Numbers Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5522 Description 给n个数A1,A2....An{A}_{1},{A}_{2}....{A}_{n}A​1​​,A​2​​....A​n​​,从中选3个位置不同的数A,B和C,问是否有一种情况满足A-B=C. Input There are multiple test cases, no mo…

水题 #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespace std; ]; int n; ]; int main() { while(~scanf("%d",&n)){ memset(tot,,sizeof tot); ;i<=n;i++) { scanf("%d",&a[i])…

/* HDU 6168 - Numbers [ 思维 ] | 2017 ZJUT Multi-University Training 9 题意: .... 分析: 全放入multiset 从小到大,慢慢筛 */ #include <bits/stdc++.h> using namespace std; const int N = 125250; int n, s[N]; int a[N], cnt; multiset<int> st; multiset<int>::it…

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题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5522 水题:暴力过 #include<stdio.h> #include<string.h> #include<algorithm> #include<queue> #define MAX 10010 using namespace std; int main() { int n,m,j,i; int s[MAX]; int vis[MAX]; while(sc…

GCD/center> 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5726 Description Give you a sequence of N(N≤100,000) integers : a1,...,an(0<ai≤1000,000,000). There are Q(Q≤100,000) queries. For each query l,r you have to calculate gcd(al,,al+1,...,ar) a…

Bazinga Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5510 Description Ladies and gentlemen, please sit up straight. Don't tilt your head. I'm serious.For n given strings S1,S2,⋯,Sn, labelled from 1 to n, you…

题目链接:hdu 5077 NAND 题目大意:Xiaoqiang要写一个编码程序,然后依据x1,x2,x3的值构造出8个字符.如今给定要求生成的8个字符.问 说Xiaoqiang最少要写多少行代码.代码内容仅仅能为NAND操作和return操作,操作的变量能够是常数. 解题思路:输入总共就256中情况,所以暴力剪枝打表,打表的代码手贱给删了...所以就将一下思路.开一个s数组 表示变量,然后相应每一层每次两个变量进行NAND操作. 大致三个剪枝,dfs时候,变量出现同样就跳过.8个字符能够直接…

C. Really Big Numbers time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4291 思路:首先保留求出循环节,然后就是矩阵求幂了. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef __int64 ll; #define MOD2 1000000007 #define MOD1 222…

Avin is studying series. A series is called "wave" if the following conditions are satisfied: 1) It contains at least two elements; 2) All elements at odd positions are the same; 3) All elements at even positions are the same; 4) Elements at odd…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5585 思路:对于2和5只须看最后一位数,对于三看所有位的数字之和就行 #include<stdio.h> #include<math.h> #include<stdlib.h> #include<string.h> #include<iterator> #include<iostream> #include<algorithm>…

Numbers Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 460    Accepted Submission(s): 283 Problem Description There is a number N.You should output "YES" if N is a multiple of 2, 3 or 5,ot…

因为题目当中的k比较小k <= 10,所以可以直接枚举,题目里面由两个trick, 一个是如果每个点都可以放稻草人的话,那么答案是0, 另外一个就是如果可以放稻草人的点不用被照到.知道了这两个基本上暴力既可以ac了 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; ; struct Point { int…

题目链接:hdu 4499 Cannon 题目大意:给出一个n*m的棋盘,上面已经存在了k个棋子,给出棋子的位置,然后求能够在这种棋盘上放多少个炮,要求后放置上去的炮相互之间不能攻击. 解题思路:枚举行放的情况,用二进制数表示,每次放之前推断能否放下(会不会和已经存在的棋子冲突),放下后推断会不会互相攻击的炮,仅仅须要对每一个新加入的炮考虑左边以及上边就能够了. #include <cstdio> #include <cstring> #include <algorithm&…

USACO ORZ Time Limit: 5000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2291    Accepted Submission(s): 822 Problem Description Like everyone, cows enjoy variety. Their current fancy is new shapes for pastur…

题目:Click here 题意:给你n个点,有多少个正多边形(3,4,5,6). 分析:整点是不能构成正五边形和正三边形和正六边形的,所以只需暴力枚举四个点判断是否是正四边形即可. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #define power(x) ((x)*(x)) using names…

odds Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 250    Accepted Submission(s): 72 Problem Description 度度熊有一棵 N 个节点 (node) 的有根树 (rooted tree),树上的每条边 (edge) 都有一个整数的权重,对于每一个非叶的节点 (non-leaf n…

http://acm.hdu.edu.cn/showproblem.php?pid=5181 题意: 有一个栈,其中有n个数1~n按顺序依次进入栈顶,在某个时刻弹出. 其中m个限制,形如数字A必须在数字B之前弹出. 求方案总数   dp[i][j]表示数字i~j的出栈方案数 枚举最后一个出栈的数k,若k合法 dp[i][j]+=dp[i][k]*dp[k+1][j] 如何判断k是否合法?   对于一组i,j,k来说,它的弹出顺序是 [i,k-1]早于[k+1,j]早于k 对于一个限制 A必须在B…

Numbers Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 514    Accepted Submission(s): 270 Problem Description zk has n numbers a1,a2,...,an. For each (i,j) satisfying 1≤i<j≤n, zk generates a…

为甚么16年Qingdao Online 都是暴力题emm///... 先暴力预处理 然后lower _bound二分 #include <iostream> #include <cstdio> #include <sstream> #include <cstring> #include <map> #include <cctype> #include <set> #include <vector> #incl…

题目链接 Problem Description zk has n numbers a1,a2,...,an. For each (i,j) satisfying 1≤i<j≤n, zk generates a new number (ai+aj). These new numbers could make up a new sequence b1,b2,...,bn(n−1)/2. LsF wants to make some trouble. While zk is sleeping, Ls…

Problem Description A number whose only prime factors are 2,3,5 or 7 is called a humble number. The sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 24, 25, 27, ... shows the first 20 humble numbers. Write a program to find and pri…

C. Hexadecimal's Numbers time limit per test 1 second memory limit per test 64 megabytes input standard input output standard output One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the me…

面试n个人,可以分任意组数,每组选一个,得分总和严格大于k,问最少分几组 就是暴力嘛...想到就去写吧.. #include <iostream> #include <cstdio> #include <sstream> #include <cstring> #include <map> #include <set> #include <vector> #include <stack> #include <…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=2089 不要62 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 54847    Accepted Submission(s): 21063 Problem Description 杭州人称那些傻乎乎粘嗒嗒的人为62(音:laoer).杭州交…

Chip Factory Time Limit: 18000/9000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 5394    Accepted Submission(s): 2422 Problem Description John is a manager of a CPU chip factory, the factory produces lots of chi…

TIANKENG manages a restaurant after graduating from ZCMU, and tens of thousands of customers come to have meal because of its delicious dishes. Today n groups of customers come to enjoy their meal, and there are Xi persons in the ith group in sum. As…

先来看看比较显然的几个局面 (a,0) 先手必败 (a,a) 先手必胜 (a,ak) 先手必胜 (a,ak+r),k>1 先手必胜,因为先手有主动权把(a,r)让给后手或留给自己 对于开局(a,r),r<a&&a/r<2,比较难分析,我们用暴力直接跑出结果 挑战程序设计竞赛把这种主动权成为自由度,名字真高端 这次的代码写的不怎么简练,不过能AC #include<iostream> #include<algorithm> #include<c…

Shopping Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 758    Accepted Submission(s): 254 Problem Description You have just moved into a new apartment and have a long list of items you need t…