Recursive sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1525    Accepted Submission(s): 710 Problem Description Farmer John likes to play mathematics games with his N cows. Recently,…

M - Meeting Time Limit:6000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit cid=113817#status//M/0" class="ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only" style="display:inline-block;pad…

铜铜铜…… 人呐真奇怪 铁牌水平总想着运气好拿个铜 铜牌水平总想着运气好拿个银 估计银牌的聚聚们一定也不满意 想拿个金吧 这次比赛挺不爽的 AB两道SB题,十分钟基本全场都过了 不知道出这种题有什么意思,而且还是两道 C是一道矩阵快速幂 不算难可是还是卡了很久 还好是1A E是一道搜索题,也是简单题 呵呵 可能是区域赛的问题 大家都不敢随便写吧 后来我们暴力过了的时候都觉得自己好SB 那个时候都快封榜了 怎么这么蠢呐 然后看的H题,其他题做出来的都很少,没怎么想 H题 哎 我们想了好久才想明白样…

题面看这里 \(PS\):符号 \([\ \rm P\ ]\) 的意义是:当表达式 \(\rm P\) 为真则取值为 \(1\),为假则取值为 \(0\). 题目大意 给你一个一天有 \(H\)​​​​​​​ 小时.一小时有 \(M\)​​​​​​​​ 分钟的表和一个正整数 \(A\)​,问一天内有多少个整数时刻,使得分针与时针的夹角小于等于 \(\displaystyle\frac{2\pi A}{HM}\)​. 题目分析 易知分针转速 \(w_1=\displaystyle \frac{2\…

Recursive sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 249    Accepted Submission(s): 140 Problem Description Farmer John likes to play mathematics games with his N cows. Recently, t…

Counting Cliques Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 539    Accepted Submission(s): 204 Problem Description A clique is a complete graph, in which there is an edge between every pair…

Thickest Burger Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 63    Accepted Submission(s): 60 Problem Description ACM ICPC is launching a thick burger. The thickness (or the height) of a piec…

Relative atomic mass Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 66    Accepted Submission(s): 59 Problem Description Relative atomic mass is a dimensionless physical quantity, the ratio of…

Rabbits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1193    Accepted Submission(s): 628 Problem Description Here N (N ≥ 3) rabbits are playing by the river. They are playing on a number li…

整理代码... Little Boxes Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 2304    Accepted Submission(s): 818 Problem Description Little boxes on the hillside.Little boxes made of ticky-tacky.Littl…

今天做的沈阳站重现赛,自己还是太水,只做出两道签到题,另外两道看懂题意了,但是也没能做出来. 1. Thickest Burger Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 0    Accepted Submission(s): 0 Problem Description ACM ICPC is launching a thic…

Pagodas Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1282    Accepted Submission(s): 902 Problem Description n pagodas were standing erect in Hong Jue Si between the Niushou Mountain and the…

Bazinga Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 3509    Accepted Submission(s): 1122 Problem Description Ladies and gentlemen, please sit up straight.Don't tilt your head. I'm serious.Fo…

Bazinga Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 214    Accepted Submission(s): 89 Problem Description Ladies and gentlemen, please sit up straight.Don't tilt your head. I'm serious.For n…

Pagodas Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 70    Accepted Submission(s): 62 Problem Description n pagodas were standing erect in Hong Jue Si between the Niushou Mountain and the Yun…

HDU 3397 Sequence operation 题目链接 题意:给定一个01序列,有5种操作 0 a b [a.b]区间置为0 1 a b [a,b]区间置为1 2 a b [a,b]区间0变成1,1变成0 3 a b 查询[a,b]区间1的个数 4 a b 查询[a,b]区间连续1最长的长度 思路:线段树线段合并.须要两个延迟标记一个置为01,一个翻转,然后因为4操作,须要记录左边最长0.1.右边最长0.1,区间最长0.1,然后区间合并去搞就可以 代码: #include <cstdi…

2018 ICPC 沈阳网络赛 Call of Accepted 题目描述:求一个算式的最大值与最小值. solution 按普通算式计算方法做,只不过要同时记住最大值和最小值而已. Convex Hull 题目描述:定义函数\(gay(x)\),若\(x\)是某个非\(1\)的数的平方的倍数,则\(gay(x)=0\),否则\(gay(x)=x^2\),求\(\sum_{num=1}^{n} ( \sum_{i=1}^{num} gay(x) ) mod p\) solution \[\sum…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5950 Farmer John likes to play mathematics games with his N cows. Recently, they are attracted by recursive sequences. In each turn, the cows would stand in a line, while John writes two positive numbers…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5954 Problem DescriptionYou have got a cylindrical cup. Its bottom diameter is 2 units and its height is 2 units as well.The height of liquid level in the cup is d (0 ≤ d ≤ 2). When you incline the cup t…

题目链接:传送门 题目: Recursive sequence Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description Farmer John likes to play mathematics games with his N cows. Recently, they are attracted…

http://acm.hdu.edu.cn/showproblem.php?pid=5955 题意:给你长度为l的n组数,每个数1-6,每次扔色子,问你每个串第一次被匹配的概率是多少 题解:先建成ac自动机构造fail数组,然后因为fail指针可能向前转移所以不能不能直接递推dp,需要高斯消元解方程,对于节点i,假设不是结束点而且能转移到它的点有a1,a2...an,那么dp[i]=1/6*dp[a1]+1/6*dp[a2]+...+1/6*a[n],然后我们可以列出n个方程,高斯消元然后找到每…

废话: 这道题很是花了我一番功夫.首先,我不会kmp算法,还专门学了一下这个算法.其次,即使会用kmp,但是如果暴力枚举的话,还是毫无疑问会爆掉.因此在dfs的基础上加上两次剪枝解决了这道题. 题意: 我没有读题,只是队友给我解释了题意,然后我根据题意写的题. 大概意思是给n个字符串,从上到下依次标记为1——n,寻找一个标记最大的串,要求这个串满足:标记比它小的串中至少有一个不是它的子串. 输入: 第一行输入一个整型t,表示共有t组数据. 每组数据首行一个整型n,表示有n个串. 接下来n行,每行…

题意:给定上一棵树,然后每条边有一个权值,然后每个点到 1 的距离有两种,第一种是直接回到1,花费是 dist(1, i)^2,还有另一种是先到另一个点 j,然后两从 j 向1走,当然 j 也可以再向 k,一直到1,但经过一个点,那么就会出多一个花费 p,问你每个点到 1 的最小距离的最大值是多少. 题解:dp[i]代表从1节点出发,向下传递到i节点的最小花费,dp[i]=min(dp[j]+dis[i]-dis[j])^2,j是从i到1链上的每一个点,很明显的斜率优化,dis[i]是i到根节点…

题目 Farmer John likes to play mathematics games with his N cows. Recently, they are attracted by recursive sequences. In each turn, the cows would stand in a line, while John writes two positive numbers a and b on a blackboard. And then, the cows woul…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=5558 Problem Description Alice wants to send a classified message to Bob. She tries to encrypt the message with her original encryption method. The message is a string S, which consists of Nlowercase let…

C.Recursive sequence 求ans(x),ans(1)=a,ans(2)=b,ans(n)=ans(n-2)*2+ans(n-1)+n^4 如果直接就去解...很难,毕竟不是那种可以直接化成矩阵的格式,我们也因为这个被卡很长时间 事实上可以把这道式子化成几个基本元素的格式,然后就容易组合了,比如ans(n-2)*2+ans(n-1)+(n-1)^4+4*(n-1)^3+6*(n-1)^2+4*(n-1)^1+1 包含了所有的基本组成形式,化绝对为相对,并且除了一个n-2其他都是n…

链接:传送门 A - Thickest Burger - [签到水题] ACM ICPC is launching a thick burger. The thickness (or the height) of a piece of club steak is A (1 ≤ A ≤ 100). The thickness (or the height) of a piece of chicken steak is B (1 ≤ B ≤ 100). The chef allows to add…

HDU 6225 Little Boxes 题意 计算四个整数的和 解题思路 使用Java大整数 import java.math.BigInteger; import java.util.Scanner; /** * * @author reqaw */ public class Main { /** * @param args the command line arguments */ public static void main(String[] args) { Scanner in =…

HDU 6222 Heron and His Triangle 链接:http://acm.hdu.edu.cn/showproblem.php?pid=6222 思路: 打表找规律+大数运算 首先我们可以打个表暴力跑出前几个满足题意的T 打表代码: #include<bits/stdc++.h> using namespace std; bool fun(double n) { if(abs(round(n) - n) < 0.000000000000001) ; ; } int ma…

A - Thickest Burger 水. #include <bits/stdc++.h> using namespace std; int t; int a, b; int main() { scanf("%d" ,&t); while (t--) { scanf("%d%d", &a, &b); if (a > b) swap(a, b); printf(); } ; } B - Relative atomic ma…