题目链接:http://codeforces.com/contest/600/problem/C C. Make Palindrome time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A string is called palindrome if it reads the same from left to right an…
C. Make Palindrome Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/600/problem/C Description A string is called palindrome if it reads the same from left to right and from right to left. For example "kazak", "oo&q…
Given a string S, you are allowed to convert it to a palindrome by adding characters in front of it. Find and return the shortest palindrome you can find by performing this transformation. For example: Given "aacecaaa", return "aaacecaaa&qu…
题目: 有效回文串 给定一个字符串,判断其是否为一个回文串.只包含字母和数字,忽略大小写. 样例 "A man, a plan, a canal: Panama" 是一个回文. "race a car" 不是一个回文. 注意 你是否考虑过,字符串有可能是空字符串?这是面试过程中,面试官常常会问的问题. 在这个题目中,我们将空字符串判定为有效回文. 挑战 O(n) 时间复杂度,且不占用额外空间. 解题: 去除非有效字符后,整体是个回文串,两边查找,利用快速排序的思想,…
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. Note: For the purpose of this problem, we define empty string as valid palindrome. Example 1: Input: "A man, a plan, a canal: Panama" O…
Given a string s, you are allowed to convert it to a palindrome by adding characters in front of it. Find and return the shortest palindrome you can find by performing this transformation. Example 1: Input: "aacecaaa" Output: "aaacecaaa&quo…
这道题目我用了一上午才做出来,还是看的别人的思路,尽管没有看代码做的有点慢.代码能力还是得加强啊.思维 得缜密.不能想当然,要有根据,写上的代码要有精确度.省的以后还得慢慢调试 思路:贪心.每次都查看两端位置上的字母是否相等.若不相等就在里面查找能使他们相等且所需移动位置最少的那 个.然后交换.记录交换的距离,贪心的离最后一个由近及远找与第一个位置相等的.同理贪心从第一个位置找和最 后一个位置相等且离第一个位置近期的. . .感觉这样的方法确实能够,可是并不会证明这样的策略的正确性.. . 代码…
C. Load Balancing 题目连接: http://www.codeforces.com/contest/609/problem/C Description In the school computer room there are n servers which are responsible for processing several computing tasks. You know the number of scheduled tasks for each server:…
C. Simple Strings 题目连接: http://www.codeforces.com/contest/665/problem/C Description zscoder loves simple strings! A string t is called simple if every pair of adjacent characters are distinct. For example ab, aba, zscoder are simple whereas aa, add a…
题目大意:给你字符串s,和t,字符串s中的'?'可以用字符串t中的字符代替,要求使得最后得到的字符串s(可以将s中的字符位置两两交换,任意位置任意次数)中含有的子串t最多. 解题思路: 因为知道s中的字符位置可以交换无数次,所以只要s中含有可以组成t的字符就一定可以出现子串t.所以就是要令t中的字符数量尽量平均地分布在s中. 代码: #include<iostream> #include<string> using namespace std; ]; int main(){ str…