问题:求一个字符串中最长不重复子串的长度. 直接思路:以每个字符为出发计算最长不重复子串.TLE.O(n2),HashMap存储字符出现的位置. 代码: public int lengthOfLongestSubstring(String s) { Map<Character , Integer> temp = new HashMap<Character , Integer>(); int len = s.length(); int tempLen = 0,maxLen = 0;…
LeetCode 3_Longest Substring Without Repeating Characters 题目描写叙述: Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc&quo…
Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst…
July 16, 2015 Problem statement: Longest Substring Without Repeating Characters Read the blog: http://blog.csdn.net/fightforyourdream/article/details/17860983 这算法写了很多次, 时间太长, 半年前, 有一次写了二个小时, 写不下去, 想法不好, 没有办法收场; 接着, 又写了四天, 每天二小时, 把上次代码拿出来看, 有什么问题, 改写.…
Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output: 1 Explana…
要开学了,不开森.键盘声音有点大,担心会吵到舍友.今年要当个可爱的技术宅呀~ 题目:Given a string, find the length of the longest substring without repeating characters. Examples:  Given "abcabcbb", the answer is "abc", which the length is 3. 第一反应的解法,直接贴代码吧,38ms的运行时间,击败58%. c…
Longest Substring Without Repeating Characters: Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the length is 3. Given "bbbbb", the…
最长无重复字符的子串 Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output…
题目链接 Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest…
题目: Given a . For . 解题思路: 这个题让找一个字符串中具有不重复单词的最长子串的长度,如:ababc,子串为abc,长度为3.有这么几个方法: 方法一: 依赖字符串本身的一些特有函数,进行相应操作来完成.我们可以维护一个子串,来保存最长的无重复的子串,并记录当前子串的长度,如果遇到重复的字符,则去掉子串中重复的字符,一次进行下去,最终就能找到最长无重复子串.如str = ababc, substr = a, ab, ba, ab, abc....类似这样的思路.如下代码: /…