198. House Robber Total Accepted: 45873 Total Submissions: 142855 Difficulty: Easy You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing ea…

House Robber:不能相邻,求能获得的最大值 House Robber II:不能相邻且第一个和最后一个不能同时取,求能获得的最大值 House Robber III:二叉树下的不能相邻,求能获得的最大值 Paint House:用3种颜色,相邻的房屋不能用同一种颜色,求花费最小 Paint House II:用k种颜色,相邻的房屋不能用同一种颜色,求花费最小Paint Fence:用k种颜色,相邻的可以用同一种颜色,但不能超过连续的2个,求有多少种可能性 198. House Robb…

House Robber II Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arrang…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house is the neighbor of the last one. Meanwhile, adjacent…

Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle. …

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/house-robber-ii/description/ 题目描述: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All h…

House Robber II You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house is the neighbor of the last one. Mean…

Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle.…

题目: Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circ…

Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle. …

URL: https://leetcode.com/problems/house-robber-ii/ You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house i…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house is the neighbor of the last one. Meanwhile, adjacent…

［抄题］: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house is the neighbor of the last one. Meanwhile, adj…

原题链接 比子母题House Robber多了一个条件:偷了0以后,第n-1间房子不能偷. 转换思路为求偷盗[0,n-1)之间,以及[1,n)之间的最大值. 用两个DP,分别保存偷不偷第0间房的情况. Runtime: 0 ms, faster than 100.00% class Solution { public: int rob(vector<int> &nums) { ; int len = nums.size(); ) return res; ) ]; ) ] > nu…

注意事项: 这是 打家劫舍 的延伸.在上次盗窃完一条街道之后,窃贼又转到了一个新的地方,这样他就不会引起太多注意.这一次,这个地方的所有房屋都围成一圈.这意味着第一个房子是最后一个是紧挨着的.同时,这些房屋的安全系统与上次那条街道的安全系统保持一致.给出一份代表每个房屋存放钱数的非负整数列表,确定你可以在不触动警报的情况下盗取的最高金额. 详见:https://leetcode.com/problems/house-robber-ii/description/ Java实现: class Sol…

你是一个专业的小偷,计划偷窃沿街的房屋,每间房内都藏有一定的现金.这个地方所有的房屋都围成一圈,这意味着第一个房屋和最后一个房屋是紧挨着的.同时,相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额. 示例 1: 输入: [2,3,2] 输出: 3 解释: 你不能先偷窃 1 号房屋(金额 = 2),然后偷窃 3 号房屋(金额 = 2), 因为他们是相邻的. 示例…

由于之前对算法题接触不多,因此暂时只做easy和medium难度的题. 看完了<算法(第四版)>后重新开始刷LeetCode了,这次决定按topic来刷题,有一个大致的方向.有些题不止包含在一个topic中,就以我自己做的先后顺序为准了. Array ---11.Container With Most Water 给定许多条与y轴平行的直线,求其中两条直线与x轴围成的容器的最大容量. 这道题用到了双指针的思想.我们在数轴的两端分别放置一个left指针和right指针,因为容器容量=较短边*两边…

1. Array 基础 27 Remove Element 26 Remove Duplicates from Sorted Array 80 Remove Duplicates from Sorted Array II 277 Find the Celebrity 189 Rotate Array 41 First Missing Positive 299 Bulls and Cows 134 Gas Station 118 Pascal's Triangle 很少考 119 Pascal's…

Hello everyone, I am a Chinese noob programmer. I have practiced questions on leetcode.com for 2 years. During this time, I studied a lot from many Great Gods' articles. After worship, I always wanted to write an article as they did, and now I take t…

198. House Robber You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected…

213. House Robber II     Total Accepted: 24216 Total Submissions: 80632 Difficulty: Medium Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

要求 你是一个小偷,每个房子中有价值不同的宝物,但若偷连续的两栋房子,就会触发报警系统,求最多可偷价值多少的宝物 示例 [3,4,1,2],返回6[3,(4),1,(2)] [4,3,1,2],返回6[(4),3,1,(2)] 实现 暴力解法:检查所有房子的组合,对每个组合检查是否有相邻房子,若没有则记录其价值,找最大值((2^n)*n) 递归 记忆化搜索 1 class Solution { 2 private: 3 // memo[i] 表示抢劫nums[i...n)所能获得的最大收益 4…

2018-04-29 20:20:56 House Robber问题是leetcode上经典的系列题,这里对其中的题目做一个讲解. 198. House Robber 问题描述: 问题求解: 本质上就是求解不连续取数的情况下能获得最大价值.可以使用动态规划来解决. dp[i][0]:第i个数没有取能获得的最高价值 dp[i][1]:第i个数取能获得的最高价值 初始值:dp[-1][0] = 0,dp[-1][1] = -INF 递推关系式:dp[i][0] = max(dp[i - 1][0],…

The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all hou…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

198.HouseRobber You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected a…

打家劫舍 题目描述 你是一个专业的小偷,计划偷窃沿街的房屋.每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额. 示例 1: 输入: [1,2,3,1] 输出: 4 解释: 偷窃 1 号房屋 (金额 = 1) ,然后偷窃 3 号房屋 (金额 = 3).   偷窃到的最高金额 = 1 + 3 = 4 . 示例…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

LinkedIn(39) 1 Two Sum 23.0% Easy 21 Merge Two Sorted Lists 35.4% Easy 23 Merge k Sorted Lists 23.3% Hard 33 Search in Rotated Sorted Array 30.2% Hard 34 Search for a Range 29.1% Medium 46 Permutations 35.7% Medium 47 Permutations II 28.0% Medium 50…