POJ 1861 Network (模版kruskal算法)】的更多相关文章

Network Time Limit: 1000MS Memory Limit: 30000K Total Submissions: Accepted: Special Judge Description Andrew is working as system administrator and is planning to establish a new network in his company. There will be N hubs in the company, they can…
题目连接:problemId=542" target="_blank">ZOJ 1542 POJ 1861 Network 网络 Network Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge Andrew is working as system administrator and is planning to establish a new network in his com…
Network Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 14021   Accepted: 5484   Special Judge Description Andrew is working as system administrator and is planning to establish a new network in his company. There will be N hubs in the c…
题目: In the planet w-503 of galaxy cgb, there is a kind of intelligent creature named QS. QScommunicate with each other via networks. If two QS want to get connected, they need to buy two network adapters (one for each QS) and a segment of network cab…
Network Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 15268   Accepted: 5987   Special Judge Description Andrew is working as system administrator and is planning to establish a new network in his company. There will be N hubs in the c…
题意:有n个点,部分点之间可以连接无向边,每条可以连接的边都有一个权值.求一种连接方法将这些点连接成一个连通图,且所有连接了的边中权值最大的边权值最小. 解法:水题,直接用Kruskal算法做一遍就行了,不过还是应该仔细想想为什么Kruskal可行.原因是,在从小边往大边遍历的过程中(一直保持图为连通图),若判定某边i必须被连接,则因为图是连通图,所以连接比它小的边不可能使边i不需要连接,所以,要使边i不需要连接,必须连接比它大的边,根据题目要求,还是连接边i情况更优. tag:最小生成树 /*…
题意:给出n个村庄之间的距离,再给出已经连通起来了的村庄.求把所有的村庄都连通要修路的长度的最小值. 思路:Kruskal算法 课本代码: //Kruskal算法 #include<iostream> using namespace std; int fa[120]; int get_father(int x){ return fa[x]=fa[x]==x?x:get_father(fa[x]);//判断两个节点是否属于一颗子树(并查集) } int main(){ int n; int p[…
Constructing Roads Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 19884   Accepted: 8315 Description There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each…
Network Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 14103   Accepted: 5528   Special Judge Description Andrew is working as system administrator and is planning to establish a new network in his company. There will be N hubs in the c…
题意:求解最小生成树,以及最小瓶颈生成树上的瓶颈边. 思路:只是求最小生成树即可.瓶颈边就是生成树上权值最大的那条边. //#include <bits/stdc++.h> #include <cstdio> #include <vector> #include <iostream> #include <algorithm> #define INF 0x7f7f7f7f #define pii pair<int,int> #defin…