Japan   Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 26544   Accepted: 7206 Description Japan plans to welcome the ACM ICPC World Finals and a lot of roads…

Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cities on the East coast and M cities on the West coast (M <= 1000, N <= 1000). K superhighways will be build. Cities on eac…

Japan Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 25489   Accepted: 6907 Description Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cities on the East coas…

Japan Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.uestc.edu.cn/#/problem/show/383 Description Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cities on the East c…

09.00 – 09.45 hrs Tracks Cloud, Mobile, & IoT Security    A New Security Paradigm for IoT (Internet of Threats) Hadi Nahari, Founder, R62 Security Computing has changed since the 50s except for security; nowhere is this more apparent than in the IoT.…

09.00 – 09.45 hrs Advanced Malware and the Cloud: The New Concept of 'Attack Fan-out' Krishna Narayanaswamy,Chief Scientist, Netskope The rapid rise in cloud adoption, of which organizations have underestimated the scope of by nearly 10x, has created…

Time Limit: 1000MS Memory Limit: 65536K Description Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cities on the East coast and M cities on the West coast (M <= 1000, N <=…

转载请注明出处:http://blog.csdn.net/u012860063 题目链接:id=3067">http://poj.org/problem? id=3067 Description Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cities on the East coast…

Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cities on the East coast and M cities on the West coast (M <= 1000, N <= 1000). K superhighways will be build. Cities on eac…

地址:http://acm.uestc.edu.cn/#/contest/show/95 题目: R - Japan Time Limit: 3000/1000MS (Java/Others)     Memory Limit: 65535/65535KB (Java/Others) Submit Status N Input T Output For each test case write one line on the standard output: Test case (case nu…

题目链接:POJ 3067 Japan Japan Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 32076   Accepted: 8620 Description Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cit…

From Global Times Two days before US President Donald Trump's visit to Japan, A fake news story caught the globe's eye on Thursday- Japan's Panasonic said it was suspending business with Huawei "to comply with restrictions". It was reported that…

Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 26270   Accepted: 7132 Description Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cities on the East coast and…

Description Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cities on the East coast and M cities on the West coast (M <= 1000, N <= 1000). K superhighways will be build. C…

Description Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cities on the East coast and M cities on the West coast (M <= 1000, N <= 1000). K superhighways will be build. C…

http://poj.org/problem?id=3067 Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 29474   Accepted: 7950 Description Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with…

Japan plans to welcome the ACM ICPC World Finals and a lot of roads must be built for the venue. Japan is tall island with N cities on the East coast and M cities on the West coast (M <= 1000, N <= 1000). K superhighways will be build. Cities on eac…

先按第一个数从大到小排序,相等的情况下,第二个数按照从大到小排序..... 预处理后,照着树状数组写就行了... 注意:k的最大值应取1000*1000 代码如下: include <cstdio> #include <cstdlib> #include <cmath> #include <cstring> #include <cstdlib> #include <stack> #include <queue> #incl…

<Windows Azure Platform 系列文章目录> 微软官方博客今天表示,微软宣布将在日本东部(埼玉县)和日本西部(大阪)提供Windows Azure服务.就在最近,微软为Windows Azure推出了大规模的更新,大量新特性添加到云平台. Windows Azure也就是微软的云平台,通过该平台能够跨微软管辖的数据中心全球网络快速构建.部署和管理应用程序.可以使用任何语言构建应用程序.工具或框架,以及将其集成到现有的IT环境. 据微软称,在过去的几年日本的云市场增长迅速,20…

基础一维树状数组  题意:左边一排 1-n 的城市,右边一排 1-m 的城市,都从上到下依次对应.接着给你一些城市对,表示城市这两个城市相连,最后问你一共有多少个交叉,其中处于城市处的交叉不算并且每个位置最多只能有有一个交叉. 树状数组:利用二进制特点解决单点更新与满足区间减法的区间求值,例如求区间和.二进制:因为每个数字一定可以用二进制转化为 log2 n个数,所以我们可以另外开一个数组bit记录当前位置前 二进制表示此位置的最后一位1代表数的个数之和(例如:10->1010记录前两个数).所…

题目 //暴力的,没什么算法的,被琪琪视为傻逼的代码: //照者学长的神奇幸运卡时代码,虽然能AC,但是中途wa,tle了那么多次,啥也不想说了 //学长威武,能想出sum必须要是—— __int64 —— org #define _CRT_SECURE_NO_WARNINGS #include<stdio.h> #include<string.h> #include<algorithm> #include<math.h> using namespace s…

上午有两场summits,议题分别是: sum-w01: G2B: Cyber-Business in Myanmar, Indonesia and Thailand sum-w02: Achieving e-Commerce Success through Effective Internet Security: A Primer for SMEs Myanmar是东南亚第二大国家,按照speaker的说法,人口多,发展快,市场很有潜力.不过business不是我们关心的,听了10分钟换场.…

13.30 hrs Keynote    Security in the World-Sized Web Bruce Schneier,Chief Technology Officer, Resilient, an IBM Company, and Security  Information technology permeates all aspects of our lives. The combination of mobile, cloud computing, the IoT, per…

# 国内出发 早上8:45的航班,首次从深圳机场乘坐国际航班(先前去日本.欧洲都从香港走),就提前了3个小时出发. 乘taxi到机场30分钟不到,135元.到了T3 4号出发口,发现check-in的柜台工作人员还未上班…… check-in之后,直接准备过关登机.走到负一电梯口,发现不太对劲,底下黑乎乎的,不像有人上班. 下去之后,一位海关工作人员看到我们,提示直接往前走,路上包括安检机器.过关通道全未启动……等走到前方,突然灯光亮起,海关表示“这么早来干嘛,里面没吃没喝没购物,你们7点半再来…

题目大意:有两排城市,这两排城市之间有一些路相互连接着,求有多少条路相互交叉. 思路:把全部的路先依照x值从小到大排序,x值同样的依照y值从小到大排序,然后插入边的时候,先找有多少比自己y值小的,这些边的x值一定比自己大,也就是一个逆序对,然后统计起来.记得答案要用long long (__int64) CODE: #include <cstdio> #include <cstring> #include <iostream> #include <algorith…

题目链接:http://poj.org/problem?id=3067 题目就是让我们求连线后交点的个数 很容易想到将左端点从小到大排序,如果左端点相同则右端点从小到大排序 那么答案即为逆序对的个数 用树状数组求解逆序对 代码: #include<iostream> #include<cstdlib> #include<cstdio> #include<cstring> #include<algorithm> using namespace st…

<题目链接> 题目大意: 有两个点集,这两个点集从上至下分别从1~n,1~m编号,现在给出n组数据,(x,y),表示左边点集编号为x的点与右边点集编号为y的点相连,现在要求计算这些线段的交点个数. 解题分析: 先将这些线段的x变量从小到大排序,若x相同,再将y从小到大排序.然后就可以直接遍历这些线段了,同时对y变量建一维树状数组,利用sum(m)-sum(node[i].y)可以很容易求出之前插入的所有线段的y值中,有多少线段的y值大于当前插入的y值,这一步相当于对排好序的线段的y值进行逆序数…

vjudge \(Description\) 给定一张\(n\)个点\(m\)条边的无向图,每个点有一个权值.求一条从\(1\)到\(n\)的路径,使得代价最小,输出最小代价. 一条路径的代价定义为,路径上所有点以及和这些点相邻的所有点的权值和. \(n\leq40,\ m\leq\frac{n(n-1)}{2}\). \(Solution\) 容易发现,如果选择从\(u\)走到\(v\),那么一定不会再回到\(u\)的其它相邻节点(不如直接走过去). 这样从点\(u\)爆搜的话,每次移动都会删…

链接:http://poj.org/problem?id=3067 题意:左边有n个城市,右边有m个城市,建k条道路,问有这k条道路中有多少个交点. 分析:将城市按x和y从小到大排序,对于每条道路,求前面有多少个y比当前的y大的,累加起来即可.即求逆序数,可以用树状数组实现. 求逆序数的思路: 可以把数一个个插入到树状数组中, 每插入一个数, 统计小于等于他的数的个数,对应的逆序为 i- sum( data[i] ),其中 i 为当前已经插入的数的个数, sum( data[i] )为比 小于等…

题目大意: 给出一个$d$维矩形,第i维的范围是$[0, l_i]$. 求满足$x_1 + x_2 + ...x_d \leq s$ 的点构成的单纯形体积. $d, l_i \leq 300$ 题解: watashi学长的blog传送门. 给出了求$a_1x_1 + a_2x_2 + ...a_dx_d \leq b $的通用做法.答案就是一个神奇的式子$\frac{1}{n!} * \sum_{I \subseteq S}{(-1)^{|I|}}*max\{0, b - \sum_{i \in…