[LeetCode] Add Strings 字符串相加】的更多相关文章

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
给定两个字符串形式的非负整数 num1 和num2 ,计算它们的和.注意:    num1 和num2 的长度都小于 5100.    num1 和num2 都只包含数字 0-9.    num1 和num2 都不包含任何前导零.    你不能使用任何內建 BigInteger 库, 也不能直接将输入的字符串转换为整数形式.详见:https://leetcode.com/problems/add-strings/description/C++: class Solution { public:…
LeetCode--Add Strings Question Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 doe…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因可能是这样可以计算超大数相乘,可以不受int或long的数值范围的约束,那么我们该如何来计算…
原题链接在这里:https://leetcode.com/problems/add-strings/ 题目: Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9.…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 二进制数想加,并且保存在string中,要注意的是如何将string和int之间互相转换,并且每位相加时,会有进位的可能,会影响之后相加的结果.而且两个输入string的长度也可能会不同.这时我们需要新建一个string,它的长度是两…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题意:计算字符串对应数字的乘积.参考JustDoIT的博客. 思路:先用一维向量存放计算的中间值,中间值存放对应位置乘积的和(暂不考虑进位的情况):然后针对进位的情况,进行计算:注意要跳…
给定两个字符串形式的非负整数 num1 和num2 ,计算它们的和. 注意: num1 和num2 的长度都小于 5100. num1 和num2 都只包含数字 0-9. num1 和num2 都不包含任何前导零. 你不能使用任何內建 BigInteger 库, 也不能直接将输入的字符串转换为整数形式. java 基础版 class Solution { public String addStrings(String num1, String num2) { String res = "&quo…