络谷 P2865 [USACO06NOV]路障Roadblocks】的更多相关文章

P2865 [USACO06NOV]路障Roadblocks 题目描述 Bessie has moved to a small farm and sometimes enjoys returning to visit one of her best friends. She does not want to get to her old home too quickly, because she likes the scenery along the way. She has decided t…
P2865 [USACO06NOV]路障Roadblocks 题目描述 Bessie has moved to a small farm and sometimes enjoys returning to visit one of her best friends. She does not want to get to her old home too quickly, because she likes the scenery along the way. She has decided t…
给一手链接 https://www.luogu.com.cn/problem/P2865 这道题其实就是在维护最短路的时候维护一下次短路就okay了 #include<cstdio> #include<cstring> #include<algorithm> #include<cmath> #include<queue> using namespace std; ,inf=1e9; int read(){ ,f=,c=getchar(); ; c…
http://poj.org/problem?id=3255 Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 15680   Accepted: 5510 Description Bessie has moved to a small farm and sometimes enjoys returning to visit one of her best friends. She does not want to get…
P2865 [USACO06NOV]路障Roadblocks 最短路(次短路) 直接在dijkstra中维护2个数组:d1(最短路),d2(次短路),然后跑一遍就行了. attention:数据有不同权值的重边(40ptsQAQ) #include<iostream> #include<cstdio> #include<cstring> #include<queue> #include<cctype> using namespace std; t…
·求1到n的严格次短路. [题解] dijktra魔改?允许多次入队,改了次短路的值也要入队. #include<cstdio> #include<algorithm> #define M 200010 #define N 5010 #define rg register using namespace std; int n,m,tot,last[N],dis[N],d2[N],pos[N]; struct edge{ int to,pre,dis; }e[M]; struct h…
链接:https://www.luogu.org/problemnew/show/P2865 题目描述 Bessie has moved to a small farm and sometimes enjoys returning to visit one of her best friends. She does not want to get to her old home too quickly, because she likes the scenery along the way. S…
题目链接 次短路模板题. 对每个点记录最短路和严格次短路,然后就是维护次值的方法了. 和这题一样. #include <cstdio> #include <queue> #include <cstring> using namespace std; inline int read(){ int s = 0, w = 1; char ch = getchar(); while(ch < '0' || ch > '9'){ if(ch == '-') w = -…
传送门 算法Dijkstra要求次短路 那么在不考虑重复走一条边的情况下 肯定是把最短路中的一段改成另一段 至少要换另一条边到路径里所以可以枚举所有不属于最短路的每条边(a,b) 那么dis(1,a)+(a,b)+ dis(b,n)就是一种可能的答案(记为S) 显然如果另一条不属于S的边更新S后会使S更长,就不可能为次短路了 那么只要对起点1和终点n分别跑Dijkstra就可以求出每个dis(1,a)和dis(b,n) 至于判断一条边是否在最短路上也很容易: 显然,如果dis(1,a)+(a,b…
一个次短路的问题,可以套用dijkstra求最短路的方法,用dis[0][i]表示最短路:dis[1][i]表示次短路,优先队列中存有最短路和次短路,然后每次找到一条道路对他进行判断,更新最短或次短路, 注意求次短路时不要打标记,因为有可能再次访问到该节点. 最后的答案就是dis[1][n]. 1 #include<bits/stdc++.h> 2 using namespace std; 3 #define N 200010 4 int tot,head[N],to[N],w[N],nxt[…
题意 Bessie has moved to a small farm and sometimes enjoys returning to visit one of her best friends. She does not want to get to her old home too quickly, because she likes the scenery along the way. She has decided to take the second-shortest rather…
注意:如果是这么个写法,堆数组要开成n+m的. 为什么呢?设想一下从1到2有m条长度递减的路,这岂不是要入队m次-- #include <algorithm> #include <iostream> #include <cstring> #include <cstdio> using namespace std; struct Edge{ int too, nxt, val; }edge[200005]; struct Node{ int idd, val;…
洛谷P1879 [USACO06NOV]玉米田Corn Fields \(f[i][j]\) 表示前 \(i\) 行且第 \(i\) 行状态为 \(j\) 的方案总数.\(j\) 的大小为 \(0 \to (1 >> n - 1)\) . 第 \(i\) 行,种植状态为 \(j\) 的方案总数等于所有合法的 \(f[i-1][k]\) 之和. 状态 \(j\) 满足同一行内没有相邻的两块草地(没有共同边). 状态 \(j\) 和 \(k\) 满足相邻两行的种植情况没有两块草地有共同边. \[…
洛谷 P6218 [USACO06NOV] Round Numbers S 题目描述 如果一个正整数的二进制表示中,\(0\) 的数目不小于 \(1\) 的数目,那么它就被称为「圆数」. 例如,\(9\) 的二进制表示为 \(10011001\),其中有 \(2\) 个 \(0\) 与 \(2\) 个 \(1\).因此,\(9\) 是一个「圆数」. 请你计算,区间 \([l,r]\) 中有多少个「圆数」. 输入格式 一行,两个整数 \(l,r\). 输出格式 一行,一个整数,表示区间 \([l,…
题目: POJ3255 洛谷2865 分析: 这道题第一眼看上去有点懵-- 不过既然要求次短路,那估计跟最短路有点关系,所以就拿着优先队列优化的Dijkstra乱搞,搞着搞着就通了. 开两个数组:\(dis\)存最短路,\(dis2\)存次短路 在松弛的时候同时更新两个数组,要判断三个条件 (\(u\)是当前考虑的点,\(v\)是与\(u\)有边相连的点,\(d(u,v)\)表示从\(u\)到\(v\)的边长) 1.如果\(dis[v]>dis[u]+d(u,v)\),则更新\(dis[v]\)…
P2866 [USACO06NOV]糟糕的一天Bad Hair Day 75通过 153提交 题目提供者洛谷OnlineJudge 标签USACO2006云端 难度普及/提高- 时空限制1s / 128MB 提交  讨论  题解 最新讨论更多讨论 题目标题 题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her…
P1879 [USACO06NOV]玉米田Corn Fields 题目描述 农场主\(John\)新买了一块长方形的新牧场,这块牧场被划分成\(M\)行\(N\)列\((1 ≤ M ≤ 12; 1 ≤ N ≤ 12)\),每一格都是一块正方形的土地.\(John\)打算在牧场上的某几格里种上美味的草,供他的奶牛们享用. 遗憾的是,有些土地相当贫瘠,不能用来种草.并且,奶牛们喜欢独占一块草地的感觉,于是\(John\)不会选择两块相邻的土地,也就是说,没有哪两块草地有公共边. \(John\)想知…
洛谷P1879:https://www.luogu.org/problemnew/show/P1879 思路 把题目翻译成人话 在n*m的棋盘 每个格子不是0就是1 1表示可以种 0表示不能种 相邻的格子不能同时种 求总方案数 把每行看成一个n位的2进制数 预处理出每行的状态后 进行DP即可 PS:在处理每行的初始状态时 将其取反后更好操作 代码 #include<iostream> #include<cstdio> using namespace std; #define mod…
P2867 [USACO06NOV]大广场Big Square 题目描述 Farmer John's cows have entered into a competition with Farmer Bob's cows. They have drawn lines on the field so it is a square grid with N × N points (2 ≤ N ≤ 100), and each cow of the two herds has positioned he…
P2176 [USACO14FEB]路障Roadblock 题目描述 每天早晨,FJ从家中穿过农场走到牛棚.农场由 N 块农田组成,农田通过 M 条双向道路连接,每条路有一定长度.FJ 的房子在 1 号田,牛棚在 N 号田.没有两块田被多条道路连接,以适当的路径顺序总是能在农场任意一对田间行走.当FZ从一块田走到另一块时,总是以总路长最短的道路顺序来走. FJ 的牛呢,总是不安好心,决定干扰他每天早晨的计划.它们在 M 条路的某一条上安放一叠稻草堆,使这条路的长度加倍.牛希望选择一条路干扰使得F…
P2867 [USACO06NOV]大广场Big Square 题目描述 Farmer John's cows have entered into a competition with Farmer Bob's cows. They have drawn lines on the field so it is a square grid with N × N points (2 ≤ N ≤ 100), and each cow of the two herds has positioned he…
没学状压DP的看一下 合法布阵问题  P1879 [USACO06NOV]玉米田Corn Fields 题意:给出一个n行m列的草地(n,m<=12),1表示肥沃,0表示贫瘠,现在要把一些牛放在肥沃的草地上,但是要求所有牛不能相邻,问你有多少种放法. 分析:假如我们知道每行都有x种合法放法(也就是x种状态),所以对于第i行就有x种放法,那么对于第i+1行的每种放法就有对应的x种放法. 所以定义dp[i][j]表示第i行状态为j时的方法数(j=0,j<=x;j++),有转移方程:dp[i][j]…
P1879 [USACO06NOV]玉米田Corn Fields 题目描述 Farmer John has purchased a lush new rectangular pasture composed of M by N (1 ≤ M ≤ 12; 1 ≤ N ≤ 12) square parcels. He wants to grow some yummy corn for the cows on a number of squares. Regrettably, some of the…
题目描述 Farmer John has purchased a lush new rectangular pasture composed of M by N (1 ≤ M ≤ 12; 1 ≤ N ≤ 12) square parcels. He wants to grow some yummy corn for the cows on a number of squares. Regrettably, some of the squares are infertile and can't b…
蒟蒻刷水题的日常 这个题虽然模拟也不会超时,但我不喜欢模拟,能不模拟就不模拟,容易超时. 接下来进入正题: 实际上一开始是个很无聊的过程,你拿点,我拿点....贼无聊.我们可以把这个过程去掉.只看最后一轮谁拿走的就行了. 上代码: #include<bits/stdc++.h>//懒人专用头文件 using namespace std; int main(){ int n,a,b; ios::sync_with_stdio(0);//cin的优化,大约能优化时间到原先1/2(讲给小白,神犇勿喷…
题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants to count the number of other cows that can see the top of other cows' heads. Each cow i has a specified…
Description 贝茜把家搬到了一个小农场,但她常常回到FJ的农场去拜访她的朋友.贝茜很喜欢路边的风景,不想那么快地结束她的旅途,于是她每次回农场,都会选择第二短的路径,而不象我们所习惯的那样,选择最短路. 贝茜所在的乡村有R(1<=R<=100,000)条双向道路,每条路都联结了所有的N(1<=N<=5000)个农场中的某两个.贝茜居住在农场1,她的朋友们居住在农场N(即贝茜每次旅行的目的地). 贝茜选择的第二短的路径中,可以包含任何一条在最短路中出现的道路,并且,一条路可…
题目大意:有一个$n\times m$的矩阵,$(1 \leq m \leq 12; 1 \leq n \leq 12)$,想在其中的一些格子中种草,一些格子不能种草,且两块草地不相邻.问有多少种种植方案. 题解:状压$DP$,$f_{i,j}$表示处理到了第$i$行,当前状态为$j$的方案数 卡点:无 C++ Code: #include <cstdio> using namespace std; const int mod = 100000000; int n, m, a; int p[1…
题目描述 Farmer John has purchased a lush new rectangular pasture composed of M by N (1 ≤ M ≤ 12; 1 ≤ N ≤ 12) square parcels. He wants to grow some yummy corn for the cows on a number of squares. Regrettably, some of the squares are infertile and can't b…
题目描述 每天早晨,FJ从家中穿过农场走到牛棚.农场由 N 块农田组成,农田通过 M 条双向道路连接,每条路有一定长度.FJ 的房子在 1 号田,牛棚在 N 号田.没有两块田被多条道路连接,以适当的路径顺序总是能在农场任意一对田间行走.当FZ从一块田走到另一块时,总是以总路长最短的道路顺序来走. FJ 的牛呢,总是不安好心,决定干扰他每天早晨的计划.它们在 M 条路的某一条上安放一叠稻草堆,使这条路的长度加倍.牛希望选择一条路干扰使得FJ 从家到牛棚的路长增加最多.它们请你设计并告诉它们最大增量…