Majority Element - LeetCode…

Question 48. Rotate Image Solution 把这个二维数组(矩阵)看成一个一个环,循环每个环,循环每条边,每个边上的点进行旋转 public void rotate(int[][] matrix) { int n = matrix.length; for (int i = 0; i < n / 2; i++) { change(matrix, i); } } private void change(int[][] matrix, int i) { int n = mat…

Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2. For example,Given:s1 = "aabcc",s2 = "dbbca", When s3 = "aadbbcbcac", return true.When s3 = "aadbbbaccc", return false. 定义boolean 数组result…

You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up:Could you do this in-place? Solution: void rotate(vector<vector<int> > &matrix) { int n = matrix.size(); ; i < n / ; i ++) { -…

题目: Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2. For example, Given: s1 = "aabcc", s2 = "dbbca", When s3 = "aadbbcbcac", return true. When s3 = "aadbbbaccc", return false. 题解: 这道题还是像…

Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2. For example,Given:s1 = "aabcc",s2 = "dbbca", When s3 = "aadbbcbcac", return true.When s3 = "aadbbbaccc", return false. 题目大意:给定三个字符串,s1,s2…

思路:在原来的字符串后面添加上strlen-1个字符,返回 class Solution { public: string reverseString(string s) { unsigned int strlen; int i; // char temp; strlen = s.size(); ) { ; i >= ; i--) { // temp = s[i]; s += s[i]; } , strlen + strlen - ); } else return s; } };…

Given a list, rotate the list to the right by k places, where k is non-negative. For example:Given 1->2->3->4->5->NULL and k = 2,return 4->5->1->2->3->NULL. 题目大意:给一个链表和一个非负整数k,把链表向右循环移位k位. 解题思路:踩了个坑,k有可能比链表的长度还长,比如长度为3的链表,k=2…

Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. click to show clarification. Clari…