LightOJ - 1333 - Grid Coloring】的更多相关文章

链接: https://vjudge.net/problem/LightOJ-1333 题意: You have to color an M x N two dimensional grid. You will be provided K different colors for this. You will also be provided a list of B blocked cells of this grid. You cannot color these blocked cells.…
地址:http://arc080.contest.atcoder.jp/tasks/arc080_b 题目: D - Grid Coloring Time limit : 2sec / Memory limit : 256MB Score : 400 points Problem Statement We have a grid with H rows and W columns of squares. Snuke is painting these squares in colors 1, 2…
C - 4-adjacent Time limit : 2sec / Memory limit : 256MB Score : 400 points Problem Statement We have a sequence of length N, a=(a1,a2,…,aN). Each ai is a positive integer. Snuke's objective is to permute the element in a so that the following conditi…
题目传送门 题目大意: 给出n*m的网格,有红蓝两种颜色,每个格子都必须被染色,当一个格子被染成蓝色后,这个格子左上方的一块都必须被染成蓝色,问最后的方案数量. 思路: 按照题目条件,如果有一个格子被染成了红色,则这个格子的右下方要全部被染成红色,也就是这个给出的网格能让我们染色的,是一个左上方和右下方都是阶梯型的图形,而对于每一行来说,当一个格子被染成了蓝色,那么左边的所有格子都必须被染成蓝色,所以我们设 f[ i ][ j ] 表示第 i 行 第 j 个格子被染成蓝色的方案数量,那么这个dp…
A - K-City Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement In K-city, there are n streets running east-west, and m streets running north-south. Each street running east-west and each street running north-south cross each…
A. Odd Palindrome 所有回文子串长度都是奇数等价于不存在长度为$2$的偶回文子串,即相邻两个字符都不同. #include<cstdio> #include<cstring> char a[1111111];int n,i; int main(){ scanf("%s",a+1); n=strlen(a+1); for(i=1;i<n;i++)if(a[i]==a[i+1])return puts("Or not."),…
C - 4-adjacent Time limit : 2sec / Memory limit : 256MB Problem Statement We have a sequence of length N, a=(a1,a2,-,aN). Each ai is a positive integer. Snuke's objective is to permute the element in a so that the following condition is satisfied: Fo…
C - 4-adjacent 我们挑出来4的倍数和不是4的倍数而是2的倍数,和奇数 然后就是放一个奇数,放一个4,如果一个奇数之后无法放4,然后它又不是最后一个,那么就不合法 #include <bits/stdc++.h> #define fi first #define se second #define pii pair<int,int> #define mp make_pair #define pb push_back #define space putchar(' ')…
题目链接:http://abc069.contest.atcoder.jp/assignments A - K-City Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement In K-city, there are n streets running east-west, and m streets running north-south. Each street running east-w…
一 演示效果 二  参考教程 <ActionScript3.0 高级动画教程> + 源码 http://download.csdn.net/download/zhengchengpeng/7756023 三 AStar源码 Main.ts新建Game,即可看Demo this.addChild(new Game()) 源码地址: https://files.cnblogs.com/files/gamedaybyday/astar_ts.rar AStar核心类 /** * A星寻路 * @au…
A - Odd Palindrome 水. #include <bits/stdc++.h> using namespace std; #define N 110 char s[N]; inline bool work() { int len = strlen(s); ; i < len; ++i) { ]) return false; } return true; } int main() { while (scanf("%s", s) != EOF) { puts…
链接 C. 4-adjacent 给定序列$a_i$,询问是否存在一个排列,满足$a_{p[i]}* a_{p[i + 1]}$是4的倍数 贪心构造 首先把只是2的倍数的数拿出来,放在最右边 前面把是1的倍数的数和是4的倍数的数交替放置即可 之后随意判断即可 #include <cstdio> #include <cstring> #include <iostream> using namespace std; extern inline char gc() { ],…
手贱去开了abc,这么无聊.直接arc啊 C - 4-adjacent Time limit : 2sec / Memory limit : 256MB Score : 400 points Problem Statement We have a sequence of length N, a=(a1,a2,…,aN). Each ai is a positive integer. Snuke's objective is to permute the element in a so that…
Lights inside 3D Grid LightOJ - 1284 题意: 在一个三维的空间,每个点都有一盏灯,开始全是关的, 现在每次随机选两个点,把两个点之间的全部点,开关都按一遍:问k次过后开着的灯的期望数量: 题解:对每个点 单独计算贡献,即k次过后每个点开关被按了奇数次的期望 对于每个点来说,要使得该点开关被按过,那么选择的两个点不能在该点的同侧,即三个方向上都在两侧 这样的概率为$P = \frac{(X \cdot X - (i - 1) \cdot (i - 1) - (X…
题目链接:https://vjudge.net/problem/LightOJ-1284 1284 - Lights inside 3D Grid    PDF (English) Statistics Forum Time Limit: 4 second(s) Memory Limit: 32 MB You are given a 3D grid, which has dimensions X, Y and Z. Each of the X x Y x Z cells contains a l…
题面: You are given a 3D grid, which has dimensions X, Y and Z. Each of the X x Y x Z cells contains a light. Initially all lights are off. You will have K turns. In each of the K turns, .... 题意: 一个大立方体里面选择k次小的立方体,将小的立方体里面灯泡的开关按一下,问最后的小灯泡亮起的个数期望 思路: 单独…
题意:给你一个长宽高为x,y,z的长方体,里面每个格子放了灯,再给你k次选取任意长方体形状的区块,对其内所有灯开或关操作,初始为关,问亮灯数量的期望值. 题解:首先考虑选取区块的概率,使某个灯在被选取的区块内要求为三维的每个坐标都在选取范围内如 \(x1<=x0<=x2\) 一个维度为选中的情况总数为\[Q_{x} = x^2 - (a-1)^2 - (x-a)^2 \] 所以一个格点被选到的概率为\(p=\frac{Q_{x}Q_{y}Q_{z}}{{x^2}{y^2}{z^2}} \) 再…
题意:在一个三维的空间,每个点都有一盏灯,开始全是关的.现在每次随机选两个点,把两个点之间的全部点,开关都按一遍,问k次过后开着的灯的期望数量: 析:很容易知道,如果一盏灯被按了奇数次,那么它肯定是开的,否则就是关的,所以我们只要计算每盏灯开着的概率就好了.对于每盏灯,假设开一次的概率是p, 这个很容易求得,那么开一共k次有奇数次开着的和是多少呢?假设Fn表示n次奇数的和,那么Fn = Fn * (1-p) + (1-Fn)*p,然后就好算了.解得Fn = 0.5 - 0.5*(1-2p)^n.…
学习博客: 戳这里 戳这里 戳这里 戳这里 题意: 在一个三维的空间,每个点都有一盏灯,开始全是关的, 现在每次随机选两个点,把两个点之间的全部点,开关都按一遍:问k次过后开着的灯的期望数量: 题解: 肯定不能从随机抽取两个数这里入手的,要求开着的灯的数量就从对每一盏灯,操作结束后灯开着的概率,然后将这些概率求和就是对于整个矩阵到最后开着的灯的数量了,这就把矩阵的问题落实到了对于求每个坐标的概率的问题. 对每个点单独计算贡献,即k次过后每个点开关被按了奇数次的期望 一个点如果被包到所选空间里,那…
http://codeforces.com/contest/111/problem/D Little Petya loves counting. He wants to count the number of ways to paint a rectangular checkered board of size n × m (n rows, m columns) in k colors. Besides, the coloring should have the following proper…
转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud  Emoogle Grid  You have to color an MxN ( 1M, N108) two dimensional grid. You will be provided K ( 2K108) different colors to do so. You will also be provided a list of B ( 0B500) list of blo…
Description You are in a cave, a long cave! The cave can be represented by a 1 x N grid. Each cell of the cave can contain any amount of gold. Initially you are in position 1. Now each turn you throw a perfect 6 sided dice. If you get X in the dice a…
1366 - Pair of Touching Circles   PDF (English) Statistics Forum Time Limit: 3 second(s) Memory Limit: 32 MB You are given a rectangular grid of height H and width W. A problem setter wants to draw a pair of circles inside the rectangle so that they…
问题 E: Coloring Dominoes 时间限制: 1 Sec  内存限制: 128 MB提交: 279  解决: 95[提交] [状态] [讨论版] [命题人:] 题目描述 We have a board with a 2×N grid. Snuke covered the board with N dominoes without overlaps. Here, a domino can cover a 1×2 or 2×1 square. Then, Snuke decided t…
传送门:http://www.lightoj.com/volume_showproblem.php?problem=1030 Discovering Gold Time Limit: 2 second(s) Memory Limit: 32 MB Program Description You are in a cave, a long cave! The cave can be represented by a 1 x N grid. Each cell of the cave can con…
题目链接:LightOJ 1418 Problem Description I have bought an island where I want to plant trees in rows and columns. So, the trees will form a rectangular grid and each of them can be thought of having integer coordinates by taking a suitable grid point as…
题目链接:LightOJ - 1030 Description You are in a cave, a long cave! The cave can be represented by a \(1 \times N\) grid. Each cell of the cave can contain any amount of gold. Initially you are in position \(1\). Now each turn you throw a perfect \(6\) s…
Emoogle Grid You have to color an M × N (1 ≤ M, N ≤ 108 ) two dimensional grid. You will be provided K (2 ≤ K ≤ 108 ) different colors to do so. You will also be provided a list of B (0 ≤ B ≤ 500) list of blocked cells of this grid. You cannot color…
ExtJS 4.2 Grid组件本身并没有提供单元格合并功能,需要自己实现这个功能. 目录 1. 原理 2. 多列合并 3. 代码与在线演示 1. 原理 1.1 HTML代码分析 首先创建一个Grid组件,然后查看下的HTML源码. 1.1.1 Grid组件 1.1.2 HTML代码 从这些代码中可以看出,Grid组件可分为grid-header和grid-body 两块区域(若含有工具栏和分页栏,它们都会含有各自的独立区域). 其中grid-body包含了许多tr元素,每一个tr都是代表Gri…
/// <summary> /// 给Grid添加边框线 /// </summary> /// <param name="grid"></param> public static void InsertFrameForGrid(Grid grid) { var rowcon = grid.RowDefinitions.Count; var clcon = grid.ColumnDefinitions.Count; ; i < row…