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题目: Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 题解: 递归解法急速判断左右两边子树哪个depth最小,要注意如果有个节点只有一边孩子时,不能返回0,要返回另外一半边的depth. 递归解法:              …
Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. https://leetcode.com/problems/minimum-depth-of-binary-tree/ 题意就是给定一个二叉树,找出从根节点到叶子节点最低的高度,直…
Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. Summary: BFS or DFS with recursion. int minDepth(TreeNode *root) { if(root == NULL) ; if(r…
题目: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 题解: 递归解法:                                                            } 非递归解法,参考codegan…
这是悦乐书的第168次更新,第170篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第27题(顺位题号是111).给定二叉树,找到它的最小深度.最小深度是沿从根节点到最近的叶节点的最短路径上的节点数.叶子节点是没有子节点的节点.例如: 给定二叉树[3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 返回其最小深度= 2. 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,使用Java语言编…
[LeetCode]Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 递归和非递归,此提比较简单.广度优先遍历即可.关键之处就在于如何保持访问深度. 下面是4种代码: im…
Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 比较左子树和右子树的深度,取小的那个返回上来,并+1. 需要注意的是如果没有左子树或右子树.那么无条件取存在的那一边子树深…
LeetCode:Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 算法1:dfs递归的求解 class Solution { public: int minDepth(T…
[Leetcode] Maximum and Minimum Depth of Binary Tree 二叉树的最小最大深度 (最小有3种解法) 描述 解析 递归深度优先搜索 当求最大深度时,我们只要在左右子树中取较大的就行了. 然而最小深度时,如果左右子树中有一个为空会返回0,这时我们是不能算做有效深度的. 所以分成了三种情况,左子树为空,右子树为空,左右子树都不为空.当然,如果左右子树都为空的话,就会返回1. 广度优先搜索(类似层序遍历的思想) 递归解法本质是深度优先搜索,但因为我们是求最小…
Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. SOLUTION 1: 递归 这种递归解法更简单.因为在本层递归中不需要考虑左右子树是否为NULL的情况.因为我们直接把…