B. Equations of Mathematical Magic】的更多相关文章

Description Colossal! — exclaimed Hawk-nose. — A programmer! That's exactly what we are looking for. Arkadi and Boris Strugatsky. Monday starts on Saturday Reading the book "Equations of Mathematical Magic" Roman Oira-Oira and Cristobal Junta fo…
思路 打表找规律,发现结果是,2的(a二进制位为1总数)次方 代码 #include<bits/stdc++.h> using namespace std; #define ll long long int main(){ ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); ll t,a; //freopen("in.txt","r",stdin); cin>>t; while(t--)…
题目要求解$a-(a\oplus x)-x=0$的解$x$的个数 移项得$a-x=a\oplus x$ $a$的二进制形式,应该是一个$01$串,异或的过程是不能影响到两个不同的位的,所以我们按位考虑 如果这一位是$0$,那么$x$的这一位也应为$0$,使得异或后答案不会更大 如果这一位是$1$,那么$x$的这一位可以为$0$或$1$,对应到减法中就是没减和减掉 所以答案就是$2^{count~~1~~in~~a}$ #include<iostream> #include<cstdio&…
https://blog.csdn.net/zfq17796515982/article/details/83051495 题意:解方程:a-(a^x)-x=0 给出a的值,要求计算解(非负)的个数 题解:需要^和 - 起到相同的效果. 1^1=0 1-1=0 1^0=1 1-0=1 0^0=0 0-0=0, 0^1=1 0-1=-1 a的二进制位上为1时,x的二进制位上为1或者0,异或和减的效果相同. a的二进制有几个1,就表示解的个数有2的几次方个 #include<bits/stdc++.…
\(\\\) \(Description\) \(T\) 组询问,每次给出一个 \(a\),求方程 \[ a-(a\oplus x)-x=0 \] 的方案数. \(T\le 10^3,a\le 2^{30}\) \(\\\) \(Solution\) 我菜又被巨佬 \(Diss\) 了...... 考场 \(NC\) 问了爷们半懂不懂的就过了...... 移项,得 \[ a=(a\oplus x)+x \] 然后注意到满足这个性质的 \(x\) ,在二进制表示下一定是 \(a\) 的子集. 因为…
题目链接 A. Make a triangle! 题意 让某段最少增加多少使得构成三角形 思路 让较小两段往最长段去凑 代码 #include <bits/stdc++.h> #define DBG(x) cerr << #x << " = " << x << endl; using namespace std; int a[5]; int main(){ scanf("%d%d%d",&a[1],…
目录 Codeforces 1064 A.Make a triangle! B.Equations of Mathematical Magic C.Oh Those Palindromes D.Labyrinth(BFS) E.Dwarves,Hats and Extrasensory Abilities(交互 二分) F.Candies for Children D.Labyrinth E.Dwarves,Hats and Extrasensory Abilities Codeforces 1…
比赛链接:传送门 A. Make a triangle!(简单思维) 题目大意: 给你三条边,问你最多加多少长度能使这三条边能构成三角形. 思路: 最大边小于答案加另外两条边的和. #include <bits/stdc++.h> using namespace std; int main() { int a, b, c; cin >> a >> b >> c; int _max = max(a, b); _max = max(_max, c); int s…
前言:依旧菜,\(A\)了\(4\)题,不过这次上蓝了挺开心的. A. Make a triangle! Description 给出\(3\)根木棍,希望用它们拼成三角形,可以将其中的某些木棍增长,求至少需要增长多少才能拼成一个三角形. Solution 水题,答案就是最长的木棍长度减去剩下两根木棍的长度和再\(+1\),如果为负则输出\(0\)(即本来就能拼成三角形). #include<cstdio> using namespace std; inline int re() { int…
A. Make a triangle! 暴力... 就是给你三个数,你每次可以选一个加1,问最少加多少次能构成三角形 #include <bits/stdc++.h> #define ll long long #define inf 0x3f3f3f3f #define il inline #define in1(a) read(a) #define in2(a,b) in1(a),in1(b) #define in3(a,b,c) in2(a,b),in1(c) #define in4(a,…
比赛传送门 A. Make a triangle! 题目大意:给你三根木棒,选出其中一根木棒增加它的长度,使构成三角形,问增加的长度最小是多少. 思路:签到题,根据样例/三角形性质不难发现,答案就是最长边减剩下两边之和加一. #include<cstdio> #include<algorithm> using namespace std; ]; int main() { ;i<=;i++) scanf("%d",&seq[i]); sort(seq…
A Make a triangle! 题意:给定三根线段,问最少要延长多少才能拼成一个三角形. 数学题. B Equations of Mathematical Magic 题意:求$a - (a \oplus b)-x=0 $的非负整数解的个数. 打表发现是\(a\)在二进制下\(1\)的数量. C Oh Those Palindromes 题意:求字符串\(S\)重新排列后的回文子串的最大数量. 猜想一样的放在一起会最多,然后就对了. D Labyrinth 题意:给定一个迷宫,有一些障碍,…
Figures To insert a figure in a LaTeX document, you write lines like this: \begin{figure} \centering \includegraphics[width=3.0in]{imagefile1} \caption{Caption for figure} \label{fig:sample_figure} \end{figure} The whole block is enclosed between \be…
A---Make a triangle! http://codeforces.com/contest/1064/problem/A 题意: 给定三个整数表示三角形的边.每次给边长可以加一,问至少要加多少才能使这三个边成为一个三角形. 思路: 找到最大的边,然后最大边 + 1减剩下两条边就行了.负数的话就是0. #include<iostream> #include<cmath> #include<algorithm> #include<stdio.h> #i…
                                              6073 Math MagicYesterday, my teacher taught us about math: +, -, *, /, GCD, LCM... As you know, LCM (Leastcommon multiple) of two positive numbers can be solved easily because of a ∗ b = GCD(a, b) ∗ LCM(a…
Thanks a lot for helping Harry Potter in finding the Sorcerer's Stone of Immortality in October. Did we not tell you that it was just an online game ? uhhh! now here is the real onsite task for Harry. You are given a magrid S ( a magic grid ) having…
Math Magic Time Limit:3000MS     Memory Limit:32768KB     64bit IO Format:%lld & %llu Submit Status Description Yesterday, my teacher taught us about math: +, -, *, /, GCD, LCM... As you know, LCM (Least common multiple) of two positive numbers can b…
Math Magic Time Limit: 3 Seconds       Memory Limit: 32768 KB Yesterday, my teacher taught us about math: +, -, *, /, GCD, LCM... As you know, LCM (Least common multiple) of two positive numbers can be solved easily because of a * b = GCD (a, b) * LC…
Magic Grid Time Limit:336MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Description Thanks a lot for helping Harry Potter in finding the Sorcerer's Stone of Immortality in October. Did we not tell you that it was just an online game ? uhhh!…
Special equations Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4569 Description Let f(x) = a nx n +...+ a 1x +a 0, in which a i (0 <= i <= n) are all known integers. We call f(x) 0 (mod…
D. Magic Numbers time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Consider the decimal presentation of an integer. Let's call a number d-magic if digit d appears in decimal presentation of…
A magic index in an array A[0...n-1] is defined to be an index such that A[i] = i. Given a sorted array of distinct integers, write a method to find a magic index, if one exists, in array A. FOLLOW UP What if the values are not distinct? public int g…
介绍 在Python中,所有以"__"双下划线包起来的方法,都统称为"Magic Method",例如类的初始化方法 __init__ ,Python中所有的魔术方法均在官方文档中有相应描述,但是对于官方的描述比较混乱而且组织比较松散.很难找到有一个例子. 构造和初始化 每个Pythoner都知道一个最基本的魔术方法, __init__ .通过此方法我们可以定义一个对象的初始操作.然而,当调用 x = SomeClass() 的时候, __init__ 并不是第一个…
F. Heroes of Making Magic III time limit per test:3 seconds memory limit per test:256 megabytes input:standard input output:standard output I’m strolling on sunshine, yeah-ah! And doesn’t it feel good! Well, it certainly feels good for our Heroes of…
Magic boy Bi Luo with his excited tree Problem Description Bi Luo is a magic boy, he also has a migic tree, the tree has N nodes , in each node , there is a treasure, it's value is V[i], and for each edge, there is a cost C[i], which means every time…
代码: int i = *reinterpret_cast<int*>(&(d += 6755399441055744.0)); 知识点: 1.reinterpret_cast<type_id> expression:type_id 必须是一个指针.引用.算术类型.函数指针或者成员指针.它可以把一个指针转换成一个整数,也可以把一个整数转换成一个指针(先把一个指针转换成一个整数,再把该整数转换成原类型的指针,还可以得到原先的指针值). 只是将bit表示进行了重新解读,不改变位…
Mathematical Induction Mathematical Induction is a special way of proving things. It has only 2 steps: Step 1. Show it is true for the first one Step 2. Show that if any one is true then the next one is true Then all are true Have you heard of the "D…
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Magic xpa 2.5發佈 Magic xpa 2.5 Release Notes Magic xpa 2.5 Release NotesNew Features, Feature Enhancements and Behavior ChangesCall with Destination – Backward Compatibility EnhancementsIn Online, the following scenarios are now possible: Calling a p…
原文地址:https://dzone.com/articles/how-springboot-autoconfiguration-magic-works In my previous post "Why Spring Boot?", we looked at how to create a Spring Boot application, but you may or may not understand what is going on behind the scenes. You…