Vanya and Brackets Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit Status Practice CodeForces 552E Description Vanya is doing his maths homework. He has an expression of form , where x1, x2, ..., xn are digits fro…

题目链接 Vanya and Brackets 题目大意是给出一个只由1-9的数.乘号和加号组成的表达式,若要在这个表达式中加上一对括号,求加上括号的表达式的最大值. 我们发现,左括号的位置肯定是最左端或者某个乘号右边,右括号的位置肯定是最右段或者某个乘号左边. 而乘号最多只有15个,那么暴力枚举就可以了. #include <bits/stdc++.h> using namespace std; #define rep(i, a, b) for (int i(a); i <= (b);…

Vanya and Brackets Time Limit: 1000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u Description Vanya is doing his maths homework. He has an expression of form , where x1, x2, ..., xn are digits from 1 to 9, and sign represents either a p…

题目链接:https://vjudge.net/contest/224393#problem/E Vanya is doing his maths homework. He has an expression of form , where x1, x2, ..., xn are digits from 1 to 9, and sign  represents either a plus '+' or the multiplication sign '*'. Vanya needs to add…

time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output Vanya is doing his maths homework. He has an expression of form , where x1, x2, -, xn are digits from 1 to 9, and sign represents either a plus '…

给一个只有加号和乘号的表达式,要求添加一对括号使得最后结果最大.表达式长度5000,乘号最多12个,表达式中数字只有1位. 左括号一定在乘号右边,右括号一定在乘号左边,因为如果不是这样的话,一定可以调整括号的位置使表达式的值增大. 于是只要枚举括号的位置然后计算表达式即可.[以上来源,懒得自己写了] 做到这道题的时候突然发现自己忘记表达式求值怎么求了 这个表达式只有括号,加号和乘号 大概用到了后缀表达式的思想,但不会去真正化成后缀表达式 建两个栈,一个char类型,一个int类型 从左到右扫描,…

题目链接 讲道理距离上一次写这种求值的题已经不知道多久了. 括号肯定是左括号在乘号的右边, 右括号在左边. 否则没有意义. 题目说乘号只有15个, 所以我们枚举就好了. #include <iostream> #include <vector> #include <cstdio> #include <cstring> #include <algorithm> #include <complex> #include <cmath&…

http://codeforces.com/contest/552/problem/E E. Vanya and Brackets time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Vanya is doing his maths homework. He has an expression of form , where x1,…

A. Vanya and Table   Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows are numbered by integers from 1 to 100 from bottom to top, the columns are numbered from 1 to 100 from left to right. In this table, Vanya chose n re…

按下Ctrl + E("编辑")或退出编辑.Brackets将搜索项目下所有CSS文件 Ctrl/Cmd + Alt + P 打开即时预览功能 alt + command + O目录的结构会显示在编辑器的边栏上,点开对应的目录 扩展 Beautify Code Folding Emmet  http://docs.emmet.io/ 直接下载https://github.com/drewhjava/brackets-beautify后,解压放到Brackets 插件目录下(插件目录He…