POJ_3304_Segments_线段判断是否相交 Description Given n segments in the two dimensional space, write a program, which determines if there exists a line such that after projecting these segments on it, all projected segments have at least one point in common.…

// 判断线段和直线相交 POJ 3304 // 思路: // 如果存在一条直线和所有线段相交,那么平移该直线一定可以经过线段上任意两个点,并且和所有线段相交. #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #include <map> #include <set> #include <queue> #includ…

Intersection Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 16322   Accepted: 4213 Description You are to write a program that has to decide whether a given line segment intersects a given rectangle. An example: line: start point: (4,9)…

题目链接 Intersection Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 12040   Accepted: 3125 Description You are to write a program that has to decide whether a given line segment intersects a given rectangle. An example: line: start point:…

题目链接 题意 : 如果两个线段相交就属于同一集合,查询某条线段所属集合有多少线段,输出. 思路 : 先判断与其他线段是否相交,然后合并. #include <cstdio> #include <cstring> #include <iostream> #include <cmath> #define eps 1e-8 #define zero(x) (((x) > 0 ? (x) : (-x)) < eps) using namespace s…

题目大意:给一个凸多边形(点不是按顺序给的),然后计算给出的线段在这个凸多边形里面的长度,如果在边界不计算. 分析:WA2..WA3...WA4..WA11...WA的无话可说,总之细节一定考虑清楚,重合的时候一定是0 代码如下: ========================================================================================================= #include<stdio.h> #include&…

Segments Time Limit: 1000MS   Memory Limit: 65536K       Description Given n segments in the two dimensional space, write a program, which determines if there exists a line such that after projecting these segments on it, all projected segments have…

链接: http://poj.org/problem?id=1039 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=22013#problem/B Pipe Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 8350   Accepted: 2501 Description The GX Light Pipeline Company started to prep…

题目链接:https://vjudge.net/problem/POJ-3449 题意:给出若干几何体,判断每个几何体与其它几何体的相交情况,并依次输出. 思路: 首先要知道的是根据正方形对角线的两个点怎么求其它两个点,比如已知(x0,y0),(x2,y2),那么: x1+x3=x0+x2, x1-x3=y2-y0, y1+y3=y0+y2, y1-y3=x0-x2 之后就暴力枚举了,枚举所有几何体的所有边,用线段相交判断几何体相交.这题的输入输出很恶心. AC代码: #include<cstd…

题目链接:POJ 3805 Problem Description Numbers of black and white points are placed on a plane. Let's imagine that a straight line of infinite length is drawn on the plane. When the line does not meet any of the points, the line divides these points into t…