2015-06-05 问题简述: 有一个 p*q 的棋盘,一个骑士(就是中国象棋里的马)想要走完所有的格子,棋盘横向是 A...Z(其中A开始 p 个),纵向是 1...q. 原题链接:http://acm.tju.edu.cn/toj/showp1702.html 解题思路: DFS:深搜把所有情况都考虑一遍,当骑士走出棋盘或走到原来走过的格子时,旅行失败了:当骑士能一直走下去直到走过的格子数等于 p*q 时,旅行成功. 提交过程中一直有一个问题使这个代码一直WA,最后才发现是 p.q输入反了…

A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 41936   Accepted: 14269 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey ar…

题目链接:http://poj.org/problem?id=2488 A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 36695   Accepted: 12462 Description Background The knight is getting bored of seeing the same black and white squares again and again…

A Knight's Journey Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 35564 Accepted: 12119 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around…

A Knight's Journey Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 51   Accepted Submission(s) : 17 Problem Description Background The knight is getting bored of seeing the same black and white…

A Knight's Journey Time Limit: 1000MSMemory Limit: 65536K Total Submissions: 34633Accepted: 11815 Description BackgroundThe knight is getting bored of seeing the same black and white squares again and again and has decided to make a journeyaround the…

A Knight’s Journey Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 34085 Accepted: 11621 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around…

  A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 24840   Accepted: 8412 Description Background   The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey…

A Knight's Journey Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 66   Accepted Submission(s) : 27 Problem Description Background The knight is getting bored of seeing the same black and white…

迷宫问题(bfs) POJ - 3984   #include <iostream> #include <queue> #include <stack> #include <cstring> using namespace std; /*广度优先搜索*/ /*将每个未访问过的邻接点进队列,然后出队列,知道到达终点*/ typedef class { public: int x; int y; }coordinate; ][]; //迷宫 ][] = { {…

A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 31195   Accepted: 10668 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey ar…

A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 35868   Accepted: 12227 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey ar…

题目链接:http://vjudge.net/contest/view.action?cid=51369#problem/A   (A - Children of the Candy Corn) http://poj.org/problem?id=2488   (A Knight's Journey) (不知道为什么,名字竟然不同哇~~~~还是poj 改名改得好) 题目意思:给出一个p * q 的棋盘,行用阿拉伯数字1,2,...,p-1, p 来表示,列从大写字母'A'开始表示.我这里为了简化…

POJ 2488 -- A Knight's Journey(骑士游历) 题意: 给出一个国际棋盘的大小,判断马能否不重复的走过所有格,并记录下其中按字典序排列的第一种路径. 经典的“骑士游历”问题 输入:第一行,整数n,接下来是n行,每一行为p和q,p为行数,q为列数,p用1...p编号,q用A...Q编号 马的走法:每步棋先横走或直走一格,然后再往外斜走一格;或者先斜走一格,最后再往外横走或竖走一格(即走"日"字).可以越子,没有中国象棋中的"蹩马腿"限制. 解…

A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 35342   Accepted: 12051 Description Background  The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey …

Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 25950   Accepted: 8853 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. When…

Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one direction and one square perpendicular to this. Th…

http://poj.org/problem?id=2488 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one directi…

Description BackgroundThe knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one direction and one square perpendicular…

Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one direction and one square perpendicular to this. Th…

Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 45941   Accepted: 15637 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whe…

Time limit1000 ms Memory limit65536 kB Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one direction a…

描述 Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one direction and one square perpendicular to this.…

Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one direction and one square perpendicular to this. Th…

题目: Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around the world. Whenever a knight moves, it is two squares in one direction and one square perpendicular to this…

poj-2488 题意:一个人要走遍一个不大于8*8的国际棋盘,他只能走日字,要输出一条字典序最小的路径 题解: (1)题目上说的"The knight can start and end on any square of the board.",是个坑点,其实要走字典序最小只需从A1开始遍历就行,因为从任意一点开始,只要能遍历完整个地图,那么A1也可以: (2)要使字典序最小,那么遍历顺序一定要注意 int dr[8]={-1,1,-2,2,-2,2,-1,1};int dc[8]=…

http://poj.org/problem?id=2488 题意 : 给你棋盘大小,判断马能否走完棋盘上所有格子,前提是不走已经走过的格子,然后输出时按照字典序排序的第一种路径 思路 : 这个题吧,有点别扭,再加上要用字典序输出,所以就要用一点小技巧了,自己提前将能输出字典序的那个先写到数组里保存,也就是说,搜索方向要进行特殊的排列,而这样的话,只要每次找的时候从第0行第0列开始找,第一个成功走完所有的格子一定是按字典序排列的,因为只要能走完所有的格子,而字典序最小的就是左上角那个格子,所以,…

题目:http://poj.org/problem?id=2488 题意: 给出一个国际棋盘的大小,判断马能否不重复的走过所有格,并记录下其中按字典序排列的第一种路径. #include <iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<stack> #include<queue> #include<iomanip> #incl…

题意:给一个n×m的棋盘,如果一个骑士可以从任意一个位置出发不重复的走遍棋盘的每个格子就输出字典序最短的路径. 解法:dfs.暴搜n×m次,只是被字典序输出坑了……而且字母是列序号数字是行序号……这两个总弄反……搜索的时候会只要按字典序搜那8个方向就可以了,搜到第一条满足条件的路径就结束. 代码: #include<stdio.h> #include<iostream> #include<algorithm> #include<string> #includ…

poj2488:http://poj.org/problem?id=2488 题意:给你一张地图,然后有一个骑士,骑士可以从地图的任意一个方格开始,作为起点,问你该骑士能否走遍整张题图.题解:首先想到就是DFS,但是要对每个点进行一次DFS,时间复杂度估计hold不住,后来一想,有些点,不必搜索.因为已经收过,所以可以采取记忆化搜索.但是这一题的难点不是这里,在于所谓的字典序输出,一开始不知道这里的字典序是指什么.后来才知道,就是找字母小的,字母相同就找数字小的,这样一来搜索到额顺序就确定了.…