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[LeetCode] 42. Trapping Rain Water 收集雨水

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of…

leetcode#42 Trapping rain water的五种解法详解

leetcode#42 Trapping rain water 这道题十分有意思,可以用很多方法做出来,每种方法的思想都值得让人细细体会. 42. Trapping Rain WaterGiven n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For ex…

[array] leetcode - 42. Trapping Rain Water - Hard

leetcode - 42. Trapping Rain Water - Hard descrition Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1],…

LeetCode 42. Trapping Rain Water 【两种解法】（python排序遍历，C++ STL map存索引，时间复杂度O（nlogn））

LeetCode 42. Trapping Rain Water Python解法 解题思路: 本思路需找到最高点左右遍历,时间复杂度O(nlogn),以下为向左遍历的过程. 将每一个点的高度和索引存成一个元组 (val, idx) 找到最高的点(可能有多个,任取一个),记为 (now_val, now_idx). 向左找第一个val不大于now_val的点(left_val, left_idx). 以left_val作为水平面,用height[left_val+1, now_val-1]中每一…

LeetCode - 42. Trapping Rain Water

42. Trapping Rain Water Problem's Link ---------------------------------------------------------------------------- Mean: 在坐标上给你一些竖直放置的条形积木,问你这个积木能够容纳多少液体. analyse: 首先找出最高的积木,然后从前往后一直扫到最高积木,从后往前一直扫到最高积木,两部分体积相加即可. Time complexity: O(N) view code ;  …

leetCode 42.Trapping Rain Water(凹槽的雨水) 解题思路和方法

Trapping Rain Water Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example,  Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. The above elevation ma…

【LeetCode】42. Trapping Rain Water 接雨水 （C++）

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 暴力求解 保存左右最大值 单调栈 日期 题目地址:https://leetcode-cn.com/problems/string-to-integer-atoi/ 题目描述 Given n non-negative integers representing an elevation map where the width of each bar is…

[leetcode]42. Trapping Rain Water雨水积水问题

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of…

[LeetCode] 42. Trapping Rain Water 解题思路

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. The above elevation map is represented by a…

[LeetCode]42. Trapping Rain Water雨水填坑

这个题难点在于无法保证右边是不是有更高的墙可以保证挡住水 双指针可以解决 /* 两边指针保证,保证另外一边肯定有能挡住水的地方. 如果从一边开始,不考虑另一边,是无法保证右边肯定有挡水的墙,如果右边只都比这个值小,遍历的时候是不能增加结果的 双指针每次取较小的一方开始遍历 */ public int trap(int[] height) { if (height.length<3) return 0; int l = 0; int r = height.length-1; int res = 0…