Given a collection of distinct numbers, return all possible permutations.For example,[1,2,3] have the following permutations:[  [1,2,3],  [1,3,2],  [2,1,3],  [2,3,1],  [3,1,2],  [3,2,1]] 方法一: class Solution { public: vector<vector<int> > permu…

题目要求:Permutations(全排列) Given a collection of numbers, return all possible permutations. For example,[1,2,3] have the following permutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], and [3,2,1]. 分析: 参考网址:http://www.cnblogs.com/panda_lin/archive/20…

给定一个含有不同数字的集合,返回所有可能的全排列.比如,[1,2,3] 具有如下排列:[  [1,2,3],  [1,3,2],  [2,1,3],  [2,3,1],  [3,1,2],  [3,2,1]] 详见:https://leetcode.com/problems/permutations/description/ Java实现: 参考:https://blog.csdn.net/jacky_chenjp/article/details/66477538 class Solution…

Given a collection of distinct integers, return all possible permutations. Example: Input: [1,2,3] Output: [ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ] 这道题是求全排列问题,给的输入数组没有重复项,这跟之前的那道 Combinations 和类似,解法基本相同,但是不同点在于那道不同的数字顺序只算一种,是一道典型的组合题,…

Given a collection of distinct integers, return all possible permutations. Input: [1,2,3] Output: [ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ] 题意: 打印全排列 Solution1: Backtracking 形式化的表示递归过程:permutations(nums[0...n-1]) = {取出一个数字} + permutati…

Given a collection of numbers that might contain duplicates, return all possible unique permutations. Example: Input: [1,1,2] Output: [ [1,1,2], [1,2,1], [2,1,1] ] 题意: 打印全排列,注明了给定序列可含有重复元素 Solution1: Backtracking code class Solution { public List<Lis…

这道题是LeetCode里的第46道题. 题目要求: 给定一个没有重复数字的序列,返回其所有可能的全排列. 示例: 输入: [1,2,3] 输出: [ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ] 回溯法解题,函数的递归调用. 提交代码: class Solution { public: void getsol(vector<int>& nums, int a[], int k, vector<int>&…

Given a collection of numbers, return all possible permutations. For example, [1,2,3] have the following permutations: [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], and [3,2,1]. 解题思路: 本题解题方法多多,为防止重复,决定使用Set的dfs算法,JVVA实现如下: static public List<List<Int…

Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example,[1,1,2] have the following unique permutations: [ [1,1,2], [1,2,1], [2,1,1] ] 46. Permutations 的拓展,这题数组含有重复的元素.解法和46题,主要是多出处理重复的数字. 先对nu…

Given a collection of numbers that might contain duplicates, return all possible unique permutations. For example, [1,1,2] have the following unique permutations: [1,1,2], [1,2,1], and [2,1,1]. 解题思路一: 发现Java for LeetCode 046 Permutations自己想多了,代码直接拿来用…