Given 2*n + 1 numbers, every numbers occurs twice except one, find it. Have you met this question in a real interview? Yes Example Given [1,2,2,1,3,4,3], return 4 Challenge One-pass, constant extra space. LeetCode上的原题,请参见我之前的博客Single Number. class So…

Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 本来是一道非常简单的题,但是由于加上了时间复杂度必须是O(n),并且空间复杂度为O(1)…

Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Example 1: Input: [2,2,1] Output:…

C++ (1)异或操作 3^3=0 (2)for (auto &i : Obejuct) {} class Solution { public: /** * @param A: Array of integers. * return: The single number. */ int singleNumber(vector<int> &A) { // write your code here ; for (auto &i : A) { ret ^= i; } retu…

［抄题］: Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? [暴力解法]: 时间分析:n 空间分析:新建n的数组来存储 ［奇葩输出条件］…

Given 2*n + 2 numbers, every numbers occurs twice except two, find them. Example Given [1,2,2,3,4,4,5,3] return 1 and 5 Challenge O(n) time, O(1) extra space. 利用bitwise XOR的特点,n个数(0或1),如果1的个数为奇数,则n个数bitwise XOR结果为1,否则为0 先将所有的数异或,得到的将是x和y以后之后的值n. 找到这个…

一篇解析比较详细的文章:http://www.acmerblog.com/leetcode-single-number-ii-5394.html C++ 解法(1) 求出每个比特位的数目,然后%3,如果这个比特位只出现1次,那么这比特位就会余1,否则就会整除. 把每个余下的比特位求出来,就知道是哪个数只出现1次了. class Solution { public: /** * @param A : An integer array * @return : An integer */ int si…

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums = [0, 1, 3] return 2. Note: Your algorithm should run in linear runtime complexity. Could you implement it u…

转载:http://www.cnblogs.com/grandyang/p/4756677.html Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in li…

136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solution { public: int singleNumber(vector<int>& nums) { if(nums.empty()) ; ; ;i < nums.size();i++) res ^= nums[i]; return res; } }; 137. Single N…