Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the…

给定一个表示分数的非负整数数组. 玩家1从数组任意一端拿取一个分数,随后玩家2继续从剩余数组任意一端拿取分数,然后玩家1拿,…….每次一个玩家只能拿取一个分数,分数被拿取之后不再可取.直到没有剩余分数可取时游戏结束.最终获得分数总和最多的玩家获胜.给定一个表示分数的数组,预测玩家1是否会成为赢家.你可以假设每个玩家的玩法都会使他的分数最大化.示例 1:输入: [1, 5, 2]输出: False解释: 一开始,玩家1可以从1和2中进行选择.如果他选择2(或者1),那么玩家2可以从1(或者2)和5…

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the…

[LeetCode]486. Predict the Winner 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/predict-the-winner/description/ 题目描述: Given an array of scores that are non-negative integers…

lc 486 Predict the Winner 486 Predict the Winner Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a…

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the…

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the…

题目如下: Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available f…

题目链接:https://leetcode.com/problems/predict-the-winner/ 1.暴力递归 当前数组左边界:i,右边界:j: 对于先发者来说,他能取到的最大值是:max(arr[i] + second(arr, i + 1, j), arr[j] + second(arr, i, j - 1)); (arr[i] + 作为后发者,在 i+1 到 j 上取得的值),(arr[j] + 作为后发者,在 i 到 j-1 上取得的值) 中大的一个. 对于后发者来说,他是被…

原题 思路: 解法一: 转换比较拿取分数多少的思路,改为考虑 player拿的分数为正,把Player2拿的视为负,加上所有分数,如果最后结果大于0则Player1赢. 思考得出递归表达式: max(nums[beg] - player2(beg + 1, end), nums[end] - player2(beg, end + 1)) 此解法效率很差 104ms,beats 5.32% class Solution { public: bool PredictTheWinner(vector<…

Leetcode之动态规划(DP)专题-486. 预测赢家(Predict the Winner) 给定一个表示分数的非负整数数组. 玩家1从数组任意一端拿取一个分数,随后玩家2继续从剩余数组任意一端拿取分数,然后玩家1拿,…….每次一个玩家只能拿取一个分数,分数被拿取之后不再可取.直到没有剩余分数可取时游戏结束.最终获得分数总和最多的玩家获胜. 给定一个表示分数的数组,预测玩家1是否会成为赢家.你可以假设每个玩家的玩法都会使他的分数最大化. 示例 1: 输入: [1, 5, 2] 输出: Fa…

486. 预测赢家 给定一个表示分数的非负整数数组. 玩家1从数组任意一端拿取一个分数,随后玩家2继续从剩余数组任意一端拿取分数,然后玩家1拿,--.每次一个玩家只能拿取一个分数,分数被拿取之后不再可取.直到没有剩余分数可取时游戏结束.最终获得分数总和最多的玩家获胜. 给定一个表示分数的数组,预测玩家1是否会成为赢家.你可以假设每个玩家的玩法都会使他的分数最大化. 示例 1: 输入: [1, 5, 2] 输出: False 解释: 一开始,玩家1可以从1和2中进行选择. 如果他选择2(或者1),…

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the…

题目描述 给定一个表示分数的非负整数数组. 玩家1从数组任意一端拿取一个分数,随后玩家2继续从剩余数组任意一端拿取分数,然后玩家1拿,--.每次一个玩家只能拿取一个分数,分数被拿取之后不再可取.直到没有剩余分数可取时游戏结束.最终获得分数总和最多的玩家获胜. 给定一个表示分数的数组,预测玩家1是否会成为赢家.你可以假设每个玩家的玩法都会使他的分数最大化. 示例 1: 输入: [1, 5, 2] 输出: False 解释: 一开始,玩家1可以从1和2中进行选择. 如果他选择2(或者1),那么玩家2…

题目描述: 给定一个表示分数的非负整数数组. 玩家1从数组任意一端拿取一个分数,随后玩家2继续从剩余数组任意一端拿取分数,然后玩家1拿,…….每次一个玩家只能拿取一个分数,分数被拿取之后不再可取.直到没有剩余分数可取时游戏结束.最终获得分数总和最多的玩家获胜. 给定一个表示分数的数组,预测玩家1是否会成为赢家.你可以假设每个玩家的玩法都会使他的分数最大化. 示例1: 输入: [1, 5, 2] 输出: False 解释: 一开始,玩家1可以从1和2中进行选择. 如果他选择2(或者1),那么玩家2…

题目链接 https://leetcode-cn.com/problems/predict-the-winner/ 题目说明 题解 主要方法:递推:动态规划:前缀和 解释说明: 求前缀和 pre_nums ,pre_nums[0] = 0, pre_nums[1+i] = sum(nums[0--i]) 动态规划.递推: 数据表示:设立二维数组dp,dp[i][j]表示区间 [i,j] 内先取者能取得的最大值.dpnums 初始状态:遍历 nums 数组求得长度为 1 的区间 [i,i] 内的最…

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the…

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the…

2018-04-22 19:19:47 问题描述: Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number wil…

原题链接在这里:https://leetcode.com/problems/predict-the-winner/description/ 题目: Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Ea…

https://leetcode.com/problems/predict-the-winner/ 题目描述:给定一个非负的积分数组,玩家1可以从数组两端任取一个积分,接着玩家2执行同样的操作,直至积分被取尽,总分大的获胜.两人都以最优决策进行游戏.对每个数组输出玩家1是否能获胜. 解法1: 使用递归,两者依次取数. class Solution{ , nums.size()-, , , ); } bool dfs(vector<int>& nums, int st, int en,…

思路: 博弈. 实现: class Solution { public: bool PredictTheWinner(vector<int>& nums) { ][]; int n = nums.size(); ; i < n; i++) dp[i][i] = nums[i]; ; i >= ; i--) { ; j < n; j++) { dp[i][j] = max(nums[i] - dp[i + ][j], nums[j] - dp[i][j - ]); }…

我写的Python代码: class Solution(object): def getNumberGame(self, n, nums): m = len(nums) dp = [[0] * m for j in xrange(m)] for i in xrange(m): dp[i][i] = nums[i] for i in reversed(xrange(0, n)): for j in xrange(i + 1, m): sum = self.getSum(i, j, nums) dp…

Hello everyone, I am a Chinese noob programmer. I have practiced questions on leetcode.com for 2 years. During this time, I studied a lot from many Great Gods' articles. After worship, I always wanted to write an article as they did, and now I take t…

Contest 91 (2018年10月24日,周三) 链接:https://leetcode.com/contest/weekly-contest-91/ 模拟比赛情况记录:第一题柠檬摊的那题6分钟AC,然后是第二题树的距离K的结点那题比较久,大概写了30分钟,第三题翻转矩阵那题第一次提交错误了,列的优化方法思路错了,WA.后来比赛时间到了才改过来.最后一题最短子数组的和比K大的这题不会做. [860]Lemonade Change   (第一题) 一个柠檬摊,有一队人排队要买柠檬,一个5刀,…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

Given a string s, find the longest palindromic subsequence's length in s. You may assume that the maximum length of s is 1000. Example 1:Input: "bbbab" Output: 4 One possible longest palindromic subsequence is "bbbb". Example 2:Input:…

问题 有偶数堆石头(数组长度为偶数),每堆石头有一些石头(数组元素为正),石头的总数是奇数.Alex和Lee两个人轮流取石头堆,每次可以从头部或尾部取,Alex先取. 给定这样一个数组,两人都以最优策略去玩这个游戏,如果Alex一定会获胜则返回True,否则返回False 思路 做法1:因为有偶数堆,所以先玩游戏的Alex可以做到:一直取第偶数堆,或者一直取第奇数堆.石头总数是奇数,那么第偶数堆的石头总数和第奇数堆的石头总数,一定有一方大于另一方.所以Alex可以计算出哪方大来取.假设第奇数堆的…

357. Count Numbers with Unique Digits 解题思路: 用arr[i]存放长度为i时,各位互不相同的数字的个数,所以arr[1]=10,arr[2]=9*9.(第一位要为1,第二位与第一位要不同) arr[3] = arr[2]*8,所以arr[i]=arr[i-1]*(10 - (k-1)).之后求和就可以了. int countNumbersWithUniqueDigits(int n) { if (!n) return 1; if (n == 1) retu…