HDU5862 Counting Intersections】的更多相关文章

题目链接: Counting Intersections Time Limit: 12000/6000 MS (Java/Others)     Memory Limit: 65536/65536 K (Java/Others) Problem Description Given some segments which are paralleled to the coordinate axis. You need to count the number of their intersection…
Given some segments which are paralleled to the coordinate axis. You need to count the number of their intersection. The input data guarantee that no two segments share the same endpoint, no covered segments, and no segments with length 0. InputThe f…
传送门:hdu 5862 Counting Intersections 题意:对于平行于坐标轴的n条线段,求两两相交的线段对有多少个,包括十,T型 官方题解:由于数据限制,只有竖向与横向的线段才会产生交点,所以先对横向线段按x端点排序,每次加入一个线段,将其对应的y坐标位置+1,当出现一个竖向线段时,查询它的两个y端点之间的和即为交点个数. 注意点:对x坐标排序是对所有线段端点排序:因为可能出现 “  1-1  “ 这样的情况,所以对于横着的线段,需要进行首尾x坐标处理:我的方法是对于x坐标,先…
Counting Intersections 题目链接: http://acm.split.hdu.edu.cn/showproblem.php?pid=5862 Description Given some segments which are paralleled to the coordinate axis. You need to count the number of their intersection. The input data guarantee that no two se…
HDU 5862 Counting Intersections(离散化+树状数组) 题目链接http://acm.split.hdu.edu.cn/showproblem.php?pid=5862 Description Given some segments which are paralleled to the coordinate axis. You need to count the number of their intersection. The input data guarant…
Counting Intersections Time Limit: 12000/6000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description Given some segments which are paralleled to the coordinate axis. You need to count the number of their intersection. The i…
题目链接: http://acm.split.hdu.edu.cn/showproblem.php?pid=5862 Counting Intersections Time Limit: 12000/6000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) 问题描述 Given some segments which are paralleled to the coordinate axis. You need to coun…
Counting Intersections Time Limit: 12000/6000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1138    Accepted Submission(s): 347 Problem Description Given some segments which are paralleled to the coordinate axis. Y…
传送门:Hdu 5862 Counting Intersections 题意:有n条线段,每一条线段都是平行于x轴或者y轴,问有多少个交点 分析: 基本的操作流程是:先将所有的线段按照横树坐标x按小的优先排序,注意是所有的线段 :(这里是将线段都去掉只保留两个端点) 然后从左到右的顺序经行扫描,遇到横的线段,如果是左端点对应的 yi 便++ , 若是右端点对应的y1便--:  遇到竖直的线段,便统计区间[y1,y2] 的数 , 看到这了是不是有点东西了呢? 如果我是按照x排序的话,两线段若想相交…
题意 有n条线段,且都平行于坐标轴.对于每条线段,给出两个端点的坐标.问一共有多少个线段的交点. 分析 最最简单的扫描法了.用线段树或者树状数组都可以. 由题目可知,线段只有两种,要么平行于x轴要么平行于y轴.而交点只能是两个不平行的线段产生的. 所有我们以一条平行于x轴的线为扫描线,从下向上扫.先把横坐标进行离散化,然后把平行于y轴的线段拆成上下两个端点.当扫到下端点的时候就在它横坐标+1,当扫到上端点的时候,就在它横坐标-1.对于每一条平行于x轴的线,则将左右端点内的值相加.就酱~ 这里一个…