这个问题叫做质因子分解,花了大概两个小时写对了.这道题细节挺多的,书上提到了几点,一个是n=1的话需要特判.有一个很容易错的点就是n一开始要先用一个变量保存起来,不保存的话后面有点麻烦,所以建议还是先保存起来.因为过程中要不断的改变n,最后还要打印出n,如果n为1的话还要特殊处理.当然也可以一开始处理打印,不过我觉得和思维颠倒有些难受.一个很重要的问题就是打印的素数表需要多大,这个我也不清楚怎么办,所以先写出来看,随机应变,如果不能完全覆盖的话再往上加,最后完全覆盖了那个样例.最后解决的细节是当…

7.7 Design an algorithm to find the kth number such that the only prime factors are 3,5, and 7. 这道题跟之前LeetCode的那道Ugly Number II 丑陋数之二基本没有啥区别,具体讲解可参见那篇,代码如下: class Solution { public: int getKthMagicNumber(int k) { vector<, ); , i5 = , i7 = ; while (re…

时间限制 50 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HE, Qinming Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1^k1* p2^k2 *…*pm^km. Input Specification: Each input file contain…

题目链接 http://www.patest.cn/contests/pat-a-practise/1059 Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1^k1 * p2^k2 *…*pm^km. Input Specification: Each input file contains one test ca…

问题 L: Prime Factors 时间限制: 1 Sec  内存限制: 128 MB [提交][状态][论坛] 题目描写叙述 I'll give you a number , please tell me how many different prime factors in this number. 输入 There is multiple test cases , in each test case there is only one line contains a number N(…

1059. Prime Factors (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HE, Qinming Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1^k1 * p2^k2 *-*pm^km. Input Specificati…

Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1^k1 * p2^k2 *…*pm^km. Input Specification: Each input file contains one test case which gives a positive integer N in the range of lon…

https://pintia.cn/problem-sets/994805342720868352/problems/994805415005503488 Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p​1​​​k​1​​​​×p​2​​​k​2​​​​×⋯×p​m​​​k​m​​​​. Input Specifi…

1059 Prime Factors (25 分) Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p​1​​​k​1​​​​×p​2​​​k​2​​​​×⋯×p​m​​​k​m​​​​. Input Specification: Each input file contains one test case which…

1059. Prime Factors (25) 时间限制 50 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HE, Qinming Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1^k1 * p2^k2 *…*pm^km. Input Specificatio…

题目链接:1332: Prime Factors Description I'll give you a number , please tell me how many different prime factors in this number. Input There is multiple test cases , in each test case there is only one line contains a number N(2<=N<=100000). Process to…

Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p​1​​​k​1​​​​×p​2​​​k​2​​​​×⋯×p​m​​​k​m​​​​. Input Specification: Each input file contains one test case which gives a positive integer …

1059 Prime Factors (25 分)   Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p​1​​​k​1​​​​×p​2​​​k​2​​​​×⋯×p​m​​​k​m​​​​. Input Specification: Each input file contains one test case whi…

Source: PAT A1059 Prime Factors (25 分) Description: Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p​1​​​k​1​​​​×p​2​​​k​2​​​​×⋯×p​m​​​k​m​​​​. Input Specification: Each input file co…

Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p​1​​​k​1​​​​×p​2​​​k​2​​​​×⋯×p​m​​​k​m​​​​. Input Specification: Each input file contains one test case which gives a positive integer …

1059 Prime Factors (25分) 1. 题目 2. 思路 先求解出int范围内的所有素数,把输入x分别对素数表中素数取余,判断是否为0,如果为0继续除该素数知道余数不是0,遍历到sqrt(x)就够了 3. 注意点 输入数为1的情况, 输出1=1 4. 代码 #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespace std; #d…

题目 Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1^k1 * p2^k2 -pm^km. Input Specification: Each input file contains one test case which gives a positive integer N in the range of lo…

1059. Prime Factors Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p1^k1 * p2^k2 *-*pm^km. Input Specification: Each input file contains one test case which gives a positive integer N…

用素数筛选法即可. 范围long int,其实大小范围和int一样,一开始以为是指long long,想这就麻烦了该怎么弄. 而现在其实就是int的范围,那难度档次就不一样了,瞬间变成水题一枚,因为int根号后大小不超过60000. 即因子的大小不会超过60000,除非本身是质数. int 4 -2147438648-+2147438647long int 4 -2147438648-+2141438647 #include <iostream> #include <cstdio>…

题意: 给出一个int型正整数N,要求把N分解成若干个质因子,如N=97532468,则把N分解成:97532468=2^2*11*17*101*1291.质因子按增序输出,如果某个质因子的幂是1,则1不输出. 思路:质因子分解的基础题. 首先,定义如下因子的结构体,用于存放最终的结果.因为N是一个int范围的正整数,由于2*3*5*7*11*13*17*19*23*29>INT_MAX,也就是说,任意一个int型整数,可分解出来的不同的质因子的个数不会超过10个,因此,数组只要开到10就够了.…

素因子分解. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<string> #include<stack> #include<vector> using namespace st…

反正知道了就是知道,不知道也想不到,很快 #include <cstdio> #include <cstdlib> #include <vector> using namespace std; inline void print_prime_k(long long p, long long k) { printf("%lld", p); ) { printf("^%lld", k); } } int main() { long l…

题意: 输入一个正整数N(范围为long int),输出它等于哪些质数的乘积. trick: 如果N为1,直接输出1即可,数据点3存在这样的数据. 如果N本身是一个质数,直接输出它等于自己即可,数据点4存在这样的数据. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; int main(){ ios::sync_with_stdio(false); ci…

题目链接: 传送门 Prime Land Time Limit: 1000MS     Memory Limit: 10000K Description Everybody in the Prime Land is using a prime base number system. In this system, each positive integer x is represented as follows: Let {pi}i=0,1,2,... denote the increasing…

Design an algorithm to find the kth number such that the only prime factors are 3, 5, and 7. The eligible numbers are like 3, 5, 7, 9, 15 ... Example If k=4, return 9. Challenge O(n log n) or O(n) time Analysis: This is the Humble number problem (丑数问…

Prime Land Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 3211   Accepted: 1473 Description Everybody in the Prime Land is using a prime base number system. In this system, each positive integer x is represented as follows: Let {pi}i=0,…

1. 问题: The prime factors of 13195 are 5, 7, 13 and 29.What is the largest prime factor of the number 600851475143 ? 2. 解法(by java in Eclipse) package com.lun.alrithmetic; /* * Q1: what's the primary factor? (1 2 3) * Q2: i & i+2ne能否遍历出所有质数 */ public…

The first two consecutive numbers to have two distinct prime factors are: 14 = 2 × 7 15 = 3 × 5 The first three consecutive numbers to have three distinct prime factors are: 644 = 2² × 7 × 23 645 = 3 × 5 × 43 646 = 2 × 17 × 19. Find the first four co…

The first two consecutive numbers to have two distinct prime factors are: 14 = 2  7 15 = 3  5 The first three consecutive numbers to have three distinct prime factors are: 644 = 2²  7  23 645 = 3  5  43 646 = 2  17  19. Find the first four consecutiv…

The prime factors of 13195 are 5, 7, 13 and 29. What is the largest prime factor of the number 600851475143 ? #include<stdio.h> #include<string.h> #include<math.h> #include<ctype.h> #include<stdlib.h> #include<stdbool.h>…