Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. /** * Definition for a point. * struct Point { * int x; * int y; * Point() : x(0), y(0) {} * Point(int a, int b) : x(a), y(b) {} * }; */ class Solutio…
/** * Definition for a point. * struct Point { * int x; * int y; * Point() : x(0), y(0) {} * Point(int a, int b) : x(a), y(b) {} * }; */ class Solution { public: /** * @param points an array of point * @return an integer */ int maxPoints(vector<Point…
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. Example 1: Input: [[1,1],[2,2],[3,3]] Output: 3 Explanation: ^ | | o | o | o +-------------> 0 1 2 3 4 Example 2: Input: [[1,1],[3,2]…
给定一个二维平面,平面上有 n 个点,求最多有多少个点在同一条直线上. 示例 1: 输入: [[1,1],[2,2],[3,3]] 输出: 3 解释: ^ | | o | o | o +-------------> 0 1 2 3 4 示例 2: 输入: [[1,1],[3,2],[5,3],[4,1],[2,3],[1,4]] 输出: 4 解释: ^ | | o | o o | o | o o +------------------…
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. Have you met this question in a real interview? Example Given 4 points: (1,2), (3,6), (0,0), (1,3). The maximum number is 3. LeetCode上的原题,请参见我之前的博…
原题地址:https://oj.leetcode.com/problems/max-points-on-a-line/ 题意:Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 解题思路:找到平面上在一条直线上最多的点.点在同一条直线上意味着这些点的斜率是一样的,那么可以考虑使用哈希表来解决,{斜率:[点1,点2]}这样的映射关系.这里有几个需要考虑…
Max Points on a Line 题目描述: Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 解题思路: 1.首先由这么一个O(n^3)的方法,也就是算出每条线的方程(n^2),然后判断有多少点在每条线上(N).这个方法肯定是可行的,只是复杂度太高2.然后想到一个O(N)的,对每一个点,分别计算这个点和其他所有点构成的斜率,具有相同斜率最…
Max Points on a Line Submission Details 27 / 27 test cases passed. Status: Accepted Runtime: 472 ms Submitted: 0 minutes ago Submitted Code Language: java Edit Code /** * Definition for a point. * class Point { * int x; * int y; * Point() {…
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 思路: 自己脑子当机了,总是想着斜率和截距都要相同.但实际上三个点是一条直线的话只要它们的斜率相同就可以了,因为用了相同的参照点,截距一定是相同的. 大神的做法: 对每一个点a, 找出所有其他点跟a的连线斜率,相同为同一条线,记录下通过a的点的线上最大的点数. 找出每一个点的最大连线通过的点数. 其…
