题目 Reward Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble about how to distribute the rewards.  The workers will compare their rewards ,and some one may…

HDU.2647 Reward(拓扑排序 TopSort) 题意分析 裸的拓扑排序 详解请移步 算法学习 拓扑排序(TopSort) 这道题有一点变化是要求计算最后的金钱数.最少金钱值是888,最少的差额是1,如1号的人比2号钱要多,2号至少是1号人的钱数+1.根据拓扑排序的思想,我们只需要类比二叉树的层序遍历,每次取出入度为0的节点做处理,累加金钱数量,然后再取出入度为0的节点处理.直到取出所有的点或者判断成环即可. 代码总览 #include <iostream> #include <…

hdu 2647 Reward Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble…

逃生 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 6686 Accepted Submission(s): 1958 Problem Description 糟糕的事情发生啦,现在大家都忙着逃命.但是逃命的通道很窄,大家只能排成一行. 现在有n个人,从1标号到n.同时有一些奇怪的约束条件,每个都形如:a必须在b之前. 同时,社会是不平等的…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2647 题意是给你n点m条有向边,叶子点(出度为0)上的值为888,父亲点为888+1,依次计算... 让你求最小的值,但是中间出现有向环就不行了,输出-1. 拓扑排序队列实现,因为叶子是最小的,所以把边反向就可以求了. //拓扑队列实现 //就是先把入度为0的先入队,然后每次出队的时候把相邻的点的入度减1,要是入度为0则再入队,不断循环直到队列为空 //时间复杂度为O(N + E) //这题就是把边…

题意不说了,说下思路. 给出的关系是a要求的工资要比b的工资多,因为尽可能的让老板少付钱,那么a的工资就是b的工资+1.能够确定关系为a>b,依据拓扑排序建边的原则是把"小于"关系看成有向边.那么我们能够建边v->u. #include <stdio.h> #include <string.h> #include <string> #include <iostream> #include <algorithm> #…

逃生 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description 糟糕的事情发生啦,现在大家都忙着逃命.但是逃命的通道很窄,大家只能排成一行. 现在有n个人,从1标号到n.同时有一些奇怪的约束条件,每个都形如:a必须在b之前.同时,社会是不平等的,这些人有的穷有的富.1号最富,2号第二富,以此类推.有钱人就贿赂负责人,所以他们有一些好处. 负责人现在…

题目链接:https://vjudge.net/contest/218427#problem/C 题目大意: 老板要给很多员工发奖金, 但是部分员工有个虚伪心态, 认为自己的奖金必须比某些人高才心理平衡: 但是老板很人道, 想满足所有人的要求, 并且很吝啬,想画的钱最少 输入若干个关系 a b a c c b 意味着a 的工资必须比b的工资高 同时a 的工资比c高: c的工资比b高 当出现环的时候输出-1 #include<iostream> #include<cstring> #…

Problem Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble about how to distribute the rewards. The workers will compare their rewards ,and some…

逃生 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2682    Accepted Submission(s): 763 Problem Description 糟糕的事情发生啦,现在大家都忙着逃命.但是逃命的通道很窄,大家只能排成一行. 现在有n个人,从1标号到n.同时有一些奇怪的约束条件,每个都形如:a必须在b之前. 同时,社会…