ACM International Collegiate Programming Contest World Finals 2013 A - Self-Assembly 题目描述:给出\(n\)个正方形组件,正方形每条边有一个标签,标签可能是00,表示这条边不能与其它边相拼,也可能是一个字母加正号或负号,相同字母不同符号的边可以相拼.每个组件有无限个,问利用这些组件是否能拼出一个无限大的多边形. solution 拆点,每个正方形拆成\(4\)个点,每条边一个,然后每条边拆成两个点(出点和入点)…

KYOCERA Programming Contest 2021(AtCoder Beginner Contest 200) 题解 哦淦我已经菜到被ABC吊打了. A - Century 首先把当前年份减去\(1\),对应的世纪也减去\(1\),然后我们就发现第\(0\)到\(99\)年对应第\(0\)世纪,第\(100\)到\(199\)年对应第\(1\)世纪,以此类推. 答案就是\(\lfloor \frac {N-1} {100} \rfloor\).这里\(\lfloor x \rflo…

Problem H High bridge, low bridge Q: There are one high bridge and one low bridge across the river. The river has flooded twice, why the high bridge is flooded twice but the low bridge is flooded only once? A: Because the lower bridge is so low that…

ACM International Collegiate Programming Contest World Finals 2014 A - Baggage 题目描述:有\(2n\)个字符摆在编号为\(1\)~\(2n\)格子里,奇数位为\(B\),偶数位为\(A\),另外编号为\((-2n+1)\)~\(0\)的格子是空的,现在可以移动两个相邻的字符,移动到两个空的格子里,最终使得全部\(A\)在全部\(B\)的左边,而且字符都是连续的,但不必放回原位,输出最小步数的方案. solution…

Consider an n \times mn×m matrix of ones and zeros. For example, this 4 \times 44×4: \displaystyle \begin{matrix} 1 & 1 & 1 & 1 \\ 0 & 1 & 1 & 1 \\ 0 & 1 & 1 & 1 \\ 0 & 1 & 1 & 0 \end{matrix}1000​1111​1111​1…

2016 China Collegiate Programming Contest Final Table of Contents 2016 China Collegiate Programming Contest FinalProblem A:Problem J:Problem H: Problem A: 题意:喝咖啡,每三杯就又可以有免费一杯,求最少花费: 分析:贪心: #include <bits/stdc++.h> using namespace std; const int inf…

layout: post title: (寒假开黑gym)2017-2018 ACM-ICPC German Collegiate Programming Contest (GCPC 2017) author: "luowentaoaa" catalog: true tags: mathjax: true - codeforces 传送门 付队! 许老师! B.Buildings (polya定理) 题意 B:给你m面墙,每面墙是n*n的格子,你有c种颜色,问你有多少种涂色方案.用po…

layout: post title: 2018-2019 ACM-ICPC Brazil Subregional Programming Contest author: "luowentaoaa" catalog: true tags: mathjax: true - codeforces 传送门 付队! 许老师! B.Marbles (nim博弈) 题意 一个棋盘n个点,每次可以把一个棋子移动到(x-d,y) or (x,y-d) or (x-d,y-d) 把其中一个棋子移动到(0…

$$2018-2019 ACM-ICPC Brazil Subregional Programming Contest$$ \(A.Slackline\ Adventure\) \(B.Marbles\) NIM游戏,把其中任意一个石子移动到(0,0)算赢,所以必败态为全部石子都到(1,2)和(2,1)这两个点而不是(0,0)了,跑出sg函数异或即可,注意如果出现先手直接赢的需要特判 //#pragma comment(linker, "/STACK:1024000000,1024000000&…

    Programming Contest Problem Types Hal Burch conducted an analysis over spring break of 1999 and made an amazing discovery: there are only 16 types of programming contest problems! Furthermore, the top several comprise almost 80% of the problems s…